Q.

y1=4sin(ωt+kx), y2=-4cos(ωt+kx), the phase difference is                      

A. π/2
B. 3π/2
C. π
D. zero
Answer» B. 3π/2
Explanation: y1=4sin(ωt+kx) y2=-4cos(ωt+kx)
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