

McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Computer Science Engineering (CSE) .
201. |
Complement of F’ gives back |
A. | f’ |
B. | f |
C. | ff |
D. | ff’ |
Answer» B. f |
202. |
Decimal digit in BCD can be represented by |
A. | 1 input line |
B. | 2 input lines |
C. | 3 input lines |
D. | 4 input lines |
Answer» D. 4 input lines |
203. |
The number of logic gates and the way of their interconnections can be classified as |
A. | logical network |
B. | system network |
C. | circuit network |
D. | gate network |
Answer» A. logical network |
204. |
EPROM uses an array of |
A. | p-channel enhancement type mosfet |
B. | n-channel enhancement type mosfet |
C. | p-channel depletion type mosfet |
D. | n-channel depletion type mosfet |
Answer» B. n-channel enhancement type mosfet |
205. |
The EPROM was invented by |
A. | wen tsing chow |
B. | dov frohman |
C. | luis o brian |
D. | j p longwell |
Answer» B. dov frohman |
206. |
Address decoding for dynamic memory chip control may also be used for |
A. | chip selection and address location |
B. | read and write control |
C. | controlling refresh circuits |
D. | memory mapping |
Answer» A. chip selection and address location |
207. |
Which of the following describes the action of storing a bit of data in a mask ROM? |
A. | a 0 is stored by connecting the gate of a mos cell to the address line |
B. | a 0 is stored in a bipolar cell by shorting the base connection to the address line |
C. | a 1 is stored by connecting the gate of a mos cell to the address line |
D. | a 1 is stored in a bipolar cell by opening the base connection to the address line |
Answer» C. a 1 is stored by connecting the gate of a mos cell to the address line |
208. |
The check sum method of testing a ROM |
A. | allows data errors to be pinpointed to a specific memory location |
B. | provides a means for locating and correcting data errors in specific memory locations |
C. | indicates if the data in more than one memory location is incorrect |
D. | simply indicates that the contents of the rom are incorrect |
Answer» D. simply indicates that the contents of the rom are incorrect |
209. |
The initial values in all the cells of an EPROM is |
A. | 0 |
B. | 1 |
C. | both 0 and 1 |
D. | alternate 0s and 1s |
Answer» B. 1 |
210. |
To store 0 in such a cell, the floating point must be |
A. | reprogrammed |
B. | restarted |
C. | charged |
D. | power off |
Answer» C. charged |
211. |
The major disadvantage of RAM is? |
A. | its access speed is too slow |
B. | its matrix size is too big |
C. | it is volatile |
D. | high power consumption |
Answer» C. it is volatile |
212. |
Which one of the following is used for the fabrication of MOS EPROM? |
A. | tms 2513 |
B. | tms 2515 |
C. | tms 2516 |
D. | tms 2518 |
Answer» C. tms 2516 |
213. |
How many addresses a MOS EPROM have? |
A. | 1024 |
B. | 512 |
C. | 2516 |
D. | 256 |
Answer» C. 2516 |
214. |
ROMs retain data when |
A. | power is on |
B. | power is off |
C. | system is down |
D. | all of the mentioned |
Answer» D. all of the mentioned |
215. |
When a RAM module passes the checker board test it is |
A. | able to read and write only 0s |
B. | faulty |
C. | probably good |
D. | able to read and write only 1s |
Answer» C. probably good |
216. |
What is the difference between static RAM and dynamic RAM? |
A. | static ram must be refreshed, dynamic ram does not |
B. | there is no difference |
C. | dynamic ram must be refreshed, static ram does not |
D. | sram is slower than dram |
Answer» C. dynamic ram must be refreshed, static ram does not |
217. |
How many natural states will there be in a 4-bit ripple counter? |
A. | 4 |
B. | 8 |
C. | 16 |
D. | 32 |
Answer» C. 16 |
218. |
A ripple counter’s speed is limited by the propagation delay of |
A. | each flip-flop |
B. | all flip-flops and gates |
C. | the flip-flops only with gates |
D. | only circuit gates |
Answer» A. each flip-flop |
219. |
One of the major drawbacks to the use of asynchronous counters is that |
A. | low-frequency applications are limited because of internal propagation delays |
B. | high-frequency applications are limited because of internal propagation delays |
C. | asynchronous counters do not have major drawbacks and are suitable for use in high- and low-frequency counting applications |
D. | asynchronous counters do not have propagation delays, which limits their use in high- frequency applications |
Answer» B. high-frequency applications are limited because of internal propagation delays |
220. |
Internal propagation delay of asynchronous counter is removed by |
A. | ripple counter |
B. | ring counter |
C. | modulus counter |
D. | synchronous counter |
Answer» D. synchronous counter |
221. |
How many flip-flops are required to construct a decade counter? |
A. | 4 |
B. | 8 |
C. | 5 |
D. | 10 |
Answer» A. 4 |
222. |
The terminal count of a typical modulus-10 binary counter is |
A. | 0000 |
B. | 1010 |
C. | 1001 |
D. | 1111 |
Answer» C. 1001 |
223. |
A ripple counter’s speed is limited by the propagation delay of |
A. | each flip-flop |
B. | all flip-flops and gates |
C. | the flip-flops only with gates |
D. | only circuit gates |
Answer» A. each flip-flop |
224. |
A 4-bit counter has a maximum modulus of |
A. | 3 |
B. | 6 |
C. | 8 |
D. | 16 |
Answer» D. 16 |
225. |
UP-DOWN counter is a combination of |
A. | latches |
B. | flip-flops |
C. | up counter |
D. | up counter & down counter |
Answer» D. up counter & down counter |
226. |
UP-DOWN counter is also known as |
A. | dual counter |
B. | multi counter |
C. | multimode counter |
D. | two counter |
Answer» C. multimode counter |
227. |
In an UP-counter, each flip-flop is triggered by |
A. | the output of the next flip-flop |
B. | the normal output of the preceding flip-flop |
C. | the clock pulse of the previous flip-flop |
D. | the inverted output of the preceding flip-flop |
Answer» B. the normal output of the preceding flip-flop |
228. |
In DOWN-counter, each flip-flop is triggered by |
A. | the output of the next flip-flop |
B. | the normal output of the preceding flip-flop |
C. | the clock pulse of the previous flip-flop |
D. | the inverted output of the preceding flip-flop |
Answer» D. the inverted output of the preceding flip-flop |
229. |
Binary counter that count incrementally and decrement is called |
A. | up-down counter |
B. | lsi counters |
C. | down counter |
D. | up counter |
Answer» A. up-down counter |
230. |
Once an up-/down-counter begins its count sequence, it |
A. | starts counting |
B. | can be reversed |
C. | can’t be reversed |
D. | can be altered |
Answer» D. can be altered |
231. |
In 4-bit up-down counter, how many flip-flops are required? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» C. 4 |
232. |
A modulus-10 counter must have _ |
A. | 10 flip-flops |
B. | 4 flip-flops |
C. | 2 flip-flops |
D. | synchronous clocking |
Answer» B. 4 flip-flops |
233. |
Which is not an example of a truncated modulus? |
A. | 8 |
B. | 9 |
C. | 11 |
D. | 15 |
Answer» A. 8 |
234. |
The designation means that the |
A. | up count is active-high, the down count is active-low |
B. | up count is active-low, the down count is active-high |
C. | up and down counts are both active-low |
D. | up and down counts are both active-high |
Answer» A. up count is active-high, the down count is active-low |
235. |
The full form of SIPO is |
A. | serial-in parallel-out |
B. | parallel-in serial-out |
C. | serial-in serial-out |
D. | serial-in peripheral-out |
Answer» A. serial-in parallel-out |
236. |
How can parallel data be taken out of a shift register simultaneously? |
A. | use the q output of the first ff |
B. | use the q output of the last ff |
C. | tie all of the q outputs together |
D. | use the q output of each ff |
Answer» D. use the q output of each ff |
237. |
What is meant by parallel load of a shift register? |
A. | all ffs are preset with data |
B. | each ff is loaded with data, one at a time |
C. | parallel shifting of data |
D. | all ffs are set with data |
Answer» A. all ffs are preset with data |
238. |
After three clock pulses, the register contains |
A. | 01110 |
B. | 00001 |
C. | 00101 |
D. | 00110 |
Answer» C. 00101 |
239. |
What will be the 4-bit pattern after the second clock pulse? (Right-most bit first) |
A. | 1100 |
B. | 0011 |
C. | 0000 |
D. | 1111 |
Answer» C. 0000 |
240. |
In digital logic, a counter is a device which |
A. | counts the number of outputs |
B. | stores the number of times a particular event or process has occurred |
C. | stores the number of times a clock pulse rises and falls |
D. | counts the number of inputs |
Answer» B. stores the number of times a particular event or process has occurred |
241. |
A counter circuit is usually constructed of |
A. | a number of latches connected in cascade form |
B. | a number of nand gates connected in cascade form |
C. | a number of flip-flops connected in cascade |
D. | a number of nor gates connected in cascade form |
Answer» C. a number of flip-flops connected in cascade |
242. |
How many types of the counter are there? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» B. 3 |
243. |
A decimal counter has states. |
A. | 5 |
B. | 10 |
C. | 15 |
D. | 20 |
Answer» B. 10 |
244. |
Ripple counters are also called |
A. | ssi counters |
B. | asynchronous counters |
C. | synchronous counters |
D. | vlsi counters |
Answer» B. asynchronous counters |
245. |
Synchronous counter is a type of |
A. | ssi counters |
B. | lsi counters |
C. | msi counters |
D. | vlsi counters |
Answer» C. msi counters |
246. |
Three decade counter would have |
A. | 2 bcd counters |
B. | 3 bcd counters |
C. | 4 bcd counters |
D. | 5 bcd counters |
Answer» B. 3 bcd counters |
247. |
BCD counter is also known as |
A. | parallel counter |
B. | decade counter |
C. | synchronous counter |
D. | vlsi counter |
Answer» B. decade counter |
248. |
The parallel outputs of a counter circuit represent the |
A. | parallel data word |
B. | clock frequency |
C. | counter modulus |
D. | clock count |
Answer» D. clock count |
249. |
The time from the beginning of a read cycle to the end of tACS/tAA is called as |
A. | write enable time |
B. | data hold |
C. | read cycle time |
D. | access time |
Answer» D. access time |
250. |
Why did PROM introduced? |
A. | to increase the storage capacity |
B. | to increase the address locations |
C. | to provide flexibility |
D. | to reduce the size |
Answer» C. to provide flexibility |
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