

McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Computer Science Engineering (CSE) , Master of Computer Applications (MCA) .
Chapters
51. |
Which of the following denotes Chomskianhiearchy? |
A. | REG ⊂ CFL ⊂ CSL ⊂ type0 |
B. | CFL ⊂ REG ⊂ type0 ⊂ CSL |
C. | CSL ⊂ type0 ⊂ REG ⊂ CFL |
D. | CSL ⊂ CFL ⊂ REG ⊂ type0 |
Answer» A. REG ⊂ CFL ⊂ CSL ⊂ type0 |
52. |
The concept of FSA is much used in this part of the compiler |
A. | Lexical analysis |
B. | Parser |
C. | Code generation |
D. | Code optimization |
Answer» A. Lexical analysis |
53. |
The following grammar G = (N, T, P, S)**spaceN = {S, A, B, C, D, E}**spaceT = {a, b, c}**spaceP : S → aAB**spaceAB → CD**spaceCD → CE**spaceC → aC**spaceC → b**spacebE → bc is |
A. | is type 3 |
B. | is type 2 but not type 3 |
C. | is type 1 but not type 2 |
D. | is type 0 but not type 1 |
Answer» C. is type 1 but not type 2 |
54. |
The following CFG is in S → aBB**spaceB → bAA**spaceA → a**spaceB → b |
A. | Chomsky normal form but not strong Chomsky normal form |
B. | Weak Chomsky normal form but not Chomsky normal form |
C. | Strong Chomsky normal form |
D. | Greibach normal form |
Answer» D. Greibach normal form |
55. |
Which of the following statements is wrong? |
A. | The regular sets are closed under intersection |
B. | The class of regular sets is closed under substitution |
C. | The class of regular sets is closed under homomorphism |
D. | Context Sensitive Grammar(CSG) can be recognized by Finite State Machine |
Answer» D. Context Sensitive Grammar(CSG) can be recognized by Finite State Machine |
56. |
Context free grammar is not closed under |
A. | Product operation |
B. | Union |
C. | Complementation |
D. | kleene star |
Answer» C. Complementation |
57. |
Let the class of language accepted by finite state machine be L1 and the class of languages represented by regular expressions be L2 then |
A. | L1 |
B. | L1>=L2 |
C. | L1 U L2 = .* |
D. | L1=L2 |
Answer» D. L1=L2 |
58. |
Which of the following statement is wrong? |
A. | Any regular language has an equivalent context-free grammar. |
B. | Some non-regular languages can’t be generated by any context-free grammar |
C. | Intersection of context free language and a regular language is always context-free |
D. | All languages can be generated by context- free grammar |
Answer» D. All languages can be generated by context- free grammar |
59. |
Grammar that produce more than one Parse tree for same sentence is: |
A. | Ambiguous |
B. | Unambiguous |
C. | Complementation |
D. | Concatenation |
Answer» A. Ambiguous |
60. |
The language accepted by a Push down Automata: |
A. | Type 0 |
B. | Type 1 |
C. | Type 2 |
D. | Type 3 |
Answer» C. Type 2 |
61. |
The PDA is called non-deterministic PDA when there are more than one out going edges from……… state: |
A. | START or READ |
B. | POP or REJECT |
C. | READ or POP |
D. | PUSH or POP |
Answer» C. READ or POP |
62. |
Let L be a language defined over an alphabet ∑,then the language of strings , defined over ∑, not belonging to L denoted by LC or L. is called : |
A. | Non regular language of L |
B. | Complement of the language L |
C. | None of the given |
D. | All of above |
Answer» B. Complement of the language L |
63. |
All NonNull words of the CFL can be generated by the corresponding CFG which is in CNF i.e the grammar in CNF will generate the same language except the: |
A. | String |
B. | Regular language |
C. | Null string |
D. | None of the above |
Answer» C. Null string |
64. |
Let L={w (0 + 1)* w has even number of 1s}, i.e. L is the set of all bit strings with even number of 1s. Which one of the regular expression below represents L? |
A. | (0*10*1)* |
B. | 0*(10*10*)* |
C. | 0*(10*1*)*0* |
D. | 0*1(10*1)*10* |
Answer» B. 0*(10*10*)* |
65. |
Consider the following Finite State Automaton The language accepted by this automaton is given by the regular expression |
A. | b*ab*ab*ab |
B. | (a+b)* |
C. | b*a(a+b)* |
D. | b*ab*ab |
Answer» C. b*a(a+b)* |
66. |
Let L1 be a recursive language. Let L2 and L3 be languages that are recursively enumerable but not recursive. Which of the following statements is not necessarily true? |
A. | L2-L1 is recursively enumerable |
B. | L1-L3 is recursively enumerable |
C. | L2 intersection L1 is recursively enumerable |
D. | L2 union L1 is recursively enumerable |
Answer» B. L1-L3 is recursively enumerable |
67. |
Let L denotes the language generated by the grammar S – OSO/00. Which of the following is true? |
A. | L = O |
B. | L is regular but not O |
C. | L is context free but not regular |
D. | L is not context free |
Answer» B. L is regular but not O |
68. |
Let S and T be language over ={a,b} represented by the regular expressions (a+b*)* and (a+b)*, respectively. Which of the following is true? |
A. | ScT (S is a subset of T) |
B. | TcS (T is a subset of S) |
C. | S=T |
D. | SnT=Ø |
Answer» C. S=T |
69. |
Which of the following pairs have DIFFERENT expressive power? |
A. | Deterministic finite automata (DFA) and Non-Deterministic finite automata(NFA) |
B. | Deterministic push down automata (DPDA) and Non-deterministic pushdown automata |
C. | Deterministic single-tape Turing machine and Non-deterministic single-tape Turing Machine |
D. | Single-tape Turing machine and multi-tape Turing machine |
Answer» B. Deterministic push down automata (DPDA) and Non-deterministic pushdown automata |
70. |
Match all items in Group 1 with correct options from those given in Group 2. List I List II**spaceP. Regular Expression 1. Syntax analysis**spaceQ. Push down automata 2. Code Generation**spaceR. Dataflow analysis 3. Lexical analysis**spaceS. Register allocation 4. Code optimization |
A. | P-4, Q-1, R-2, S-3 |
B. | P-3, Q-1, R-4, S-2 |
C. | P-3, Q-4, R-1, S-2 |
D. | P-2, Q-1, R-4, S-3 |
Answer» B. P-3, Q-1, R-4, S-2 |
71. |
A minimum state deterministic finite automation accepting the language L = {W W € {0,1}* , number of 0's and 1's in W are divisible by 3 and 5 respectively has |
A. | 15 states |
B. | 11 states |
C. | 10 states |
D. | 9 states |
Answer» A. 15 states |
72. |
Any Language generated by an unrestricted grammar is: |
A. | Recursive |
B. | Recursively Enumerable |
C. | Not Recursive |
D. | None of the above |
Answer» A. Recursive |
73. |
The Family of recursive language is not closed under which of the following operations: |
A. | Union |
B. | Intersection |
C. | Complementation |
D. | None of the above. |
Answer» D. None of the above. |
74. |
PCP is: |
A. | Decidable |
B. | Undecidable |
C. | Sometimes Decidable |
D. | None of the |
Answer» B. Undecidable |
75. |
If PCP is decidable then MPCP is |
A. | Decidable |
B. | Undecidable |
C. | Can’t Say |
D. | None of the |
Answer» C. Can’t Say |
76. |
Consider a language L for which there exists a Turing machine ™, T, that accepts every word in L and either rejects or loops for every word that is not in L. The language L is |
A. | NP hard |
B. | NP complete |
C. | Recursive |
D. | Recursively enumerable |
Answer» D. Recursively enumerable |
77. |
Consider the following statements
|
A. | I only |
B. | I and II |
C. | I and III |
D. | II and III |
Answer» B. I and II |
78. |
Recursively enumerable languages are not closed under |
A. | Union |
B. | homomorphism |
C. | complementation |
D. | concatenation |
Answer» C. complementation |
79. |
Which of the following problem is undecidable? |
A. | Membership problem for CFL |
B. | Membership problem for regular sets |
C. | Membership problem for CSL |
D. | Membership problem for type 0 languages |
Answer» D. Membership problem for type 0 languages |
80. |
Recursive languages are |
A. | A proper superset of CFL |
B. | Always recognized by PDA |
C. | Are also called type 0 languages |
D. | Always recognized by FSA |
Answer» A. A proper superset of CFL |
81. |
Consider the following problem x. Given a Turing machine M over the input alphabet Σ, any state q of M. And a word w Є Σ*, does the computation of M on w visit the state q? Which of the following statements about x is correct? |
A. | X is decidable |
B. | X is undecidable but partially decidable |
C. | X is undecidable and not even partially decidable |
D. | X is not a decision problem |
Answer» A. X is decidable |
82. |
If a language is denoted by a regular expression L = ( x )* (x y x ), then which of the following is not a legal string within L ? |
A. | yx |
B. | xyx |
C. | x |
D. | xyxyx |
Answer» D. xyxyx |
83. |
Given A = {0,1} and L = A*. If R = (0n1n, n > 0), then language L ∪ R and R are respectively |
A. | Regular, regular |
B. | Not regular, regular |
C. | Regular, not regular |
D. | Context free, not regular |
Answer» D. Context free, not regular |
84. |
If L1 and L2 are context free language and R a regular set, then which one of the languages below is not necessarily a context free language? |
A. | L1 L2 |
B. | L1 ∩ L2 |
C. | L1 ∩ R |
D. | L1 ∪ L2 |
Answer» B. L1 ∩ L2 |
85. |
The logic of pumping lemma is a good example of |
A. | Pigeon-hole principle |
B. | Divide-and-conquer technique |
C. | Recursion |
D. | Iteration |
Answer» A. Pigeon-hole principle |
86. |
For two regular languages L1 = (a + b)* a and L2 = b (a + b ) *, the intersection of L1 and L2 is given by |
A. | (a + b ) * ab |
B. | ab (a + b ) * |
C. | a ( a + b ) * b |
D. | b (a + b ) * a |
Answer» D. b (a + b ) * a |
87. |
Pumping lemma is generally used for proving that |
A. | Given grammar is regular |
B. | Given grammar is not regular |
C. | Whether two given regular expressions are equivalent or not |
D. | None of these |
Answer» B. Given grammar is not regular |
88. |
What is the highest type number which can be applied to the following grammar? S —>Aa, A —> Ba, B —>abc |
A. | Type 0 |
B. | Type 1 |
C. | Type 2 |
D. | Type 3 |
Answer» C. Type 2 |
89. |
Following syntax-directed translation scheme is used with a shift reduction (bottom up) parser that perform the action in braces immediately after a reduction by the corresponding production
|
A. | 0202021 |
B. | 1202020 |
C. | 1020202 |
D. | None of these |
Answer» A. 0202021 |
90. |
FSM can recognize |
A. | Any grammar |
B. | Only CG |
C. | Both (a) and ( b ) |
D. | Only regular grammar |
Answer» D. Only regular grammar |
91. |
Basic limitation of FSM is that it |
A. | Cannot remember arbitrary large amount of information |
B. | Sometimes fails to recognize grammars that are regular |
C. | Sometimes recognizes grammars are not regular |
D. | None of these |
Answer» A. Cannot remember arbitrary large amount of information |
92. |
Which of the following are decidable?
|
A. | 1 and 2 |
B. | 1 and 4 |
C. | 2 and 3 |
D. | 2 and 4 |
Answer» B. 1 and 4 |
93. |
If L and L¯ are recursively enumerable, then L is |
A. | Regular |
B. | Context free |
C. | Context sensitive |
D. | Recursive |
Answer» D. Recursive |
94. |
Which of the following problems is undecidable? |
A. | Membership problem for CFGs |
B. | Ambiguity problem for CFGs. |
C. | Finiteness problem for FSAs. |
D. | Equivalence problem for FSAs. |
Answer» B. Ambiguity problem for CFGs. |
95. |
Fred created a new automaton model which is a push down automaton but with two stacks and the added ability of having commands which do not read input tape but which can pop from one stack and push into the other.This new automaton can recognize (choose strongest result) |
A. | Context Free Language |
B. | Context sensitive language |
C. | Regular language |
D. | Languages recognizable by Turing machine |
Answer» D. Languages recognizable by Turing machine |
96. |
Which of the following statements is/are FALSE?
|
A. | 1 and 4 only |
B. | 1 and 3 only |
C. | 2 only |
D. | 3 only |
Answer» C. 2 only |
97. |
Consider a string s over (0+1)*. The number of 0’s in s is denoted by no(s) and the number of 1’s in s is denoted by n1(s). The language that is not regular is |
A. | L = {s ε (0+1)* I for every prefix s’ of s, I no(s’)-n1(s’) I ≤ 2} |
B. | L = {s ε (0+1)* I no(s) mod 7 = n1(s) mod 5 = 0} |
C. | L = {s ε (0+1)* I no(s) is a 3 digit prime} |
D. | L = {s ε (0+1)* I no(s)-n1(s) I ≤ 4 |
Answer» D. L = {s ε (0+1)* I no(s)-n1(s) I ≤ 4 |
98. |
Which one of the following is true regarding FOTRAN? |
A. | It is a context free language |
B. | It is a context sensitive language |
C. | It is a regular language |
D. | None of the above |
Answer» B. It is a context sensitive language |
99. |
Which statement is true? |
A. | The PDA must have one accept state and one reject state |
B. | The PDA must have one accept state and two reject state |
C. | The PDA must have two accept state and two reject state |
D. | There is no reject state in the PDA. |
Answer» D. There is no reject state in the PDA. |
100. |
TM is more powerful than FSM because |
A. | The tape movement is confined to one direction |
B. | It has no finite state control |
C. | It has the capability to remember arbitrary long sequences of input symbols |
D. | None of these |
Answer» B. It has no finite state control |
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