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| Q. |
In Bresenham's algorithm, while generating a circle , it is easy to generate? |
| A. | one octant first and other by successive reflection |
| B. | one octant first and other by successive rotation |
| C. | one octant first and other by successive translation |
| D. | all octants |
| Answer» A. one octant first and other by successive reflection | |
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