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| Q. |
Ignoring early effect, if C1 is the total capacitance tied to the emitter, what is the input pole of a simple C.B. stage? |
| A. | 1/gm * c1 |
| B. | 2/gm * c1 |
| C. | gm * c1 |
| D. | gm * 2c1 |
| Answer» A. 1/gm * c1 | |
| Explanation: the resistance looking into the | |
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