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| Q. | A point is 5 units away from the vertical plane and 4 units away from profile plane and 3 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the front view and top view of point is | 
| A. | 7 units | 
| B. | 8 units | 
| C. | 9 units | 
| D. | 5 units | 
| Answer» B. 8 units | |
| Explanation: since the point is 3 units away from the horizontal plane the distance from the point to xy reference line will be 3 units. and then the point is at a distance of 5 units from the vertical plane the distance from reference line and point will be 5, sum is 8. | |
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