McqMate
501. |
The power of the electromagnetic wave with electric and magnetic field intensities given by 12 and 15 respectively is |
A. | 180 |
B. | 90 |
C. | 45 |
D. | 120 |
Answer» B. 90 |
502. |
The transmission coefficient is given by 0.65. Find the return loss of the wave. |
A. | 9.11 |
B. | 1.99 |
C. | 1.19 |
D. | 9.91 |
Answer» A. 9.11 |
503. |
The intrinsic impedance of a wave with electric and magnetic field of 10 and 8 respectively is |
A. | 1.6 |
B. | 1.11 |
C. | 1.25 |
D. | 0.8 |
Answer» B. 1.11 |
504. |
The intrinsic impedance in free space is |
A. | 60π |
B. | 12π |
C. | 6π |
D. | 120π |
Answer» D. 120π |
505. |
The skin effect is a phenomenon observed in |
A. | insulators |
B. | dielectrics |
C. | conductors |
D. | semiconductors |
Answer» C. conductors |
506. |
The skin depth is measured in |
A. | meter |
B. | millimetre |
C. | centimetre |
D. | micrometer |
Answer» D. micrometer |
507. |
The attenuation constant is 0.5 units. The skin depth will be |
A. | 0.5 |
B. | 0.25 |
C. | 2 |
D. | 4 |
Answer» C. 2 |
508. |
The relation between the skin depth and frequency is given by |
A. | skin depth α f |
B. | skin depth α 1/f |
C. | skin depth α √f |
D. | skin depth α 1/√f |
Answer» D. skin depth α 1/√f |
509. |
The skin depth of the wave having a frequency of 3MHz and a velocity of 12 m/s is |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 6 |
Answer» C. 4 |
510. |
The coaxial cable consists of |
A. | conductors |
B. | dielectric |
C. | conductor with dielectric |
D. | two conductors with dielectric |
Answer» D. two conductors with dielectric |
511. |
The transmission line is said to be lossless when the |
A. | conductor is perfect and dielectric is lossless |
B. | conductor is perfect and dielectric is lossy |
C. | conductor is imperfect and dielectric is lossy |
D. | conductor is imperfect and dielectric is lossless |
Answer» A. conductor is perfect and dielectric is lossless |
512. |
The resistance of a lossless transmission line is |
A. | 0 |
B. | 1 |
C. | -1 |
D. | infinity |
Answer» A. 0 |
513. |
The attenuation constant is measured in the units of |
A. | ohm |
B. | neper |
C. | decibel |
D. | radian/sec |
Answer» B. neper |
514. |
The condition that holds good in a distortionless transmission line is |
A. | r/l = g/c |
B. | rl = gc |
C. | l/r = c/g |
D. | rg/lc |
Answer» A. r/l = g/c |
515. |
Given that R = 20 ohm, L = 40 mH, C = 40 μF, G = 0.02 mho. Find whether the line is distortionless or not. |
A. | distorted line |
B. | distortionless line |
C. | all of the mentioned |
D. | none of the mentioned |
Answer» B. distortionless line |
516. |
For R= 20 ohm and G= 0.8 mho, the attenuation constant will be |
A. | 16 |
B. | 4 |
C. | 2 |
D. | 32 |
Answer» A. 16 |
517. |
The Smith chart is a polar chart which plots |
A. | r vs z |
B. | r vs znorm |
C. | t vs z |
D. | t vs znorm |
Answer» B. r vs znorm |
518. |
The Smith chart consists of the |
A. | constant r and variable x circles |
B. | variable r and constant x circles |
C. | constant r and constant x circles |
D. | variable r and variable x circles |
Answer» C. constant r and constant x circles |
519. |
The circles in the Smith chart pass through which point? |
A. | (0,1) |
B. | (0,-1) |
C. | (-1,0) |
D. | (1,0) |
Answer» D. (1,0) |
520. |
Moving towards the clockwise direction in the Smith chart implies moving |
A. | towards generator |
B. | towards load |
C. | towards stub |
D. | towards waveguide |
Answer» A. towards generator |
521. |
The centre of the point having a normalised resistance of 1.2 ohm and reactance of 1.5 ohm is |
A. | (0.54,0) |
B. | (0.45,0) |
C. | (0.36,0) |
D. | (0.78,0) |
Answer» A. (0.54,0) |
522. |
The normalised load impedance of the transmission line 50 ohm with a load of 30 ohm is |
A. | 30 |
B. | 150 |
C. | 5/3 |
D. | 3/5 |
Answer» D. 3/5 |
523. |
The radius of the point having a normalised resistance of 1 ohm is |
A. | 1 |
B. | 0.2 |
C. | 0.5 |
D. | 0.25 |
Answer» C. 0.5 |
524. |
The open circuit line will have a reflection coefficient of |
A. | 0 |
B. | 1 |
C. | -1 |
D. | ∞ |
Answer» B. 1 |
525. |
For time varying currents, the field or waves will be |
A. | electrostatic |
B. | magneto static |
C. | electromagnetic |
D. | electrical |
Answer» C. electromagnetic |
526. |
According to Faraday’s law, EMF stands for |
A. | electromagnetic field |
B. | electromagnetic force |
C. | electromagnetic friction |
D. | electromotive force |
Answer» D. electromotive force |
527. |
Find the displacement current when the flux density is given by t3 at 2 seconds. |
A. | 3 |
B. | 6 |
C. | 12 |
D. | 27 |
Answer» C. 12 |
528. |
Find the force due to a current element of length 2cm and flux density of 12 tesla. The current through the element will be 5A. |
A. | 1 n |
B. | 1.2 n |
C. | 1.4 n |
D. | 1.6 n |
Answer» B. 1.2 n |
529. |
When the conduction current density and displacement current density are same, the dissipation factor will be |
A. | zero |
B. | minimum |
C. | maximum |
D. | unity |
Answer» D. unity |
530. |
The divergence of which quantity will be zero? |
A. | e |
B. | d |
C. | h |
D. | b |
Answer» D. b |
531. |
Find the charge density when the electric flux density is given by 2x i + 3y j + 4z k. |
A. | 10 |
B. | 9 |
C. | 24 |
D. | 0 |
Answer» B. 9 |
532. |
Find the Maxwell equation derived from Faraday’s law. |
A. | div(h) = j |
B. | div(d) = i |
C. | curl(e) = -db/dt |
D. | curl(b) = -dh/dt |
Answer» C. curl(e) = -db/dt |
533. |
Find the Maxwell law derived from Ampere law. |
A. | div(i) = h |
B. | div(h) = j |
C. | curl(h) = j |
D. | curl(b) = d |
Answer» C. curl(h) = j |
534. |
In which of the following forms can Maxwell’s equation not be represented? |
A. | static |
B. | differential |
C. | integral |
D. | harmonic |
Answer» A. static |
535. |
The charge build up in the capacitor is due to which quantity? |
A. | conduction current |
B. | displacement current |
C. | convection current |
D. | direct current |
Answer» B. displacement current |
536. |
In metals which of the following equation will hold good? |
A. | curl(h) = j |
B. | curl(j) = dd/dt |
C. | curl(h) = d |
D. | curl(j) = db/dt |
Answer» A. curl(h) = j |
537. |
Find the flux enclosed by a material of flux density 12 units in an area of 80cm. |
A. | 9.6 |
B. | 12/80 |
C. | 80/12 |
D. | 12/0.8 |
Answer» A. 9.6 |
538. |
Find the electric flux density of a material with charge density 16 units in unit volume. |
A. | 1/16 |
B. | 16t |
C. | 16 |
D. | 162 |
Answer» C. 16 |
539. |
Find the conductivity of a material with conduction current density 100 units and electric field of 4 units. |
A. | 25 |
B. | 400 |
C. | 0.04 |
D. | 1600 |
Answer» A. 25 |
540. |
Calculate the displacement current density when the electric flux density is 20sin 0.5t. |
A. | 10sin 0.5t |
B. | 10cos 0.5t |
C. | 20sin 2t |
D. | 20cos 2t |
Answer» B. 10cos 0.5t |
541. |
The power of the electromagnetic wave with electric and magnetic field intensities given by 12 and 15 respectively is |
A. | 180 |
B. | 90 |
C. | 45 |
D. | 120 |
Answer» B. 90 |
542. |
The power of a wave of with voltage of 140V and a characteristic impedance of 50 ohm is |
A. | 1.96 |
B. | 19.6 |
C. | 196 |
D. | 19600 |
Answer» C. 196 |
543. |
The power reflected by a wave with incident power of 16 units is(Given that the reflection coefficient is 0.5) |
A. | 2 |
B. | 8 |
C. | 6 |
D. | 4 |
Answer» D. 4 |
544. |
The incident and the reflected voltage are given by 15 and 5 respectively. The transmission coefficient is |
A. | 1/3 |
B. | 2/3 |
C. | 1 |
D. | 3 |
Answer» B. 2/3 |
545. |
The current reflection coefficient is given by -0.75. Find the voltage reflection coefficient. |
A. | -0.75 |
B. | 0.25 |
C. | -0.25 |
D. | 0.75 |
Answer» D. 0.75 |
546. |
The attenuation is given by 20 units. Find the power loss in decibels. |
A. | 13.01 |
B. | 26.02 |
C. | 52.04 |
D. | 104.08 |
Answer» A. 13.01 |
547. |
The curl of the electric field intensity is |
A. | conservative |
B. | rotational |
C. | divergent |
D. | static |
Answer» B. rotational |
548. |
Which of the following identities is always zero for static fields? |
A. | grad(curl v) |
B. | curl(div v) |
C. | div(grad v) |
D. | curl(grad v) |
Answer» D. curl(grad v) |
549. |
Find the displacement current density of a material with flux density of 5sin t |
A. | 2.5cos t |
B. | 2.5sin t |
C. | 5cos t |
D. | 5sin t |
Answer» C. 5cos t |
550. |
Find the magnetic field intensity when the magnetic vector potential x i + 2y j + 3z k. |
A. | 6 |
B. | -6 |
C. | 0 |
D. | 1 |
Answer» B. -6 |
551. |
The value of ∫ H.dL will be |
A. | j |
B. | i |
C. | b |
D. | h |
Answer» B. i |
552. |
Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin. |
A. | 28 |
B. | 16 |
C. | 12 |
D. | 4 |
Answer» C. 12 |
553. |
The Laplacian of the magnetic vector potential will be |
A. | –μ j |
B. | – μ i |
C. | –μ b |
D. | –μ h |
Answer» A. –μ j |
554. |
Find the gradient of t = x2y+ ez at the point p(1,5,-2) |
A. | i + 10j + 0.135k |
B. | 10i + j + 0.135k |
C. | i + 0.135j + 10k |
D. | 10i + 0.135j + k |
Answer» B. 10i + j + 0.135k |
555. |
+ z2 at (1,1,1) |
A. | i + j + k |
B. | 2i + 2j + 2k |
C. | 2xi + 2yj + 2zk |
D. | 4xi + 2yj + 4zk |
Answer» B. 2i + 2j + 2k |
556. |
i + 2xy j + 5xz2 k |
A. | √4.01 |
B. | √4.02 |
C. | √4.03 |
D. | √4.04 |
Answer» D. √4.04 |
557. |
,2,5) is (in Joule) |
A. | 0.64 |
B. | 0.72 |
C. | 0.78 |
D. | 0.80 |
Answer» B. 0.72 |
558. |
/x) j + 5 k. |
A. | -8.014 |
B. | -8.114 |
C. | -8.214 |
D. | -8.314 |
Answer» C. -8.214 |
559. |
πε) ln(b/a). State True/False. |
A. | true |
B. | false |
Answer» A. true |
560. |
i in spherical coordinates with r = 4m and θ = π/2. |
A. | 600 |
B. | 599.8 |
C. | 588.9 |
D. | 577.8 |
Answer» C. 588.9 |
561. |
and 1, y = 0 and 2, z = 0 and 3. |
A. | 10 |
B. | 12 |
C. | 14 |
D. | 16 |
Answer» B. 12 |
562. |
in volume integral. |
A. | 80 π |
B. | 5 π |
C. | 75 π |
D. | 85 π |
Answer» C. 75 π |
563. |
, hence find charge using volume integral. |
A. | 6100 π |
B. | 6200 π |
C. | 6300 π |
D. | 6400 π |
Answer» D. 6400 π |
564. |
j. |
A. | 20 |
B. | 70/3 |
C. | 80/3 |
D. | 30 |
Answer» C. 80/3 |
565. |
= 9. |
A. | 120π |
B. | 180π |
C. | 240π |
D. | 300π |
Answer» B. 180π |
566. |
5cm apart in transformer oil(εr=2.2) in 10-4 N, |
A. | 8.15 |
B. | 5.18 |
C. | 1.518 |
D. | 1.815 |
Answer» D. 1.815 |
567. |
5 X 10-7 C, both the charges are in vacuum. |
A. | 0.03 |
B. | 0.05 |
C. | 0.07 |
D. | 0.09 |
Answer» D. 0.09 |
568. |
cm in vacuum(in 10-8C) |
A. | 4 |
B. | 2 |
C. | 8 |
D. | 6 |
Answer» A. 4 |
569. |
cm and minimises as d increases. State True/False |
A. | true |
B. | false |
Answer» A. true |
570. |
Electric field of an infinitely long conductor of charge density λ, is given by E =λ/(2πεh).aN. State True/False |
A. | true |
B. | false |
Answer» A. true |
571. |
,1,1)m? |
A. | 10-6 |
B. | -10-6 |
C. | 106 |
D. | -106 |
Answer» B. -10-6 |
572. |
14 units? |
A. | 1 |
B. | 0.75 |
C. | 0.5 |
D. | 0.25 |
Answer» D. 0.25 |
573. |
Find the potential of V = 60sin θ/r2 at P(3,60,25) |
A. | 5.774 |
B. | 6.774 |
C. | 7.774 |
D. | 8.774 |
Answer» A. 5.774 |
574. |
,1,3). |
A. | 105 |
B. | 106 |
C. | 107 |
D. | 108 |
Answer» B. 106 |
575. |
What is the potential difference between 10sinθcosφ/r2 at A(1,30,20) and B(4,90,60)? |
A. | 2.386 |
B. | 3.386 |
C. | 4.386 |
D. | 5.386 |
Answer» C. 4.386 |
576. |
m from the ring. |
A. | 18π |
B. | 24π |
C. | 36π |
D. | 72π |
Answer» D. 72π |
577. |
at R = 4m and σ = -3 at R = 5m. Find the flux density at R = 1m. |
A. | 0 |
B. | 1 |
C. | 2 |
D. | 3 |
Answer» A. 0 |
578. |
at R = 4m and σ = -3 at R = 5m. Find the flux density at R = 3m. |
A. | 3 |
B. | 10/3 |
C. | 11/3 |
D. | 4 |
Answer» B. 10/3 |
579. |
at R = 4m and σ =-3 at R = 5m. Find the flux density at R = 4.5m. |
A. | 4/4.5 |
B. | 3/4.5 |
C. | 2/4.5 |
D. | 1/4.5 |
Answer» C. 2/4.5 |
580. |
at R = 4m and σ = -3 at R = 5m. Find the flux density at R = 6m. |
A. | 17/6 |
B. | -17/6 |
C. | 13/6 |
D. | -13/6 |
Answer» D. -13/6 |
581. |
Find the electric potential for an electric field 3units at a distance of 2m. |
A. | 9 |
B. | 4 |
C. | 6 |
D. | 3/2 |
Answer» C. 6 |
582. |
Find the potential at a point (4, 3, -6) for the function V = 2x2y + 5z. |
A. | 96 |
B. | 66 |
C. | 30 |
D. | -66 |
Answer» B. 66 |
583. |
-10 units) |
A. | 2.1 |
B. | 2.33 |
C. | 2.5 |
D. | 2.77 |
Answer» C. 2.5 |
584. |
Transform the vector A = 3i – 2j – 4k at P(2,3,3) to cylindrical coordinates |
A. | -3.6j – 4k |
B. | -3.6j + 4k |
C. | 3.6j – 4k |
D. | 3.6j + 4k |
Answer» A. -3.6j – 4k |
585. |
, -2) |
A. | 2.467i + j + 1.167k |
B. | 2.467i – j + 1.167k |
C. | 2.467i – j – 1.167k |
D. | 2.467i + j – 1.167k |
Answer» A. 2.467i + j + 1.167k |
586. |
Transform the vector (4,-2,-4) at (1,2,3) into spherical coordinates. |
A. | 3.197i – 2.393j + 4.472k |
B. | -3.197i + 2.393j – 4.472k |
C. | 3.197i + 2.393j + 4.472k |
D. | -3.197i – 2.393j – 4.472k |
Answer» B. -3.197i + 2.393j – 4.472k |
587. |
units. |
A. | 500 |
B. | 250 |
C. | 1000 |
D. | 2000 |
Answer» C. 1000 |
588. |
m/s. |
A. | 16.67 |
B. | 2400 |
C. | 2880 |
D. | 0.06 |
Answer» B. 2400 |
589. |
Find the mean free path of an electron travelling at a speed of 18m/s in 2 seconds. |
A. | 9 |
B. | 36 |
C. | 0.11 |
D. | 4.5 |
Answer» B. 36 |
590. |
units. |
A. | 200 |
B. | 50 |
C. | 400 |
D. | 0.02 |
Answer» A. 200 |
591. |
units and E = 8 units. |
A. | 1.77 |
B. | 2.25 |
C. | 36 |
D. | 144 |
Answer» C. 36 |
592. |
units. |
A. | 3 |
B. | 2 |
C. | 60 |
D. | 2.4 |
Answer» C. 60 |
593. |
Compute the refractive index when the dielectric constant is 256 in air. |
A. | 2562 |
B. | 16 |
C. | 256 |
D. | 64 |
Answer» B. 16 |
594. |
Find the permittivity of the surface when a wave incident at an angle 60 is reflected by the surface at 45 in air |
A. | 1.41 |
B. | 3.5 |
C. | 2.2 |
D. | 1.73 |
Answer» D. 1.73 |
595. |
Calculate the energy in the 4F capacitor. |
A. | 128kj |
B. | 1.28kj |
C. | 12.8kj |
D. | 1280j |
Answer» C. 12.8kj |
596. |
kV. |
A. | 350n |
B. | 0.035kn |
C. | 0.035n |
D. | 3.35kn |
Answer» C. 0.035n |
597. |
kV. Find „a‟. |
A. | 1m |
B. | 1cm |
C. | 10cm |
D. | 1mm |
Answer» D. 1mm |
598. |
kV. Find „a‟. |
A. | 10mm |
B. | 100mm |
C. | 1000m |
D. | 1000cm |
Answer» D. 1000cm |
599. |
The unit for dielectric strength is ____________ |
A. | v/m2 |
B. | mv/m2 |
C. | mv/m |
D. | vm |
Answer» C. mv/m |
600. |
m, calculate the dielectric strength. |
A. | 2mv/m |
B. | 4mv/m |
C. | 6mv/m |
D. | 8mv/m |
Answer» A. 2mv/m |
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