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Q. |
## Ignoring early effect, if C1 is the total capacitance tied to the emitter, what is the input pole of a simple C.B. stage? |

A. | 1/gm * c1 |

B. | 2/gm * c1 |

C. | gm * c1 |

D. | gm * 2c1 |

Answer» A. 1/gm * c1 | |

Explanation: the resistance looking into the |

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