Q.

A circular cavity resonator is filled with a dielectric of 2.08 and is operating at 5GHz of frequency. Then the wave number is:

A. 181
B. 151
C. 161
D. 216
Answer» B. 151
Explanation: wave number for a circular cavity resonator is given by the expression 2πf011√∈r/c. substituting the given values in the above expression; the wave number of the cavity resonator is 151.
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