McqMate
| Q. |
A circular cavity resonator is filled with a dielectric of 2.08 and is operating at 5GHz of frequency. Then the wave number is: |
| A. | 181 |
| B. | 151 |
| C. | 161 |
| D. | 216 |
| Answer» B. 151 | |
| Explanation: wave number for a circular cavity resonator is given by the expression 2πf011√∈r/c. substituting the given values in the above expression; the wave number of the cavity resonator is 151. | |
View all MCQs in
Engineering PhysicsNo comments yet