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| Q. |
A point is 7 units away from the vertical plane and 5 units away from profile plane and 7 units away from horizontal plane in 3rd quadrant then the projections are drawn on paper the distance between the front view and side view of point is |
| A. | 10 |
| B. | 5 |
| C. | 9 |
| D. | 12 |
| Answer» D. 12 | |
| Explanation: since the point is 5 units away from the profile plane the distance from the point to a reference line will be 5 units. and then the point is at distance of 7 units from the profile plane the distance from reference line and point will be 7 units, sum is 12. | |
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