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| Q. |
The expression for K0 as given by Jacky is |
| A. | k0 = 1 – sin φ |
| B. | k0 = sin φ |
| C. | k0 = 1 – cos φ |
| D. | k0 = 1 + sin φ |
| Answer» A. k0 = 1 – sin φ | |
| Explanation: k0 can be calculated by using the following equation as computed by jacky in 1944: | |
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