Even-odd method of inside test counts ----- to decide the position of a point.

Related MCQs

• In winding number method , constructed horizontal line between point Q and point P intersects two edges of the polygon with winding no. +1 and -1. Tell whether point Q is inside or outside and what is the net winding ? Note : Q is the point to be tested for inside test.P is point outside the polygon.
• In winding number method , constructed horizontal line between point Q and point P intersects edge of the polygon with winding no. +1 . Tell whether point Q is inside or outside and what is the net winding ? Note : Q is the point to be tested for inside test. P is point outside the polygon.
• In an inside test if number of intersections are ---------------- then point is inside of the polygon. Note : intersection point is not a vertex.
• In Sutherland – Hodgman algorithm for polygon clipping , assume P (present point ) lies inside the window and S ( Previous point) lies inside the window. Then while processing through that window boundary we should
• In an inside test if number of intersections is odd then point is ---------------- of the polygon. Note : intersection point is not a vertex
• In an inside test if intersections point is a vertex and edges meeting at that vertex lies on same side of constructed horizontal line then the number of intersections are considered as ----------. Note : intersection point is a vertex
• In an inside test if intersections point is a vertex and edges meeting at that vertex lies on ------------- side of constructed horizontal line then the number of intersections are considered as even number . Note : intersection point is a vertex
• An -------------test is used to check whether a point is inside or outside of the polygon.
• In Sutherland – Hodgman algorithm for polygon clipping , assume P (present point ) lies inside the window and S ( Previous point) lies outside the window. Then while processing through that window boundary we should
• In Sutherland – Hodgman algorithm for polygon clipping , assume P (present point ) lies outside the window and S ( Previous point) lies inside the window. Then while processing through that window boundary we should