While using three moments equation, a fixed end of a continuous beam is replaced by an additional span of

Related MCQs

• A fixed beam of the uniform section is carrying a point load at the centre, if the moment of inertia of the middle half portion is reduced to half its previous value, then the fixed end moments will              
• There are two beams of equal length L and a load P is acting on centre of both beams. One of them is simply supported at both ends while the other one is fixed at both ends. Deflection of centre of simply supported beam will be                      times that of defection of centre of fixed beam.
• The three moments equation is applicable only when
• Consider the following statements: Sinking of an intermediate support of a continuous beam 1. Reduces the negative moment at support. 2. Increases the negative moment at support. 3. Reduces the positive moment at support. 4. Increases the positive moment at the centre of span. Of these statements
• When a uniformly distributed load, longer than the span of the girder, moves from left to right, then the maximum bending moment at mid section of span occurs when the uniformly distributed load occupies
• The fixed support in a real beam becomes in the conjugate beam a
• Carryover Moment at end B due to moment M applied at end A for the given non-prismatic beam is                  
• Bending moment at any section in a conjugate beam gives in the actual beam
• A simply supported beam deflects by 5 mm when it is subjected to a concentrated load of 10 kN at its centre. What will be deflection in a 1/10 model of the beam if the model is subjected to a 1 kN load at its centre?
• The maximum negative bending moment in fixed beam carrying udl occurs at