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401. |
the desired characteristic of line is/are……. |
A. | it should appear as a straight line |
B. | it should start and end accurately |
C. | it should be drawn rapidly |
D. | all of above |
Answer» D. all of above |
402. |
the desired characteristic of line is/are……. |
A. | it should start and end accurately |
B. | it should be displayed with constant brightness |
C. | it should be drawn rapidly |
D. | all of above |
Answer» D. all of above |
403. |
the horizontal and vertical lines drawn by line drawing algorithm are…… |
A. | straight |
B. | curved |
C. | zig-zag |
D. | none of these |
Answer» A. straight |
404. |
A line drawn in the background color is |
A. | visible |
B. | invisible |
C. | visible or invisible |
D. | none |
Answer» B. invisible |
405. |
In Bresenham's algorithm, while generating a circle , it is easy to generate? |
A. | one octant first and other by successive reflection |
B. | one octant first and other by successive rotation |
C. | one octant first and other by successive translation |
D. | all octants |
Answer» A. one octant first and other by successive reflection |
406. |
Why a circle drawn on the screen appears to be elliptical ? |
A. | it is due to the aspect ratio of monitor |
B. | screen has rectangular shape |
C. | our eyes are not at the same level on screen |
D. | crt is completely spherical |
Answer» A. it is due to the aspect ratio of monitor |
407. |
In bresenhan's algorithm error term is initialized to ? |
A. | 0 |
B. | 1 |
C. | -0.5 |
D. | none of above |
Answer» A. 0 |
408. |
The anti - aliasing technique which allows shift of 1/4,1/2 and 3/4 of a pixel diameter enabling a closer path of a line is ? |
A. | pixel phasing |
B. | filtering |
C. | intensity compensation |
D. | sampling technique |
Answer» A. pixel phasing |
409. |
A technique by which the vertical and /or horizontal scan frequency of video signal can be changed for different purpose and applications is called |
A. | scan conversion |
B. | polygon filling |
C. | two dimensional graphics |
D. | anti aliasing |
Answer» A. scan conversion |
410. |
A pixel may be defined as |
A. | ?? smallest size object |
B. | larger size object |
C. | medium size object |
D. | none of these |
Answer» A. ?? smallest size object |
411. |
A position in plane known as |
A. | line |
B. | point |
C. | graphics |
D. | none of these |
Answer» B. point |
412. |
A line can be represented by |
A. | one point |
B. | two points |
C. | three points |
D. | four points |
Answer» B. two points |
413. |
A vector can be defined as |
A. | intersection b/w two point position |
B. | difference b/w two point position |
C. | comparison b/w two point position |
D. | none of these |
Answer» B. difference b/w two point position |
414. |
Bresanham circle algorithm uses the approach of |
A. | midpoint |
B. | point |
C. | line |
D. | none of these |
Answer» A. midpoint |
415. |
The side effect of scan conversion are |
A. | aliasing |
B. | anti aliasing |
C. | both a & b |
D. | none of these |
Answer» A. aliasing |
416. |
The process of reducing aliasing is called |
A. | resolution |
B. | anti aliasing |
C. | sampling |
D. | none of these |
Answer» B. anti aliasing |
417. |
Two basic technique for anti aliasing in ray tracing algorithm are |
A. | pixel sampling and super sampling |
B. | adaptive sampling and super sampling |
C. | pixel sampling and super sampling |
D. | none of these |
Answer» B. adaptive sampling and super sampling |
418. |
Pixel mask means |
A. | a string containing only 1;s |
B. | a string containing only 0’s |
C. | a string containing 1 and 0 |
D. | a string containing 0 and 0 |
Answer» C. a string containing 1 and 0 |
419. |
A heavy line on a video monitor could be displayed as |
A. | adjacent perpendicular lines |
B. | adjacent parallel lines |
C. | both a and b |
D. | neither a nor b |
Answer» B. adjacent parallel lines |
420. |
To set the line-width attribute the following command is used. |
A. | setlinewidthscalefactor (lw) |
B. | setlinewidth() |
C. | setlinewidthscalefacto (lw) |
D. | setlinewidthscalefactor (lw) |
Answer» D. setlinewidthscalefactor (lw) |
421. |
The parameter to “setLineWidthScaleFactor (lw) “function specifies? |
A. | standard width |
B. | relative width of the line |
C. | thickness of the line |
D. | all the above |
Answer» B. relative width of the line |
422. |
Higher persistence phosphorus needs _________ refresh rate |
A. | lower |
B. | higher |
C. | medium |
D. | none of these |
Answer» A. lower |
423. |
Higher persistence phosphorus is used in |
A. | animation |
B. | simple object |
C. | higher complex object |
D. | all of these |
Answer» C. higher complex object |
424. |
Phosphorus are of various types depending on |
A. | color |
B. | persistence |
C. | both a & b |
D. | none of these |
Answer» C. both a & b |
425. |
if one octant of the circle is generated, to complete the generation of full circle, how many reflections are required? |
A. | 1 |
B. | 2 |
C. | 4 |
D. | 8 |
Answer» D. 8 |
426. |
the best line drawing algorithm among all possible line drawing algorithm is…………. |
A. | dda |
B. | algorithm which uses direct equation of line |
C. | bresenham\s algorithm |
D. | none of them |
Answer» C. bresenham\s algorithm |
427. |
if any two point Pi(xi, yi) is considered, then it lies on the line on the line segment y = mx+b if……… |
A. | yi.mxi + b |
B. | min (x1, x2) <= xi <= max (x1, x2) |
C. | min (y1, y2) <= y <= max (y1, y2) |
D. | all of above |
Answer» D. all of above |
428. |
if a line segment between (x1, y1) and (x2, y2) is represented in parametric form with a parameter u, then the expression for can be given as…….. |
A. | x= x1-(x2-x1)u |
B. | x= x1+(x2-x1)u |
C. | x= x1+(x1-u)x2 |
D. | x= x1+(u-x1)x2 |
Answer» B. x= x1+(x2-x1)u |
429. |
a vector has ………. |
A. | a single direction |
B. | two direction |
C. | a length |
D. | a and c |
Answer» D. a and c |
430. |
The problem of aliasing are |
A. | staircase |
B. | unequal brightness |
C. | picket fence problem |
D. | all of these |
Answer» D. all of these |
431. |
The technique to minimizing aliasing are |
A. | increased no of resolution |
B. | modify pixel intensities |
C. | super sampling |
D. | all of these |
Answer» D. all of these |
432. |
Lower persistence phosphorus is used in |
A. | animation |
B. | simple object |
C. | complex object |
D. | all of these |
Answer» A. animation |
433. |
Lower persistence phosphorus needs_________ refresh rate |
A. | lower |
B. | higher |
C. | medium |
D. | none of these |
Answer» B. higher |
434. |
the equation of a line, y= mx+b, b is ……. |
A. | slope of a line the height at which the line crosses the x-axis. |
B. | slope of a line the height at which the line crosses the y-axis. |
C. | constant |
D. | slope of a line |
Answer» B. slope of a line the height at which the line crosses the y-axis. |
435. |
the basic geometric structures provided by graphics primitive packages are refered to as |
A. | inputs |
B. | input primitives |
C. | outputs |
D. | output primitives |
Answer» D. output primitives |
436. |
when a line is represented by a equation, y=mx+b and rx+sy+t=0, m=……. |
A. | (-r/s) |
B. | r/s |
C. | s/r |
D. | (-s/r) |
Answer» A. (-r/s) |
437. |
when a line is represented by a equation, y=mx+b and rx+sy+t=0, b=……. |
A. | (-s/t) |
B. | (-t/s) |
C. | s/t |
D. | t/s |
Answer» B. (-t/s) |
438. |
if two lines are parallel, they have …….slope. |
A. | different |
B. | same |
C. | zero |
D. | none of these |
Answer» B. same |
439. |
if two lines are represented by equations y=m1x+b1 and y=m2x+b2, their point of intersection is given by……… |
A. | [(m1-m2/b2-b1), (m1-m2)/(b2m1-b1m2)] |
B. | [(m2-m1/b2-b1), (m2-m1)/(b2m1-b1m2)] |
C. | [(m1m2/b2b1), (m1m2)/(b2m1-b1m2)] |
D. | [(b2-b1/m1-m2), (b2m1-b1m2)/(m1-m2)] |
Answer» D. [(b2-b1/m1-m2), (b2m1-b1m2)/(m1-m2)] |
440. |
when we say a line, it…… |
A. | extends forward |
B. | extends backward |
C. | ends at two points |
D. | extends forever both forward and backward |
Answer» D. extends forever both forward and backward |
441. |
In computer graphics, pictures or graphics objects are presented as a collection of discrete picture element called______. |
A. | dots |
B. | pixels |
C. | co-ordinates |
D. | points |
Answer» B. pixels |
442. |
. _______is the smallest addressable screen element. |
A. | dots |
B. | point |
C. | pixels |
D. | spot |
Answer» C. pixels |
443. |
We can control ____of the pixels which compose the screen. |
A. | intensity |
B. | size |
C. | shape |
D. | none |
Answer» A. intensity |
444. |
We can control ____of the pixels which compose the screen. |
A. | colour |
B. | size |
C. | shape |
D. | none |
Answer» A. colour |
445. |
Each pixel on the graphics display represents______. |
A. | a single mathematical point |
B. | 2 mathematical point |
C. | 4 mathematical point |
D. | a region which theoretically can contain infinite points |
Answer» D. a region which theoretically can contain infinite points |
446. |
. A point (42,38) can be displayed on a screen by a pixel. |
A. | (4,3) |
B. | (3,4) |
C. | (5,4) |
D. | (4,4) |
Answer» A. (4,3) |
447. |
The process of determining the appropriate pixel for representing, picture or graphics objects is known as___ |
A. | scan conversion |
B. | rasterization |
C. | scanning |
D. | graphical representation |
Answer» B. rasterization |
448. |
The process representing continuous picture or graphics objects as a collection of descrete pixels is called____. |
A. | scan conversion |
B. | rasterization |
C. | scanning |
D. | graphical representation |
Answer» A. scan conversion |
449. |
The computer graphics allows____ on pictures before displaying it. |
A. | rotation |
B. | translation |
C. | scaling and projections |
D. | all of above |
Answer» D. all of above |
450. |
Graphics devices include_____. |
A. | input devices |
B. | output devices |
C. | a and b |
D. | none |
Answer» C. a and b |
451. |
Computer graphics allows_____. |
A. | user interface |
B. | plotting of graphics and chart |
C. | office automation and desktop publishing |
D. | all of above |
Answer» D. all of above |
452. |
Computer graphics allows______. |
A. | copmuter-aided drafting and design |
B. | simulaion and animation |
C. | art and commerce |
D. | all of above |
Answer» D. all of above |
453. |
Computer graphics allows_____. |
A. | process control |
B. | cartography |
C. | art and commerce |
D. | all of above |
Answer» D. all of above |
454. |
The Hardware components of conceptual framework for interactive graphics is/are________. |
A. | input devices |
B. | output devices |
C. | a and b |
D. | none of these |
Answer» C. a and b |
455. |
The display devices are_____. |
A. | input |
B. | output |
C. | a and b |
D. | none of these |
Answer» B. output |
456. |
CRT stands for____. |
A. | cathode ray tube |
B. | colour ray tube |
C. | cathode radio tube |
D. | colour radio tube |
Answer» A. cathode ray tube |
457. |
A CRT is an evacuated _________ tube. |
A. | plastic |
B. | glass |
C. | steel |
D. | iron |
Answer» B. glass |
458. |
An____________ gun at the rear of the CRT produces a beam of electrons. |
A. | electronic |
B. | electron |
C. | element |
D. | emergency |
Answer» B. electron |
459. |
The deflection system of the CRT consistsof___________deflection plates. |
A. | vertical |
B. | horizontal |
C. | a and b |
D. | none of these |
Answer» C. a and b |
460. |
The techique(s) used for producing image on the CRT is/are__________ . |
A. | vector scan |
B. | raster scan |
C. | both a and b |
D. | none of these |
Answer» C. both a and b |
461. |
Vector scan technique is also called _________. |
A. | scalar scan |
B. | random scan |
C. | raster scan |
D. | beam scan |
Answer» B. random scan |
462. |
In vector scan display, buffer memory used is also called _________. |
A. | refresh memory |
B. | refresh buffer |
C. | buffer display |
D. | refresh circuit |
Answer» B. refresh buffer |
463. |
In vector scan display, the phosphor is to be refreshed at least ________ times per second to avoid flicker. |
A. | 10 |
B. | 20 |
C. | 30 |
D. | 40 |
Answer» C. 30 |
464. |
The techique(s) used for producing image on the CRT is/are__________. |
A. | vector scan |
B. | raster scan |
C. | both a and b |
D. | none of these |
Answer» C. both a and b |
465. |
In raster scan display,the display image is stored in the form of _________ in the refresh buffer. |
A. | 1s |
B. | 0s |
C. | 1s and 0s |
D. | none of these |
Answer» C. 1s and 0s |
466. |
In raster scan CRT, the beam is swept back and forth from _______ across the screen. |
A. | left to right |
B. | right to left |
C. | up to down |
D. | down to up |
Answer» A. left to right |
467. |
In raster Scan CRT, when a beam is moved from the left to the right,it s ____ and it is _____ when it is moved from the right to the left. |
A. | on,off |
B. | off,on |
C. | on,on |
D. | off,off |
Answer» A. on,off |
468. |
In raster scan display, the screen image repeatedly scanned, this process is called _______. |
A. | buffering of screen |
B. | refreshig of screen |
C. | rendering of screen |
D. | heghlighting screen |
Answer» B. refreshig of screen |
469. |
On a black and white system with one bit per pixel , the frame buffer is called a__________. |
A. | bitmap |
B. | pixmap |
C. | bitpixmap |
D. | pixbitmap |
Answer» A. bitmap |
470. |
The cost of vector scan display is___________ cost of raster scan dispay. |
A. | equal to |
B. | less than |
C. | more than |
D. | none of these |
Answer» C. more than |
471. |
For ____________ display , scan conversion hardware is required. |
A. | vector scan |
B. | random scan |
C. | raster scan |
D. | none of these |
Answer» C. raster scan |
472. |
Aspect ratio is the ratio of ________ to prodce equal length lines in both direction on the screen |
A. | vertical points to horizontal points |
B. | horizontal points to vertical points |
C. | left to riht and right to left diagonal points |
D. | right to left and left to right diagonal points |
Answer» A. vertical points to horizontal points |
473. |
Display file can be implemented using __________ data structure. |
A. | array |
B. | linked list |
C. | paging |
D. | all of the above |
Answer» D. all of the above |
474. |
The process of digitizing a picture definition given in an application program into a set of pixel-intensity Values is called ____________. |
A. | animation |
B. | sampling |
C. | rasterization |
D. | scan-conversion |
Answer» D. scan-conversion |
475. |
The size of frame buffer(video memory )depends on_____________. |
A. | resolution only |
B. | number of different colors only |
C. | both (b) and(c) |
D. | computer byte |
Answer» C. both (b) and(c) |
476. |
A pixel of black_white image or graphics object takes _________ space in memory. |
A. | 1 bit |
B. | 2 bits |
C. | 1 nibble |
D. | 1 byte |
Answer» C. 1 nibble |
477. |
The resolution of an image is __________. |
A. | number of pixels per unit area |
B. | number of pixels per unit length inhorizontal |
C. | number of pixels per unit length in vertical |
D. | none of these |
Answer» A. number of pixels per unit area |
478. |
The path the electron beam takes at the end of each refresh cycle is called______. |
A. | horizontal retrace |
B. | vertical retrace |
C. | diagonal retrace |
D. | left to right retrace |
Answer» B. vertical retrace |
479. |
The path the electron beam takes when returning to the left side of the CRTscreen is called_____. |
A. | horizontal retrace |
B. | vertical retrace |
C. | diagonal retrace |
D. | top to bottom retrace |
Answer» A. horizontal retrace |
480. |
Frame buffer is used to store_____. |
A. | number if pixels in image |
B. | intencities of pixels |
C. | image definition |
D. | co-ordinate values of image |
Answer» B. intencities of pixels |
481. |
The clearity of a displayed image depends on the______. |
A. | resolution |
B. | floating point precision of system |
C. | associated software |
D. | aspect ratio |
Answer» A. resolution |
482. |
Random scan monitor can also referred to as______. |
A. | vector displays |
B. | stroke writing displays |
C. | calligraphic displays |
D. | none of the above |
Answer» A. vector displays |
483. |
Which facility is provided by computer graphics to change the shape colour or other properties of objects begin viewed. |
A. | motion dynamics |
B. | update dynamics |
C. | a & b |
D. | none of these |
Answer» B. update dynamics |
484. |
and start point is (20, 20), then slope m =? |
A. | 1.2 |
B. | 0.8 |
C. | -0.4 |
D. | none of the above |
Answer» B. 0.8 |
485. |
is a point on a circle that has center at the origin. Which of the following points are also on circle ? |
A. | (2,-4),(-2,4) |
B. | (4,-2) |
C. | (-4,2) |
D. | all of above |
Answer» D. all of above |
486. |
and (5,3) is to be drawn, using DDA algorithm. Find the value of x and y increments? |
A. | x-increments = 1; y-increments =1 |
B. | x-increments = 0.5; y-increments =1 |
C. | x-increments = 1; y-increments =0.5 |
D. | none of above |
Answer» C. x-increments = 1; y-increments =0.5 |
487. |
A closed polyline is called a _________. |
A. | polychain |
B. | polygon |
C. | polyclosed |
D. | closed chain |
Answer» B. polygon |
488. |
__________ is a method for testing a pixel inside of a polygon. |
A. | even-odd method |
B. | winding number method |
C. | a and b |
D. | none of these |
Answer» C. a and b |
489. |
The seed fill algorithm for filling polygon is classified as ________ fill algorithm and _______ fill algorithm. |
A. | flood, boundry |
B. | even, odd |
C. | edge, flood |
D. | boundry, scan |
Answer» A. flood, boundry |
490. |
The putpixel function draws the pixel specified_______. |
A. | intensity |
B. | colour |
C. | size |
D. | shape |
Answer» B. colour |
491. |
Mapping the world co-ordinates into physical device co-ordinates is called__________. |
A. | translation |
B. | homogeneous transformation |
C. | co-ordinate conversion |
D. | viewing transformation |
Answer» D. viewing transformation |
492. |
An area on a physical device to which a window is mapped is called a __________. |
A. | window |
B. | segment |
C. | clip |
D. | viewport |
Answer» D. viewport |
493. |
The line is said to be interior to the clipping window if ___________point(s) is/ are interior to the window. |
A. | any line |
B. | one end |
C. | both end |
D. | any two |
Answer» C. both end |
494. |
The transformation which maps the viewing co-ordinates to normalized device co-ordinte is called _______. |
A. | viewing transformation |
B. | translation |
C. | normalization transformation |
D. | homogeneous transformation |
Answer» C. normalization transformation |
495. |
If both end points of a line are exterior to the clipping window,__________. |
A. | the line is interior to the clipping window |
B. | the line is not necessarily completely exterior to the clipping window |
C. | the line is completely exterior to the clipping window |
D. | none of these |
Answer» B. the line is not necessarily completely exterior to the clipping window |
496. |
If both end points of a line are completely to the left of clipping window,________. |
A. | the line is interior to the clipping window |
B. | the line is not necessarily completely exterior to the clipping window |
C. | the line is completely exterior to the clipping window |
D. | none of these |
Answer» C. the line is completely exterior to the clipping window |
497. |
In Cohen-sutherland subdivision line clipping algorithm, bit 1 in region code is set if _____. |
A. | end point of line is to the left of the window |
B. | end point of line is to the right of the window |
C. | end point of line is to the below of the window |
D. | end point of line is to the above of the window |
Answer» A. end point of line is to the left of the window |
498. |
In Cohen-sutherland subdivision line clipping algorithm, bit 3 in region code is set if _____. |
A. | end point of line is to the left of the window |
B. | end point of line is to the right of the window |
C. | end point of line is to the below of the window |
D. | end point of line is to the above of the window |
Answer» C. end point of line is to the below of the window |
499. |
The complex graphics operations are_______. |
A. | selection |
B. | separation |
C. | clipping |
D. | none of these |
Answer» C. clipping |
500. |
The end point of polygon are called as__________. |
A. | edges |
B. | vertices |
C. | line |
D. | none of these |
Answer» B. vertices |
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