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Chapter:

120+ Ultrasonic Testing Level 2 Solved MCQs

in Non Destructive Testing and Evaluation

These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Mechanical Engineering .

Chapters

Chapter: Ultrasonic Testing Level 2
1.

Most commercial ultrasonic testing is performed at frequencies between:

A. 1 MHz and 10 MHz
B. 1 MHz and 100 MHz
C. 10 MHz and 50 MHz
D. 1 MHz and 25 MHz
Answer» D. 1 MHz and 25 MHz
2.

For a transducer with any given Q, resolution increases with:

A. Sensitivity
B. Frequency
C. Wavelength
D. Crystal thickness
Answer» B. Frequency
3.

Resolving power of a transducer is directly proportional to its:

A. Wavelength
B. Crystal thickness
C. Bandwidth
D. Q
Answer» C. Bandwidth
4.

The term is used to refer to the product of wave velocity and density is:

A. Acoustic impedance
B. The velocity-density ratio
C. Index of refraction
D. Reflection co-efficient
Answer» A. Acoustic impedance
5.

Snell's law is given by which of the following:

A. (Sin A)/(Sin B) = VB/VA
B. (Sin A)/(Sin B) = VA/VB
C. (Sin A)/ VB = V(Sin B)/VA
D. (Sin A)[VA] = (Sin B)[ VB]
Answer» B. (Sin A)/(Sin B) = VA/VB
6.

Snell's law is used to calculate:

A. Angle of beam divergence
B. Angle of diffraction
C. Angle of refraction
D. None of the above
Answer» C. Angle of refraction
7.

Calculate the refracted shear wave angle in steel [VS = 0.323cm/microsec] for an incident longitudinal wave of 37.9 degrees in Plexiglas [VL = 0.267cm/microsec]

A. 26 degrees
B. 45 degrees
C. 48 degrees
D. 64 degrees
Answer» B. 45 degrees
8.

Calculate the refracted shear wave angle in steel [VS = 0.323cm/microsec] for an incident longitudinal wave of 45.7 degrees in Plexiglas [VL = 0.267cm/microsec]

A. 64 degrees
B. 45.7 degrees
C. 60 degrees
D. 70 degrees
Answer» C. 60 degrees
9.

Calculate the refracted shear wave angle in aluminium [VS = 0.31cm/microsec] for an incident longitudinal wave of 43.5 degrees in Plexiglas [VL =0.267cm/microsec]

A. 53 degrees
B. 61 degrees
C. 42 degrees
D. 68 degrees
Answer» A. 53 degrees
10.

Calculate the refracted shear wave angle in aluminium [VS = 0.31cm/microsec] for an incident longitudinal wave of 53 degrees in Plexiglas [VL = 0.267cm/microsec]

A. 53 degrees
B. 61 degrees
C. 42 degrees
D. 68 degrees
Answer» D. 68 degrees
11.

Lithium sulphate, barium titanate and lead metaniobate are examples of:

A. Magnetostrictive elements
B. Piezoelectric elements
C. Rochelle salts
D. Y cut crystals
Answer» B. Piezoelectric elements
12.

The particle motion for compression waves is:

A. Parallel to wave propagation
B. Transverse to wave propagation
C. Elliptical
D. Circular
Answer» A. Parallel to wave propagation
13.

Shear waves for ultrasonic testing are usually produced:

A. X cut crystals
B. Y cut crystals
C. Modulated R-F conversion
D. Mode converted longitudinal waves
Answer» B. Y cut crystals
14.

Near surface resolution can be improved by:

A. Using a narrow band transducer
B. Using a focused transducer
C. Using a high Q transducer
D. None of the above
Answer» B. Using a focused transducer
15.

The most important requirement for paintbrush transducer is:

A. Uniform beam intensity across the transducer
B. A pinpoint focal spot
C. Good horizontal linearity characteristics
D. Prescribed vertical and horizontal linearity characteristics
Answer» A. Uniform beam intensity across the transducer
16.

Which of the following is an advantage of a focused transducer?

A. Extended useful range
B. Reduced sensitivity in localised area
C. Improved signal to noise ratio over an extended range
D. Higher resolution over a limited range
Answer» D. Higher resolution over a limited range
17.

Which of the following is intended to be a ‘first cut’ or rough inspection device to be followed by more precise evaluation of any discontinuities found?

A. Wheel transducer
B. Focused transducer
C. Paintbrush transducer
D. Ball transducer
Answer» C. Paintbrush transducer
18.

A wider entry surface indication or pulse may result from:

A. Side lobes of the sound beam being reflected from a rough surface
B. Using a lower energy pulser
C. Using a higher amplifier attenuation setting
D. Huygen's principle
Answer» A. Side lobes of the sound beam being reflected from a rough surface
19.

Which of the following methods might be used to reduce attenuation losses in an ultrasonic test?

A. Use a shorter wavelength
B. Use a lower frequency transducer
C. Change from longitudinal waves to shear waves
D. Change to a coarser grained test piece
Answer» B. Use a lower frequency transducer
20.

When comparing discontinuity echoes to equivalent flat bottom hole echoes in materials with similar impedance, surface finish and attenuation:

A. The flaw is never larger than the flat bottom hole
B. The flaw is never smaller than the flat bottom hole
C. The flaw is always smaller than the flat bottom hole
D. None of the above
Answer» D. None of the above
21.

An advantage of immersion testing is that:

A. Large parts are easily inspected
B. Most test systems are easily transported in the field
C. High test frequencies may be used
D. Most test systems are not easily transported in the field
Answer» C. High test frequencies may be used
22.

An advantage of immersion testing is that:

A. Large parts may be easily inspected
B. Most test systems are easily transported in the field
C. Low test frequencies may be used
D. Irregularly shaped test pieces can be virtually completely examined
Answer» D. Irregularly shaped test pieces can be virtually completely examined
23.

An ultrasonic data display which shows a plan view presentation of the data is called:

A. A scan
B. B scan
C. C scan
D. Orthogonal view
Answer» C. C scan
24.

An ultrasonic display which shows a cross section of the test piece and any flaws which are found are called:

A. A scan
B. B scan
C. C scan
D. Orthogonal view
Answer» B. B scan
25.

An ultrasonic display which shows echo locations and amplitude is called:

A. A scan
B. B scan
C. C scan
D. Orthogonal view
Answer» A. A scan
26.

An advantage of using lower frequencies during ultrasonic testing is that:

A. Near surface resolution is improved
B. Sensitivity to small discontinuities is improved
C. Beam spread is reduced
D. Sensitivity to unfavourable oriented flaws is improved
Answer» D. Sensitivity to unfavourable oriented flaws is improved
27.

A method of compensating for the ‘dead zone’ or near surface resolution problems is to:

A. Inspect all areas of the test piece twice to assure repeatability of indications
B. Re-inspect from the opposite side of the test piece if geometry permits
C. Re-inspect using a higher energy pulse
D. Re-inspect using a higher frequency transducer that does not have a ‘dead
Answer» B. Re-inspect from the opposite side of the test piece if geometry permits
28.

When testing a test piece with parallel front and back surfaces, no back wall echo can be obtained. Which of the following actions might enable you to obtain a back wall echo?

A. Use a wetter transducer
B. Use a lower frequency transducer
C. Use a transducer with a narrower bandwidth
D. Use a higher frequency transducer
Answer» B. Use a lower frequency transducer
29.

Materials which can readily be inspected with frequencies of 1 to 5 MHz are:

A. Steel, cast iron and concrete
B. Titanium, wood and aluminium
C. Magnesium, titanium and steel
D. All of the above
Answer» C. Magnesium, titanium and steel
30.

When variations are noticed in the front surface reflection, the test piece should be inspected for possible near surface discontinuities by:

A. Using a lower frequency transducer
B. Using a higher pulse energy
C. Inspecting from the opposite side
D. Calibrating on a smaller diameter flat bottom hole
Answer» C. Inspecting from the opposite side
31.

Forging bursts are most often orientated:

A. Parallel to the surface
B. Perpendicular to the surface
C. In a random manner
D. At an angle of 45 degrees to the surface
Answer» C. In a random manner
32.

The purpose of adding a wetting agent to an immersion bath is:

A. To make sure the bath is wet
B. To reduce corrosive properties of the bath
C. To eliminate air bubbles in the bath
D. To prevent rust
Answer» C. To eliminate air bubbles in the bath
33.

During immersion testing of pipe or tubing the incident longitudinal wave angle must be limited to a narrow range. The reason for the upper limit is:

A. To avoid complete reflection of ultrasound from the test piece
B. To prevent formation of Rayleigh waves
C. To prevent formation of shear waves
D. To avoid saturating the test piece with ultrasound
Answer» A. To avoid complete reflection of ultrasound from the test piece
34.

A calibration for immersion ultrasonic testing of pipe or tubing should establish a transducer position such as:

A. I.D. and O.D. notches produce equal responses for equivalent metal path distances
B. Rayleigh waves are generated through the entire pipe or tubing wall
C. All ultrasound enters the test piece
D. Only longitudinal waves are generated in the test piece
Answer» C. All ultrasound enters the test piece
35.

During immersion ultrasonic testing of pipe or tubing, spurious echoes may be caused by:

A. Dirt on the test piece
B. Grease on the test piece
C. Air bubbles on the test piece
D. All of the above
Answer» D. All of the above
36.

Typical frequencies which might be used to perform ultrasonic testing of concrete are:

A. 25 to 100 kHz
B. 200 to 5 MHz
C. 1 MHz to 5 MHz
D. 2.25 MHz to 10 MHz
Answer» A. 25 to 100 kHz
37.

Typical frequencies which might be used to perform ultrasonic testing of ferrous and non-ferrous welds are:

A. 25 to 100 kHz
B. 200 to 5 MHz
C. 1 MHz to 5 MHz
D. 2.25 MHz to 10 MHz
Answer» C. 1 MHz to 5 MHz
38.

Which of the following materials would probably require testing at the lowest frequency?

A. Small grained mild steel
B. Mild steel castings
C. Mild steel forgings
D. Cast iron
Answer» D. Cast iron
39.

Which of the following is an advantage of contact testing over immersion?

A. Ability to maintain uniform coupling on rough surface
B. Longer dead time near the front surface of the test piece
C. Ease of field use
D. Ability to continuously vary incident wave angle during test
Answer» C. Ease of field use
40.

Which of the following is a disadvantage of contact testing?

A. Ability to maintain uniform coupling on rough surface
B. Ease of field use
C. Greater penetrating power than immersion testing
D. Less penetrating power than immersion testing
Answer» A. Ability to maintain uniform coupling on rough surface
41.

A typical application for a through transmission technique is:

A. Flaw depth sizing
B. Flaw depth location
C. Thickness gauging
D. Bond/unbond testing
Answer» D. Bond/unbond testing
42.

An ultrasonic technique in which two transducers are used, in a constant position relative to each other, is:

A. Through transmission
B. Contact testing
C. Pulse echo
D. Continuous wave
Answer» A. Through transmission
43.

Which of the following cast materials could most likely be successfully ultrasonically tested?

A. Low carbon steel
B. Stainless steel
C. Iron
D. Pure lead
Answer» A. Low carbon steel
44.

Which of the following product forms would probably be tested at the lowest frequency?

A. Forgings
B. Hot rolled plate
C. Castings
D. Extrusions
Answer» C. Castings
45.

Addition of approximately 6% antimony as an alloying element could be expected to increase the ultrasonic inspectability of which of the following materials?

A. Low carbon steel
B. Stainless steel
C. Iron
D. Pure lead
Answer» D. Pure lead
46.

Strong signals which travel across the horizontal time base of an A scan presentation while the transducer is motionless on the test piece are probably:

A. Randomly oriented flaws
B. Electrical interference
C. Grain noise
D. Loose wedge on transducer
Answer» B. Electrical interference
47.

Excessive ringing of the transducer could be caused by:

A. Electrical interference
B. Loose crystal
C. Test piece with large grain size
D. Test piece with small grain size
Answer» B. Loose crystal
48.

When inspecting a long bar with a longitudinal wave from one end, a series of additional echoes are seen immediately after the bottom surface reflection. these are most likely:

A. Refracted shear and longitudinal waves caused by beam spread
B. Flaw indications
C. Multiples of the back surface reflection
D. None of the above
Answer» D. None of the above
49.

One of the most apparent characteristics of a discontinuity echo, as opposed to a nonrelevant indication is:

A. Lack of repeatability
B. Sharp, distinct signal
C. Stable position with fixed transducer position
D. High noise level
Answer» B. Sharp, distinct signal
50.

Typical immersion test frequencies for wrought aluminium are:

A. 10 MHz and up
B. 5 MHz and below
C. 500 MHz to 1 MHz
D. Above 25 MHz
Answer» A. 10 MHz and up

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