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Q. |
A point is 20 units away from the vertical plane and 12 units away from profile plane and 9 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the side view and top view of point is |
A. | 29 units |
B. | 21 units |
C. | 35.8 units |
D. | 17.9 units |
Answer» C. 35.8 units | |
Explanation: since here distance from side view and top view is asked for that we need the distance between the front view and side view (12+9); front view and top view (9+20)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √(212+292 ) = 35.80 units. |
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