McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Computer Science Engineering (CSE) .
| 251. |
If a RAM chip has n address input lines then it can access memory locations upto |
| A. | 2(n-1) |
| B. | 2(n+1) |
| C. | 2n |
| D. | 22n |
| Answer» C. 2n | |
| Explanation: ram is a volatile memory, therefore it stores data as long as power is on. ram is also known as rwm (i.e. read write memory). if a ram chip has n address input lines then it can access memory locations upto 2n. | |
| 252. |
The n-bit address is placed in the |
| A. | mbr |
| B. | mar |
| C. | ram |
| D. | rom |
| Answer» B. mar | |
| Explanation: the n-bit address is placed in the memory address register (mar) to select one of 2n memory locations. it stores the address of the instruction which is to be executed next. | |
| 253. |
Which of the following control signals are selected for read and write operations in a RAM? |
| A. | data buffer |
| B. | chip select |
| C. | read and write |
| D. | memory |
| Answer» C. read and write | |
| Explanation: read and write are control signals that are used to enable memory for read and write operations respectively. | |
| 254. |
Computers invariably use RAM for |
| A. | high complexity |
| B. | high resolution |
| C. | high speed main memory |
| D. | high flexibility |
| Answer» C. high speed main memory | |
| Explanation: ram is a volatile memory, therefore it stores data as long as power is on. ram is also known | |
| 255. |
How many types of RAMs are? |
| A. | 2 |
| B. | 3 |
| C. | 4 |
| D. | 5 |
| Answer» A. 2 | |
| Explanation: there are two types of ram and these are static and dynamic. static ram(sram) is faster than dynamic ram(dram) as the access time for dram is more compared to that of sram. | |
| 256. |
Static RAM employs |
| A. | bjt or mosfet |
| B. | fet or jfet |
| C. | capacitor or bjt |
| D. | bjt or mos |
| Answer» D. bjt or mos | |
| Explanation: static ram employs bipolar or mos flip-flops because both the semiconductor has storing capacity. thus, it’s access time is less and it is faster in operation. | |
| 257. |
Dynamic RAM employs |
| A. | capacitor or mosfet |
| B. | fet or jfet |
| C. | capacitor or bjt |
| D. | bjt or mos |
| Answer» A. capacitor or mosfet | |
| Explanation: dynamic ram employs a capacitor or mosfet. thus, it’s access time is more and it is slower in operation. | |
| 258. |
Which one of the following is volatile in nature? |
| A. | rom |
| B. | erom |
| C. | prom |
| D. | ram |
| Answer» D. ram | |
| Explanation: ram is a volatile memory, therefore it stores data as long as power is on. ram is also known as rwm (i.e. read write memory). rams are volatile because the stored data will be lost once the d.c. power applied to the flip-flops is removed. | |
| 259. |
The magnetic core memories have been replaced by semiconductor RAMs, why? |
| A. | semiconductor rams are highly flexible |
| B. | semiconductor rams have highest storing capacity |
| C. | semiconductor rams are smaller in size |
| D. | all of the mentioned |
| Answer» D. all of the mentioned | |
| Explanation: ram is a volatile memory, therefore it stores data as long as power is on. ram is also known as rwm (i.e. read write memory). the magnetic core memories have been replaced by semiconductor rams because of smaller in size, high storing capacity as well as flexibility. | |
| 260. |
The data written in flip-flop remains stored as long as |
| A. | d.c. power is supplied |
| B. | d.c. power is removed |
| C. | a.c. power is supplied |
| D. | a.c. power is removed |
| Answer» A. d.c. power is supplied | |
| Explanation: since flip-flops are made up of semiconductor materials. so, it can’t accept a.c. source and the data written in flip-flop remains stored as long as the dc power is maintained. | |
| 261. |
Memory is a/an |
| A. | device to collect data from other computer |
| B. | block of data to keep data separately |
| C. | indispensable part of computer |
| D. | device to connect through all over the world |
| Answer» C. indispensable part of computer | |
| Explanation: memory is an indispensable unit of a computer and microprocessor based systems which stores permanent or temporary data. | |
| 262. |
The instruction used in a program for executing them is stored in the |
| A. | cpu |
| B. | control unit |
| C. | memory |
| D. | microprocessor |
| Answer» C. memory | |
| Explanation: all of the program and the instructions are stored in the memory. the processor fetches it as and when required. | |
| 263. |
A register is able to hold |
| A. | data |
| B. | word |
| C. | nibble |
| D. | both data and word |
| Answer» B. word | |
| Explanation: register is also a part of memory inside a computer. it stands there to hold a word. a word is a group of 16-bits or 2-bytes. | |
| 264. |
A register file holds |
| A. | a large number of word of information |
| B. | a small number of word of information |
| C. | a large number of programs |
| D. | a modest number of words of information |
| Answer» D. a modest number of words of information | |
| Explanation: a register file is different from a simple register because of capability to hold a modest number of words of information. a word is a group of 16-bits or 2-bytes. | |
| 265. |
The very first computer memory consisted of |
| A. | a small display |
| B. | a large memory storage equipment |
| C. | an automatic keyboard input |
| D. | an automatic mouse input |
| Answer» B. a large memory storage equipment | |
| Explanation: the very first computer memory consisted of a minute magnetic toroid, which required large, bulky circuit boards stored in large cabinates. | |
| 266. |
A minute magnetic toroid is also called as |
| A. | large memory |
| B. | small memory |
| C. | core memory |
| D. | both small and large memory |
| Answer» C. core memory | |
| Explanation: a minute magnetic toroid is also called as core memory which is made up of a semiconductor. a semiconductor is a device whose electrical | |
| 267. |
Which one of the following has capability to store data in extremely high densities? |
| A. | register |
| B. | capacitor |
| C. | semiconductor |
| D. | flip-flop |
| Answer» C. semiconductor | |
| Explanation: semiconductor has capability to store data in extremely high densities. | |
| 268. |
A large memory is compressed into a small one by using |
| A. | lsi semiconductor |
| B. | vlsi semiconductor |
| C. | cdr semiconductor |
| D. | ssi semiconductor |
| Answer» B. vlsi semiconductor | |
| Explanation: vlsi (very large scale integration) semiconductor is used in modern computers to short the size of memory. | |
| 269. |
VLSI chip utilizes |
| A. | nmos |
| B. | cmos |
| C. | bjt |
| D. | all of the mentioned |
| Answer» D. all of the mentioned | |
| Explanation: vlsi (very large scale integration) is a memory chip which is made up of nmos, cmos, bjt, and bicmos. it can include 10,000 to 100,000 gates per ic. | |
| 270. |
CD-ROM refers to |
| A. | floppy disk |
| B. | compact disk-read only memory |
| C. | compressed disk-read only memory |
| D. | compressed disk- random access memory |
| Answer» B. compact disk-read only memory | |
| Explanation: cd-rom refers to compact disk-read only memory. | |
| 271. |
Data stored in an electronic memory cell can be accessed at random and on demand using |
| A. | memory addressing |
| B. | direct addressing |
| C. | indirect addressing |
| D. | control unit |
| Answer» B. direct addressing | |
| Explanation: direct addressing eliminates the need to process a large stream of irrelevant data in order to the desired data word. | |
| 272. |
The full form of PLD is |
| A. | programmable large device |
| B. | programmable long device |
| C. | programmable logic device |
| D. | programmable lengthy device |
| Answer» C. programmable logic device | |
| Explanation: the full form of pld is programmable logic device. | |
| 273. |
The evolution of PLD began with |
| A. | erom |
| B. | ram |
| C. | prom |
| D. | eeprom |
| Answer» A. erom | |
| Explanation: the evolution of pld (programmable logic device) began with programmable read only memory (i.e. prom). here, the rom can be externally programmed as per the user. | |
| 274. |
A ROM is defined as |
| A. | read out memory |
| B. | read once memory |
| C. | read only memory |
| D. | read one memory |
| Answer» C. read only memory | |
| Explanation: a rom is defined as read only memory which can read the instruction stored in a computer. | |
| 275. |
In layering, n layers provide service to |
| A. | n layer |
| B. | n-1 layer |
| C. | n+1 layer |
| D. | none of the mentioned |
| Answer» C. n+1 layer | |
| Explanation: in layering n layer provides service to n+1 layer and use the service provided by n-1 layer. | |
| 276. |
Which can be used as an intermediate device in between transmitter entity and receiver entity? |
| A. | ip router |
| B. | microwave router |
| C. | telephone switch |
| D. | all of the mentioned |
| Answer» D. all of the mentioned | |
| Explanation: ip router, microwave router and telephone switch can be used as an intermediate device between communication of two entities. | |
| 277. |
Which has comparatively high frequency component? |
| A. | sine wave |
| B. | cosine wave |
| C. | square wave |
| D. | none of the mentioned |
| Answer» C. square wave | |
| Explanation: square wave has comparatively high frequency component in them. | |
| 278. |
Which has continuous transmission? |
| A. | asynchronous |
| B. | synchronous |
| C. | asynchronous & synchronous |
| D. | none of the mentioned |
| Answer» B. synchronous | |
| Explanation: synchronous has continuous transmission where as asynchronous have sporadic transmission. | |
| 279. |
Which requires bit transitions? |
| A. | asynchronous |
| B. | synchronous |
| C. | asynchronous & synchronous |
| D. | none of the mentioned |
| Answer» B. synchronous | |
| Explanation: synchronous transmission needs bit transition. | |
| 280. |
In synchronous transmission, receiver must stay synchronous for |
| A. | 4 bits |
| B. | 8 bits |
| C. | 9 bits |
| D. | 16 bits |
| Answer» C. 9 bits | |
| Explanation: in synchronous transmission, receiver must stay synchronous for 9 bits. | |
| 281. |
Which is more efficient? |
| A. | parity check |
| B. | cyclic redundancy check |
| C. | parity & cyclic redundancy check |
| D. | none of the mentioned |
| Answer» B. cyclic redundancy check | |
| Explanation: cyclic redundancy check is more efficient than parity check. | |
| 282. |
Which can detect two bit errors? |
| A. | parity check |
| B. | cyclic redundancy check |
| C. | parity & cyclic redundancy check |
| D. | none of the mentioned |
| Answer» B. cyclic redundancy check | |
| Explanation: crc is more powerful and it can detect various kind of errors like 2 bit errors. | |
| 283. |
CRC uses |
| A. | multiplication |
| B. | binary division |
| C. | multiplication & binary division |
| D. | none of the mentioned |
| Answer» C. multiplication & binary division | |
| Explanation: crc uses more math like multiplication and binary division. | |
| 284. |
Which of the following has the capability to store the information permanently? |
| A. | ram |
| B. | rom |
| C. | storage cells |
| D. | both ram and rom |
| Answer» B. rom | |
| Explanation: rom (read only memory) has the capability to store the information permanently. ram provides random access to memory. storage cells are responsible for the transfer of data from and into the memory. | |
| 285. |
ROM has the capability to perform |
| A. | write operation only |
| B. | read operation only |
| C. | both write and read operation |
| D. | erase operation |
| Answer» B. read operation only | |
| Explanation: rom means “read only memory”. hence, it has capability to perform read operation only. no write or erase operation could be performed in the rom. | |
| 286. |
Since, ROM has the capability to read the information only then also it has been designed, why? |
| A. | for controlling purpose |
| B. | for loading purpose |
| C. | for booting purpose |
| D. | for erasing purpose |
| Answer» C. for booting purpose | |
| Explanation: rom means “read only memory”. hence, it has capability to perform read operation only. no write or erase operation could be performed in the rom. it has designed to provide the computer with resident programmes and for booting purpose. | |
| 287. |
The ROM is a |
| A. | sequential circuit |
| B. | combinational circuit |
| C. | magnetic circuit |
| D. | static circuit |
| Answer» B. combinational circuit | |
| Explanation: rom is a combination of different ics. so, it is a combinational circuit. | |
| 288. |
ROM is made up of |
| A. | nand and or gates |
| B. | nor and decoder |
| C. | decoder and or gates |
| D. | nand and decoder |
| Answer» C. decoder and or gates | |
| Explanation: rom (read only memory) has the capability to store the information permanently. rom is made up of decoder and or gates within a single ic package. | |
| 289. |
In ROM, each bit is a combination of the address variables is called |
| A. | memory unit |
| B. | storage class |
| C. | data word |
| D. | address |
| Answer» D. address | |
| Explanation: in rom, each bit combination that comes out of the output lines is called data word. usually, a word consists of 16-bits or 2-bytes. | |
| 290. |
What is memory decoding? |
| A. | the process of memory ic used in a digital system is overloaded with data |
| B. | the process of memory ic used in a digital system is selected for the range of address assigned |
| C. | the process of memory ic used in a digital system is selected for the range of data assigned |
| D. | the process of memory ic used in a digital system is overloaded with data allocated in memory cell |
| Answer» B. the process of memory ic used in a digital system is selected for the range of address assigned | |
| Explanation: the memory ic used in a digital system is selected or enabled only for the range of addresses assigned to it and this process is called memory decoding. it decodes the memory to be selected for a specific address. | |
| 291. |
Which is not a removable drive? |
| A. | zip |
| B. | hard disk |
| C. | super disk |
| D. | jaz |
| Answer» C. super disk | |
| Explanation: hard disk is present inside a computer. so, it is not a removable drive. | |
| 292. |
In ROM, each bit combination that comes out of the output lines is called |
| A. | memory unit |
| B. | storage class |
| C. | data word |
| D. | address |
| Answer» C. data word | |
| Explanation: in rom, each bit combination that comes out of the output lines is called data word. usually, a word consists of 16-bits or 2-bytes. | |
| 293. |
VLSI chip utilizes |
| A. | nmos |
| B. | cmos |
| C. | bjt |
| D. | all of the mentioned |
| Answer» D. all of the mentioned | |
| Explanation: very large scale integration (vlsi) (ranging from 10,000 to 100,000 gates per ic) is a memory chip which is made up of nmos, cmos, bjt, and bicmos. | |
| 294. |
How many address bits are required to select memory location in Memory decoder? |
| A. | 4 kb |
| B. | 8 kb |
| C. | 12 kb |
| D. | 16 kb |
| Answer» C. 12 kb | |
| Explanation: memory decoder decodes the memory to be selected for a specific address. since, the given eprom and ram are of 4 kb (4 * 1024 = 4096) | |
| 295. |
How memory expansion is done? |
| A. | by increasing the supply voltage of the memory ics |
| B. | by decreasing the supply voltage of the memory ics |
| C. | by connecting memory ics together |
| D. | by separating memory ics |
| Answer» C. by connecting memory ics together | |
| Explanation: memory ics can be connected together to expand the number of memory words or the number of bits per word. | |
| 296. |
IC 4116 is organised as |
| A. | 512 * 4 |
| B. | 16 * 1 |
| C. | 32 * 4 |
| D. | 64 * 2 |
| Answer» C. 32 * 4 | |
| Explanation: ic 4116 is organised as 16 * 1 k which has capability to store 16 kb. | |
| 297. |
PLD contains a large number of |
| A. | flip-flops |
| B. | gates |
| C. | registers |
| D. | all of the mentioned |
| Answer» D. all of the mentioned | |
| Explanation: programmable logic devices is a collection of a large number of gates, flip-flops, registers that are interconnected on the chip. thus, it is used for designing logic circuits. | |
| 298. |
How many 1024 * 1 RAM chips are required to construct a 1024 * 8 memory system? |
| A. | 4 |
| B. | 6 |
| C. | 8 |
| D. | 12 |
| Answer» C. 8 | |
| Explanation: one 1024 * 1 ram chips is of 1-bit. so, for construction of 1024 * 8 ram chip of 8-bits, | |
| 299. |
How many 16K * 4 RAMs are required to achieve a memory with a capacity of 64K and a word length of 8 bits? |
| A. | 2 |
| B. | 4 |
| C. | 6 |
| D. | 8 |
| Answer» D. 8 | |
| Explanation: 16k * 4 = 64k ram is of 64k. therefore, for a word of length 8-bits, | |
| 300. |
Why antifuses are implemented in a PLD? |
| A. | to protect from high voltage |
| B. | to increase the memory |
| C. | to implement the programmes |
| D. | as a switching devices |
| Answer» C. to implement the programmes | |
| Explanation: programmable logic devices is a collection of a large number of gates, flip-flops, | |
Done Studing? Take A Test.
Great job completing your study session! Now it's time to put your knowledge to the test. Challenge yourself, see how much you've learned, and identify areas for improvement. Don’t worry, this is all part of the journey to mastery. Ready for the next step? Take a quiz to solidify what you've just studied.