Q.

Ignoring early effect, if C1 is the total capacitance tied to the emitter, what is the input pole of a simple C.B. stage?

A. 1/gm * c1
B. 2/gm * c1
C. gm * c1
D. gm * 2c1
Answer» A. 1/gm * c1
Explanation: the resistance looking into the
1.7k
0
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