McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Electronics and Communication Engineering .
351. |
view plane normal vector is perpendicular to---- |
A. | viewing |
B. | projection |
C. | workstation |
D. | 3d |
Answer» C. workstation |
352. |
2 basic ways of projecting objects onto viewplane are --- and--- |
A. | normal |
B. | plane |
C. | view |
D. | reference |
Answer» C. view |
353. |
A ---- projection preserves relative proportion of object but does not produce the realistic view |
A. | serial parallel |
B. | serial, perspective |
C. | parallel, perspective |
D. | none of these |
Answer» C. parallel, perspective |
354. |
A---- projection produces realistic view but does not preserve relative proportion |
A. | serial |
B. | parallel |
C. | perspective |
D. | any |
Answer» B. parallel |
355. |
In perspective projection line of projection converge at a single point called ----- |
A. | center of projection |
B. | parallel |
C. | perspective |
D. | any |
Answer» C. perspective |
356. |
In perspective projection eye of the viewer is placed at the _. |
A. | scaling |
B. | rotation |
C. | translation |
D. | all of these |
Answer» C. translation |
357. |
In _ the projection, lines are perpendicular to the projection plane. |
A. | left of the projection |
B. | right of the projection |
C. | top of the projection |
D. | center of the projection |
Answer» D. center of the projection |
358. |
clockwise rotaton of 2D object is similar to clockwise rotation of _ in 3D |
A. | orthographic projection |
B. | oblique projection |
C. | perspective projection |
D. | cavalier projection |
Answer» A. orthographic projection |
359. |
In _ transformation,we get Z(new)=Z(old). |
A. | about xaxis |
B. | about y axis |
C. | about zaxis |
D. | none of these |
Answer» C. about zaxis |
360. |
In case of 3 clipping _ is the additional thing as compared to 2d clipping. |
A. | true |
B. | false |
C. | not allways |
D. | none of these |
Answer» B. false |
361. |
if two points used to specify a line are (x1, y1) and (x2, y2), then the equation of line is given as……….. |
A. | x-x1/y-y1= y2-y1/x2-x1 |
B. | y-y1/x-x1=y2-y1/x2-x1 |
C. | a or b |
D. | none of these |
Answer» B. y-y1/x-x1=y2-y1/x2-x1 |
362. |
the equation of a line in slope intercept form is given as…… |
A. | x = my + b |
B. | b= mx+y |
C. | y=mx+b |
D. | y+b=mx |
Answer» C. y=mx+b |
363. |
……… is the fundamental element of the picture representation. |
A. | line segments |
B. | polygon |
C. | point |
D. | circles |
Answer» C. point |
364. |
minimum…….. Points are required to represent a line |
A. | two |
B. | three |
C. | four |
D. | none of these |
Answer» A. two |
365. |
………. and ……... are the basic output primitives. |
A. | points, line segments |
B. | points, circle |
C. | line segments, curves |
D. | circles, polygons |
Answer» A. points, line segments |
366. |
points P1(3.2, 7.8) and P2(3.7, 7.1) are both represented by pixel…….. |
A. | (3,8) |
B. | (4,7) |
C. | (3,7) |
D. | (4,8) |
Answer» C. (3,7) |
367. |
pixel phasing is an anti-aliasing technique based on……… |
A. | hardware |
B. | software |
C. | both hardware and software |
D. | none of these |
Answer» A. hardware |
368. |
pixel phasing is a technique for…….. |
A. | shading |
B. | anti-aliasing |
C. | hidden line removal |
D. | none of these |
Answer» B. anti-aliasing |
369. |
a line connecting the points (1,1) and (5,3) is to be drawn, using the DDA algorithm. Find the values of x and y increments. |
A. | x-increment= 1; y-increment=1 |
B. | x-increment= 0.5; y-increment=1 |
C. | x-increment= 1; y-increment=0.5 |
D. | none of these |
Answer» C. x-increment= 1; y-increment=0.5 |
370. |
Which of the following algorithm can be used for circle generation? |
A. | bresenham\s algorithm |
B. | mid-point algorithm |
C. | both a and b |
D. | none of these |
Answer» C. both a and b |
371. |
aliasing means…….. |
A. | rendering effect |
B. | shading effect |
C. | staircase effect |
D. | cueing effect |
Answer» C. staircase effect |
372. |
slope of the line joining the points(1,2) and (3,4) is……. |
A. | 0 |
B. | 1 |
C. | 2 |
D. | 3 |
Answer» B. 1 |
373. |
a line segment…………… |
A. | extends forward |
B. | extends backward |
C. | ends at two points |
D. | extends forever both forward and backward |
Answer» C. ends at two points |
374. |
the multiplication of a vector and the reciprocal of its length is equal to …….. |
A. | zero |
B. | can\t define |
C. | one |
D. | none of the above |
Answer» C. one |
375. |
the process of turning on the pixels for a line segment is called……. |
A. | line generation |
B. | vector generation |
C. | pixel generation |
D. | a or b |
Answer» D. a or b |
376. |
the horizontal and vertical lines drawn by line drawing algorithm are…… |
A. | less |
B. | more |
C. | constant |
D. | none of these |
Answer» C. constant |
377. |
the width of 45 degree line drawn by line drawing algorithm is…………. |
A. | constant |
B. | not constant |
C. | minimum |
D. | maximum |
Answer» B. not constant |
378. |
the brightness of the line is dependent on the ……of the line. |
A. | orientation |
B. | start and end points |
C. | length |
D. | none of these |
Answer» A. orientation |
379. |
the horizontal and vertical lines appear …….the 45 degree line. |
A. | straight than |
B. | longer than |
C. | brighter than |
D. | none of these |
Answer» C. brighter than |
380. |
DDA stands for …………. |
A. | data differential algorithm |
B. | digital data algorithm |
C. | digital differential analyzer |
D. | digital differential algorithm |
Answer» C. digital differential analyzer |
381. |
the slope of a straight line is given as…….. |
A. | m= (??y / ??x) |
B. | m= (??x / ??y) |
C. | m= (x / y) |
D. | m= (y / x) |
Answer» A. m= (??y / ??x) |
382. |
the slope of a straight line is given as…….. |
A. | m= y1-y2/x2-x1 |
B. | m= y2-y1/x2-x1 |
C. | m=x2-x1/y2-y1 |
D. | m= x1-x2/y1-y2 |
Answer» B. m= y2-y1/x2-x1 |
383. |
in DDA line drawing algorithm, Δx or Δy, whichever is ………, is chosen as one raster unit. |
A. | 1 |
B. | 0 |
C. | smaller |
D. | larger |
Answer» D. larger |
384. |
sign function makes the DDA line drawing algorithm work in ………….quadrants. |
A. | i and ii |
B. | i and iii |
C. | ii and iii |
D. | all of above |
Answer» D. all of above |
385. |
if a line is to be drawn from (0,0) to (4,6) using DDA line drawing algorithm, the third point to be plotted is ……. |
A. | (1,2) |
B. | (2,3) |
C. | (3,2) |
D. | (2,1) |
Answer» A. (1,2) |
386. |
when a line with end-points (20,10) and (30,18) is to be drawn using DDA line drawing algrithm, ………is chosen as one raster unit. |
A. | ??x |
B. | ??y |
C. | a or b |
D. | any of above |
Answer» A. ??x |
387. |
when a line is to be drawn from (0,0) to (6,6) using DDA line drawing algorithm, the initial values for x and y are…….. |
A. | 0.5, 0.5 |
B. | (-0.5), (-0.5) |
C. | 0, (-0.5) |
D. | 0.5, 0 |
Answer» B. (-0.5), (-0.5) |
388. |
the DDA line drawing algorithm is …….. Dependent. |
A. | orientation |
B. | length |
C. | end points |
D. | display |
Answer» A. orientation |
389. |
the end point accuracy of DDA line drawing algorithm is …….. |
A. | good |
B. | better |
C. | best |
D. | poor |
Answer» D. poor |
390. |
floating point algorithm in DDA algorithm is…….. |
A. | time efficient |
B. | time consuming |
C. | fast |
D. | slow |
Answer» B. time consuming |
391. |
DDA line drawing algorithm for calculating pixel position is ……… the direct use of equation y = mx + b |
A. | slower than |
B. | faster than |
C. | of equal speed to that of |
D. | none of these |
Answer» B. faster than |
392. |
alorithm those use the outputs of the previous iteration, in the computation of outputs in the current iteration are called |
A. | successive approximation |
B. | incremental |
C. | double-referencing |
D. | scan-line |
Answer» B. incremental |
393. |
the advantage of Bresenham's algorithm over conventional DDA algorithm is …….? |
A. | no rounding operation |
B. | use of integer addition and subtraction |
C. | producing smooth appearance |
D. | less number of iteration |
Answer» B. use of integer addition and subtraction |
394. |
The basic attributes of a straight line segment are |
A. | type |
B. | width |
C. | color |
D. | all of these |
Answer» D. all of these |
395. |
A dashed line could be displayed by generating_________. |
A. | inter dash spacing |
B. | very short dashes |
C. | both a and b |
D. | a or b |
Answer» A. inter dash spacing |
396. |
A dotted line can be displayed by generating |
A. | very short dashes with spacing equal to and greater than dash size |
B. | very long dashes with spacing equal to or greater than dash size |
C. | very short dashes with spacing equal to and greater than dash size |
D. | dots |
Answer» C. very short dashes with spacing equal to and greater than dash size |
397. |
Which of the following is not a line-type? |
A. | dashed line |
B. | dark line |
C. | dotted line |
D. | all |
Answer» B. dark line |
398. |
In an application program, to set line-type attributes the following statement is used. |
A. | setlinetype(lt) |
B. | setlinetype(lt) |
C. | setlinetype(lt) |
D. | setline() |
Answer» B. setlinetype(lt) |
399. |
The algorithm which displays line-type attributes by plotting pixel spans is |
A. | raster line algorithm |
B. | raster scan algorithm |
C. | random line algorithm |
D. | random scan algorithm |
Answer» A. raster line algorithm |
400. |
the line drawn using line drawing algorithm should be displayed with ……brightness. |
A. | varying |
B. | constant |
C. | maximum |
D. | minimum |
Answer» B. constant |
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