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Q. |
A circular cavity resonator is filled with a dielectric of 2.08 and is operating at 5GHz of frequency. Then the wave number is: |
A. | 181 |
B. | 151 |
C. | 161 |
D. | 216 |
Answer» B. 151 | |
Explanation: wave number for a circular cavity resonator is given by the expression 2πf011√∈r/c. substituting the given values in the above expression; the wave number of the cavity resonator is 151. |
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