McqMate
| Q. |
y1=4sin(ωt+kx), y2=-4cos(ωt+kx), the phase difference is |
| A. | π/2 |
| B. | 3π/2 |
| C. | π |
| D. | zero |
| Answer» B. 3π/2 | |
| Explanation: y1=4sin(ωt+kx) y2=-4cos(ωt+kx) | |
View all MCQs in
Engineering PhysicsNo comments yet