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| Q. |
A suspension shows zero-order kinetic with a rate constant 2mg/ml.month. The dose of suspension is 20mg/ml. The biological half life of the above dosage form is |
| A. | 5 months |
| B. | 1 month |
| C. | 3 months |
| D. | 2 months |
| Answer» A. 5 months | |
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Biopharmaceutics and PharmacokineticsDiscussion
Shana C
1 year ago
Explanation please
0
sabina khan
1 year ago
T half for zero order kinetics is
T1/2 = [A]° / 2 k
Where : K is rate constant &
[A]° is initial concentration of reactants ( unit is mol /liter or M)
so T half = 20 / 2×2 =5
T1/2 = [A]° / 2 k
Where : K is rate constant &
[A]° is initial concentration of reactants ( unit is mol /liter or M)
so T half = 20 / 2×2 =5
0
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