McqMate
| 101. |
The 4th quadrant is in which position? |
| A. | below h.p, behind v.p |
| B. | above h.p, behind v.p |
| C. | above h.p, in-front of v.p |
| D. | below h.p, in-front of v.p |
| Answer» D. below h.p, in-front of v.p | |
| Explanation: the position of reference planes will be similar to quadrants in x, y plane co-ordinate system. as the 4th quadrant lies below the x-axis and in front of the y-axis here also the 4th quadrant is below h.p, in front of v.p. | |
| 102. |
The 1st quadrant is in which position? |
| A. | below h.p, behind v.p |
| B. | above h.p, behind v.p |
| C. | above h.p, in-front of v.p |
| D. | below h.p, in-front of v.p |
| Answer» C. above h.p, in-front of v.p | |
| Explanation: the position of reference planes will be similar to quadrants in x, y | |
| 103. |
The position of the views with respect to the reference line will not change according to the quadrant in which the object may be situated. |
| A. | true |
| B. | false |
| Answer» B. false | |
| Explanation: the position of the views with respect to the reference line will change according to the quadrant in which the object may be situated because the representation of views will on 2 dimensional sheet for that the planes has to rotate and with respective to reference line and this will be different for different quadrant. | |
| 104. |
The first and the third quadrants are always opened out while rotating the planes. |
| A. | true |
| B. | false |
| Answer» A. true | |
| Explanation: according to the standards it is made that the planes rotate in a clockwise direction while drawing the orthographic projections of objects on the different quadrant. so as the horizontal rotates 90 degrees in clockwise with respect to reference line the views in 2nd and 4th quadrants overlap but in 1st and 3rd the views will not coincide so they are said to be opened. | |
| 105. |
An object is kept in one of the quadrants of principal planes of projection, for both the front view and top view of the object, the view came first and then the object (the observer is at the top right side of principal planes). The object is in which quadrant? |
| A. | 1st quadrant |
| B. | 2nd quadrant |
| C. | 3rd quadrant |
| D. | 4th quadrant |
| Answer» C. 3rd quadrant | |
| Explanation: if we imagine the principal planes and the observer at the top right side of those planes we can clearly watch the positions of object with respect to their view. here the object is in 3rd quadrant so view will come first. | |
| 106. |
An object is kept in one of the quadrants of principal planes of projection, for both the front view and top view of the object the object came first and then the views on planes (the observer is at top right side of principal planes). The object is in which quadrant? |
| A. | 1st quadrant |
| B. | 2nd quadrant |
| C. | 3rd quadrant |
| D. | 4th quadrant |
| Answer» A. 1st quadrant | |
| Explanation: if we imagine the principal planes and the observer at top right side of those planes we can clearly watch the positions of object with respect to their view. here the object is in 1st quadrant so object will come first in both the views. | |
| 107. |
An object is kept in one of the quadrants of principal planes of projection, for the front view the view is first and object is next and for top view the object came first and then the view on plane (the observer is at top right side of principal planes). The object is in which quadrant? |
| A. | 1st quadrant |
| B. | 2nd quadrant |
| C. | 3rd quadrant |
| D. | 4th quadrant |
| Answer» B. 2nd quadrant | |
| Explanation: if we imagine the principal planes and the observer at top right side of those planes we can clearly watch the positions of object with respect to their view. here the object is in 2nd quadrant so view will come first for front view and object will come first for top view. | |
| 108. |
The line formed by intersection of principal planes is called |
| A. | projection line |
| B. | origin line |
| C. | line of intersection |
| D. | reference line |
| Answer» D. reference line | |
| Explanation: the line formed by an intersection of principal planes or reference planes of projection that is the vertical plane or frontal plane and horizontal plane is called reference line which is denoted by the letters xy. | |
| 109. |
The vertical plane is also called |
| A. | straight plane |
| B. | perpendicular plane |
| C. | frontal plane |
| D. | pole plane |
| Answer» C. frontal plane | |
| Explanation: vertical plane will be vertical to ground and perpendicular with horizontal plane. as the observer will always be at right- top side of planes of projections the front view will always be placed on vertical plane only so the vertical plane is also called frontal plane. | |
| 110. |
The negative horizontal plane and positive horizontal makes angle with each other. |
| A. | 90 degrees |
| B. | 180 degrees |
| C. | 120 degrees |
| D. | 270 degrees |
| Answer» B. 180 degrees | |
| Explanation: the negative horizontal plane means the part of horizontal plane which lies in 2nd quadrant. the positive and negative planes are parallel to each other so the angle between the parallel planes is always 180 degrees. | |
| 111. |
The positive vertical plane and positive horizontal plane makes angle with each other in anti clockwise direction. |
| A. | 180 degrees |
| B. | 270 degrees |
| C. | 0 degrees |
| D. | 90 degrees |
| Answer» B. 270 degrees | |
| Explanation: given the direction is anti- clockwise direction so the angle in 270 degrees if it is given clockwise direction the angle should be 90 degrees since the given planes are consecutive planes in planes of projection. | |
| 112. |
In 1st angle projection the object is kept in |
| A. | 1st quadrant |
| B. | 2nd quadrant |
| C. | 3rd quadrant |
| D. | 4th quadrant |
| Answer» A. 1st quadrant | |
| Explanation: we can keep an object in any quadrant of projection planes but every time we keep in different quadrants gives different relative positions in projections. here 1st angle represents the initial stage in forming projection of planes so 1st quadrant represents 1st angle projection. | |
| 113. |
1st angle projection is recommended by |
| A. | usa |
| B. | isi |
| C. | bureau of indian standards |
| D. | asme |
| Answer» C. bureau of indian standards | |
| Explanation: first angle projection is recommended by bureau of indian standards but usa and other countries recommend third angle projection. the changes in both | |
| 114. |
In 1st angle projection the lies between and |
| A. | object, projection plane, observer |
| B. | projection plane, object, observer |
| C. | reference line, side view, front view |
| D. | reference line, left side view, right side view |
| Answer» A. object, projection plane, observer | |
| Explanation: the observer is always at the right side top end. so as the observer watches the object comes first and then the projection plane as the object in the 1st quadrant in 1st angle projection. so object lies between projection plane and observer. | |
| 115. |
In 1st angle projection, the front view will be below the top view. |
| A. | true |
| B. | false |
| Answer» B. false | |
| Explanation: as the object is in first quadrant and the front view projects on vertical plane and top view projects on horizontal plane. and for representing the projection the horizontal plane has to turn 90 degrees in clockwise direction. the top view will be below the front view. | |
| 116. |
In 1st angle projection the positions of front and top views are |
| A. | top view lies above the front view |
| B. | front view lies above the top view |
| C. | front view lie left side to top view |
| D. | top view lie left side to front view |
| Answer» B. front view lies above the top view | |
| Explanation: as the object is in first quadrant and the front view projects on vertical plane and top view projects on horizontal plane. and for representing the projection the horizontal plane has to turn 90 degrees in clockwise direction. | |
| 117. |
In 1st angle projection, the left side view will be left side of front view. |
| A. | true |
| B. | false |
| Answer» B. false | |
| Explanation: in first angle projection the object’s left side will be projected only if we watch from left side of object and the impression will fall to the right side of front view similar to the other side also so the left side view is placed on the right side of front view. | |
| 118. |
The positions of right side view and front view of an object kept in 1st quadrant and projection are drawn? |
| A. | right side view is right side of front view |
| B. | right side view is left side of front view |
| C. | right side view is above the front view |
| D. | right side view is below the front view |
| Answer» B. right side view is left side of front view | |
| Explanation: in first angle projection the object’s right side will be projected only if we watch from right side of object and the impression will fall to the left side of front view similar to the other side also so the right side view is placed on the left side of front view. | |
| 119. |
The positions of reference line and top view in 1st angle projection are |
| A. | reference line lies above the top view |
| B. | reference line lies below the top view |
| C. | reference line lie left side to top view |
| D. | reference line lie right side to top view |
| Answer» A. reference line lies above the top view | |
| Explanation: reference line will be the xy line which is formed by intersection of vertical plane and horizontal plane. in the first angle projection the projections of object is taken by placing object in 1st quadrant and top view is projected on to horizontal plane which is after the reference line. | |
| 120. |
If an object is placed in 1st quadrant such that one of the surfaces of object is coinciding with vertical plane, what is the correct position of views from the following? |
| A. | the front view touches the reference line |
| B. | the side view touches the reference line |
| C. | the top view touches the reference line |
| D. | the bottom view touches the reference line |
| Answer» C. the top view touches the reference line | |
| Explanation: in the first angle projection the projections of object is taken by placing object in 1st quadrant. if the object’s surface is coinciding the vertical plane which indirectly saying the distance from vertical plane is zero so top view of that object touches the reference line. | |
| 121. |
If an object is placed in 1st quadrant such that one of the surfaces of object is coinciding with horizontal plane, what is the correct position of views from the following? |
| A. | the front view touches the reference line |
| B. | the side view touches the reference line |
| C. | the top view touches the reference line |
| D. | the bottom view touches the reference line |
| Answer» A. the front view touches the reference line | |
| Explanation: in the first angle projection the projections of object is taken by placing object in 1st quadrant. if the object’s surface is coinciding the horizontal plane which indirectly saying the distance from horizontal plane is zero so front view of that object touches the reference line. | |
| 122. |
If an object is placed in 1st quadrant such that one of the surfaces of object is coinciding with both vertical plane and horizontal plane, what is the correct position of views from the following? |
| A. | the top view touches the reference line |
| B. | the top view and side view touch each other |
| C. | both side views touch each other |
| D. | the top view and front touches each other at reference line |
| Answer» D. the top view and front touches each other at reference line | |
| Explanation: if the object is placed in 1st quadrant and the object’s surface is coinciding with both the horizontal plane and vertical plane which indirectly saying the distance from both the planes is zero so both top and front views of that object touches the reference line. | |
| 123. |
Where is the position of bottom view in 1st angle projection? |
| A. | left side of right hand side view |
| B. | right side of right hand side view |
| C. | above the front view |
| D. | below the top view |
| Answer» C. above the front view | |
| Explanation: first angle projection means the object is placed in first quadrant and the top view of the object is below the front view so the bottom view is above the front view. | |
| 124. |
Where is the position of back view in 1st angle projection? |
| A. | left side of right hand side view |
| B. | right side of right hand side view |
| C. | above the front view |
| D. | below the top view |
| Answer» B. right side of right hand side view | |
| Explanation: in the first angle projection the top view of the object is below the front view and then come the side views to the left and right of front view and then back view which can either be kept on ends of side views but as standard notation it is placed on right side of right side view. | |
| 125. |
In 3rd angle projection the object is kept in |
| A. | 1st quadrant |
| B. | 2nd quadrant |
| C. | 3rd quadrant |
| D. | 4th quadrant |
| Answer» C. 3rd quadrant | |
| Explanation: we can keep object in any quadrant of projection planes but every time we keep in different quadrants gives different relative positions in projections. here 3rd angle represents the initial stage in forming projection of planes so 3rd quadrant represents 3rd angle projection. | |
| 126. |
3rd angle projection is recommended by |
| A. | usa |
| B. | isi |
| C. | bureau of indian standards |
| D. | is |
| Answer» A. usa | |
| Explanation: third angle projection is recommended by usa and other countries and 1st angle projection is recommended by bureau of indian standards. the changes in both the projections are relative positions in projection. | |
| 127. |
In 3rd angle projection the lies between and |
| A. | object, projection plane, observer |
| B. | projection plane, object, observer |
| C. | reference line, side view, front view |
| D. | reference line, left side view, right side view |
| Answer» B. projection plane, object, observer | |
| Explanation: the observer is always at the right side top end. so as the observer watches the projection plane comes first and then the object as the object in the 3rd quadrant in 3rd angle projection, so plane of projection lies between object and observer. | |
| 128. |
In 3rd angle projection, the front view will be below the top view. |
| A. | true |
| B. | false |
| C. | topic 2.4 third angle projection method |
| Answer» A. true | |
| Explanation: as the object is in third quadrant and the front view projects on a vertical plane and top view projects on horizontal plane. and for representing the projection the horizontal plane has to turn 90 degrees in clockwise direction. the top view will be above the front view. | |
| 129. |
In 3rd angle projection, the positions of front view and top views are? |
| A. | top view lies above the front view |
| B. | front view lies above the top view |
| C. | front view lie left side to top view |
| D. | top view lie left side to front view |
| Answer» A. top view lies above the front view | |
| Explanation: as the object is in third quadrant and the front view projects on a vertical plane and top view projects on horizontal plane. and for representing the projection the horizontal plane has to turn 90 degrees in clockwise direction. | |
| 130. |
In 3rd angle projection, the left side view will be left side of front view. |
| A. | true |
| B. | false |
| Answer» A. true | |
| Explanation: in third angle projection the object’s left side will be projected only if we watch from right side of the object so impression will fall to the left side of front view since the plane of projection is back side of object and also the right side view is placed on the right side of front view. | |
| 131. |
The positions of right side view and front view of an object kept in 3rd quadrant and projection are drawn? |
| A. | right side view is right side of front view |
| B. | right side view is left side of front view |
| C. | right side view is above the front view |
| D. | right side view is below the front view |
| Answer» A. right side view is right side of front view | |
| Explanation: in third angle projection the | |
| 132. |
The positions of reference line and top view in 3rd angle projection are? |
| A. | reference line lies above the top view |
| B. | reference line lies below the top view |
| C. | reference line lie left side to top view |
| D. | reference line lie right side to top view |
| Answer» B. reference line lies below the top view | |
| Explanation: reference line will be the xy line which is formed by an intersection of vertical plane and horizontal plane. in the third angle projection the projections of object are taken by placing object in 3rd quadrant and top view is projected on to horizontal plane which is above the reference line. | |
| 133. |
If an object is placed in 3rd quadrant such that one of the surfaces of object is coinciding with vertical plane, what is the correct position of views from the following? |
| A. | the front view touches the reference line |
| B. | the side view touches the reference line |
| C. | the top view touches the reference line |
| D. | the bottom view touches the reference line |
| Answer» C. the top view touches the reference line | |
| Explanation: in the third angle projection the projections of object is taken by placing object in 3rd quadrant. if the object’s surface is coinciding the vertical plane which indirectly saying the distance from vertical plane is zero so top view of that object touches the reference line. | |
| 134. |
If an object is placed in 3rd quadrant such that one of the surfaces of object is coinciding with horizontal plane, what is the correct position of views from the following? |
| A. | the front view touches the reference line |
| B. | the side view touches the reference line |
| C. | the top view touches the reference line |
| D. | the bottom view touches the reference line |
| Answer» A. the front view touches the reference line | |
| Explanation: in the third angle projection the projections of object is taken by placing object in 3rd quadrant. if the object’s surface is coinciding the horizontal plane which indirectly saying the distance from horizontal plane is zero so front view of that object touches the reference line. | |
| 135. |
If an object is placed in 3rd quadrant such that one of the surfaces of object is coinciding with both vertical plane and horizontal plane, what is the correct position of views from the following? |
| A. | the top view touches the reference line |
| B. | the top view and side view touch each other |
| C. | both side views touch each other |
| D. | the top view and front touches each other at reference line |
| Answer» D. the top view and front touches each other at reference line | |
| Explanation: if the object is placed in 3rd quadrant and the object’s surface is coinciding with both the horizontal plane and vertical plane which indirectly saying the distance from both the planes is zero so both top and front views of that object touches the reference line. | |
| 136. |
Where is the position of bottom view in 3rd angle projection? |
| A. | left side of right hand side view |
| B. | right side of right hand side view |
| C. | above the front view |
| D. | below the top view |
| Answer» D. below the top view | |
| Explanation: third angle projection means the object is placed in third quadrant and the top view of the object is above the front view so the bottom view is below the front view. | |
| 137. |
Where is the position of back view in 3rd angle projection? |
| A. | left side of right hand side view |
| B. | right side of right hand side view |
| C. | above the front view |
| D. | below the top view |
| Answer» B. right side of right hand side view | |
| Explanation: in the third angle projection the top view of the object is above the front view and then come the side views to the left and right of front view and then back view which can either be kept on ends of side views but as standard notation it is placed on right side of right side view. | |
| 138. |
A regular cone is rested on base on horizontal plane the front view will be |
| A. | circle |
| B. | scalene triangle |
| C. | equilateral triangle |
| D. | isosceles triangle |
| Answer» D. isosceles triangle | |
| Explanation: given the cone is regular cone that means the tip of cone will be at center if viewed from top, so for such a cone the front view will be a triangle and in particular isosceles triangle and the top view will be circle. | |
| 139. |
A Cube is placed on horizontal plane such that one of the space diagonal is perpendicular to horizontal plane the top view will be |
| A. | octagon |
| B. | square |
| C. | hexagon |
| D. | rectangle |
| Answer» C. hexagon | |
| Explanation: a cube is a 3 dimensional object whose length, width and thickness will | |
| 140. |
A cylinder’s axis is perpendicular to profile plane the top view will be |
| A. | circle |
| B. | cylinder |
| C. | rectangle |
| D. | parallelogram |
| Answer» C. rectangle | |
| Explanation: given a cylinder whose axis is perpendicular to a profile plane so the top view and front view will be rectangle and side view will be circle. if the cylinder is slightly tilted with respect to profile then top view and front view will be parallelogram. | |
| 141. |
An egg is placed vertical to horizontal plane the top view will be |
| A. | ellipse |
| B. | circle |
| C. | oval |
| D. | sphere |
| Answer» B. circle | |
| Explanation: given the egg is placed vertical to horizontal plane the front view and side view will be same and it might be conical, oval or elliptical etc. the top view always be circle. that’s why the egg boxes are made impression of semi spheres. | |
| 142. |
A Cardboard is made to cut in shape of ‘A’ and as we placed in projection planes and from top view the legs of cardboard touch the profile plane and cardboard is parallel to horizontal plane. Which of the following is wrong? |
| A. | the front view gives thickness of cardboard |
| B. | the side views give width of cardboard |
| C. | the front view gives height of cardboard |
| D. | the top view gives thickness of cardboard |
| Answer» D. the top view gives thickness of cardboard | |
| Explanation: from given information, we can understand that the cardboard is parallel to horizontal plane and direction of ‘a’ placed in projection planes so the front view and side view gives thickness, the front view and top view gives a height of cardboard and side view and top view gives width of cardboard. | |
| 143. |
An object is placed in between projection planes, the front view and side view gives the same rectangle and top view is giving square the object is |
| A. | a square cylinder, such that square base is parallel to horizontal plane |
| B. | a square cylinder, such that square base is parallel to vertical plane |
| C. | a square cylinder, such that square base is parallel to profile plane |
| D. | a square cylinder, such that axis is parallel to horizontal |
| Answer» A. a square cylinder, such that square base is parallel to horizontal plane | |
| Explanation: given that the object is viewing from front and side as rectangle and top view is square so we can understand that pyramid has height more than the side of square and accordingly the view the object can be cuboid (square cylinder). | |
| 144. |
A plate of a negligible thickness of circular shape is placed parallel to horizontal plane the front view will be |
| A. | line |
| B. | circle |
| C. | rectangle |
| D. | ellipse |
| Answer» A. line | |
| Explanation: given a plate which is in circular shape given plate is parallel to horizontal plane so the front view and side views will be line whose length is equal to diameter of circle as the thickness is negligible the front view, side view can’t be rectangle and top view will be circle. | |
| 145. |
A regular tetrahedron is placed on horizontal plane on one of its base, the front view, top view and side view gives triangle. |
| A. | true |
| B. | false |
| Answer» A. true | |
| Explanation: a regular tetrahedron is formed by enclosing 4 equal triangles. and given one of the base is parallel to horizontal so in what angle the tetrahedron might be turned the front view and side view will be a triangle. | |
| 146. |
A regular cone is placed on horizontal plane on its base the top view is |
| A. | circle |
| B. | rectangle |
| C. | square |
| D. | triangle |
| Answer» A. circle | |
| Explanation: a regular cone generally will have a base circle and constant difference in cross-section. when a cone placed on horizontal that is base is parallel to horizontal plane then the front view and side views will show triangle for both and top view will shows circle. | |
| 147. |
The views will change if we keep the object in different quadrants. |
| A. | true |
| B. | false |
| Answer» B. false | |
| Explanation: whenever we change the object from one quadrant to other quadrants the relative positions of projection drawn will change accordingly but the views of the object will not change. | |
| 148. |
A Square pyramid is resting on vertical plane with base parallel to vertical plane. The side view will be |
| A. | triangle |
| B. | polygon with 4 sides |
| C. | square |
| D. | polygon with 5 sides |
| Answer» A. triangle | |
| Explanation: a square pyramid have base of square which is resting on vertical plane as said above so the side views, top view and bottom view gives the triangle and front view and back view gives square. | |
| 149. |
A triangular prism is placed in projection plane such that the square surface is parallel to horizontal plane. The top view, front view will be |
| A. | square, rectangle respectively |
| B. | rectangle, triangle respectively |
| C. | rectangle, rectangle respectively |
| D. | triangle, rectangle respectively |
| Answer» C. rectangle, rectangle respectively | |
| Explanation: given a triangular prism is placed in projection plane such that the square base is parallel to horizontal plane. a triangular prism is nothing but triangular cylinder as per position given the front view and top view will be rectangle and side view will be triangle. | |
| 150. |
A pentagonal prism is placed the axis is perpendicular to horizontal plane, the top view and front view are |
| A. | pentagon, rectangle |
| B. | rectangle, rectangle |
| C. | pentagon, triangle |
| D. | rectangle, triangle |
| Answer» A. pentagon, rectangle | |
| Explanation: given a pentagonal prism is placed in projection plane such that the axis is perpendicular to horizontal plane. a pentagonal prism is nothing but pentagonal cylinder as per position given the front view and side view will be rectangle and top view will be pentagon. | |
| 151. |
A hexagonal nut is placed on a horizontal plane such that the axis is perpendicular to profile plane. The top view and side view will be |
| A. | rectangle, hexagon |
| B. | hexagon, rectangle |
| C. | rectangle, rectangle |
| D. | rectangle, circle |
| Answer» A. rectangle, hexagon | |
| Explanation: given a hexagonal nut is placed on horizontal plane such that the axis is perpendicular to profile plane. as per position given the front view, back view, top view and bottom view will be rectangle and side view will be hexagon. | |
| 152. |
Two points are placed in 1st quadrant of projection planes such that the line joining the points is perpendicular to profile plane the side view and top view will be |
| A. | single point, two points |
| B. | two points, single point |
| C. | single point, single point |
| D. | two points, two points |
| Answer» A. single point, two points | |
| Explanation: here given the two points such that the joining line is perpendicular to profile | |
| 153. |
A point is 5 units away from the vertical plane and 4 units away from profile plane and 3 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the front view and top view of point is |
| A. | 7 units |
| B. | 8 units |
| C. | 9 units |
| D. | 5 units |
| Answer» B. 8 units | |
| Explanation: since the point is 3 units away from the horizontal plane the distance from the point to xy reference line will be 3 units. and then the point is at a distance of 5 units from the vertical plane the distance from reference line and point will be 5, sum is 8. | |
| 154. |
A point is 8 units away from the vertical plane and 2 units away from profile plane and 4 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the side view and front view of point is |
| A. | 12 units |
| B. | 6 units |
| C. | 10 units |
| D. | 8 units |
| Answer» C. 10 units | |
| Explanation: since the point is 2 units away from the profile plane the distance from the point to reference line will be 2 units. and then the point is at a distance of 8 units from the vertical plane the distance from reference line and point will be 8, sum is 10. | |
| 155. |
A point is 20 units away from the vertical plane and 12 units away from profile plane and 9 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the side view and front view of point is |
| A. | 29 units |
| B. | 21 units |
| C. | 32 units |
| D. | 11 units |
| Answer» C. 32 units | |
| Explanation: since the point is 12 units away from the profile plane the distance from the point to reference line will be 12 units. and then the point is at a distance of 20 units from profile plane the distance from reference line and point will be 20 units, sum is 32. | |
| 156. |
A point is 2 units away from the vertical plane and 3 units away from profile plane and 7 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the shortest distance from top view and side view of point is |
| A. | 10.29 |
| B. | 5.14 |
| C. | 9 |
| D. | 7 |
| Answer» C. 9 | |
| Explanation: since here distance from side view and top view is asked for that we need the distance between the front view and side | |
| 157. |
If a point P is placed in between the projection planes. The distance from side view to reference line towards front view and the distance between top view and reference line towards top view will be same. |
| A. | true |
| B. | false |
| Answer» A. true | |
| Explanation: the projection will be drawn by turning the other planes parallel to a vertical plane in clockwise direction along the lines of intersecting of planes. and so as we fold again the planes at respective reference lines and then drawing perpendiculars to the planes at those points the point of intersection gives the point p. | |
| 158. |
A point is 20 units away from the vertical plane and 12 units away from profile plane and 9 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the side view and top view of point is |
| A. | 29 units |
| B. | 21 units |
| C. | 35.8 units |
| D. | 17.9 units |
| Answer» C. 35.8 units | |
| Explanation: since here distance from side view and top view is asked for that we need the distance between the front view and side view (12+9); front view and top view (9+20)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √(212+292 ) = 35.80 units. | |
| 159. |
A point is 15 units away from the vertical plane and 12 units away from profile plane and horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the front view and top view of point is |
| A. | 27 |
| B. | 15 |
| C. | 12 |
| D. | 24 |
| Answer» A. 27 | |
| Explanation: since the point is 12 units away from the horizontal plane the distance from the point to xy reference line will be 12 units. and then the point is at a distance of 15 units from the vertical plane the distance from reference line and point will be 15, sum is 27. | |
| 160. |
A point is 12 units away from the vertical plane and profile plane 15 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the front view and side view of point is |
| A. | 27 |
| B. | 15 |
| C. | 12 |
| D. | 24 |
| Answer» D. 24 | |
| Explanation: since the point is 12 units away from the profile plane the distance from the point to xy reference line will be 12 units. | |
| 161. |
A point is 7 units away from the vertical plane and horizontal plane 9 units away from profile plane in 1st quadrant then the projections are drawn on paper the distance between the front view and top view of point is |
| A. | 27 |
| B. | 15 |
| C. | 16 |
| D. | 14 |
| Answer» D. 14 | |
| Explanation: since the point is 7 units away from the horizontal plane the distance from the point to xy reference line will be 7 units. and then the point is at a distance of 7 units from the vertical plane the distance from reference line and point will be 7, sum is 14 units. | |
| 162. |
A point is 16 units away from the vertical plane and horizontal plane 4 units away from profile plane in 1st quadrant then the projections are drawn on paper the distance between the side view and top view of point is |
| A. | 37.73 units |
| B. | 32.98 units |
| C. | 16 |
| D. | 8 |
| Answer» D. 8 | |
| Explanation: since here distance from side view and top view is asked for that we need the distance between the front view and side view (4+16); front view and top view (16+16)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √202+322 ) = 37.73 units. | |
| 163. |
A point is in 2nd quadrant 20 units away from the horizontal plane and 10 units away from the vertical plane. Orthographic projection is drawn. What is the distance from point of front view to reference line, top view point to reference line? |
| A. | 20, 10 |
| B. | 10, 20 |
| C. | 0, 20 |
| D. | 10, 0 |
| Answer» A. 20, 10 | |
| Explanation: given object is point placed in 2nd quadrant the top view gives the distance from vertical plane (10) and front view gives the distance from horizontal plane (20) both are placed overlapped in orthographic projection since the object is placed in the 2nd quadrant. | |
| 164. |
A point is in 2nd quadrant 15 units away from the vertical plane and 10 units away from the horizontal plane. Orthographic projection is drawn. What is the distance from point of front view to reference line, top view point to reference line? |
| A. | 15, 10 |
| B. | 10, 15 |
| C. | 0, 15 |
| D. | 10, 0 |
| Answer» B. 10, 15 | |
| Explanation: given object is point the top view gives the distance from vertical plane | |
| 165. |
A point is in 2nd quadrant, 15 units away from the vertical plane, 10 units away from the horizontal plane and 8 units away from the profile plane. Orthographic projection is drawn. What is the distance from point of front view to point of side view? |
| A. | 25 |
| B. | 23 |
| C. | 18 |
| D. | 5 |
| Answer» B. 23 | |
| Explanation: side view is obtained by turning the profile plane along the hinge with vertical parallel to vertical plane. side view and front view have same distance from reference line. sum of distances from the point to vertical plane and profile plane gives the following that is 15+8 = 23 units. | |
| 166. |
A point in 2nd quadrant is 15 cm away from both the horizontal plane and vertical plane and orthographic projections are drawn. The distance between the points formed by front view and top view is |
| A. | 0 |
| B. | 30 |
| C. | 15 |
| D. | 15+ distance from a profile |
| Answer» A. 0 | |
| Explanation: given the point is in 2nd quadrant. while drawing orthographic projections the front view and top view overlaps and also the distance of point is same from planes of projections so the distance between them is zero. | |
| 167. |
A point in 2nd quadrant is 10 units away from the horizontal plane and 13 units away from both the vertical plane and profile plane. Orthographic projections are drawn find the distance from side view and front view. |
| A. | 10 |
| B. | 13 |
| C. | 20 |
| D. | 26 |
| Answer» D. 26 | |
| Explanation: given the point is in 2nd quadrant. the front view and side view lie parallel to the horizontal plane when orthographic projections are drawn. the distance from side view to vertical reference is 13 and distance from front view to profile plane is 13. sum is 13+13= 26. | |
| 168. |
A point in 2nd quadrant is 25 units away from both the horizontal plane and profile plane and 15 units away from the vertical plane. Orthographic projections are drawn find the distance from side view and front view. |
| A. | 25 |
| B. | 15 |
| C. | 30 |
| D. | 40 |
| Answer» D. 40 | |
| Explanation: given the point is in 2nd quadrant. the front view and side view lie parallel to the horizontal plane when orthographic projections are drawn. the distance from side view to vertical reference is 15 and distance from front view to profile plane is 25. sum is 15+25 =40. | |
| 169. |
A point in 2nd quadrant is 12 units away from the horizontal plane and vertical plane and 13 units away from both the profile plane. Orthographic projections are drawn find the distance from side view and front view. |
| A. | 13 |
| B. | 26 |
| C. | 25 |
| D. | 24 |
| Answer» C. 25 | |
| Explanation: given the point is in 2nd quadrant. the front view and side view lie parallel to the horizontal plane when orthographic projections are drawn. the distance from side view to vertical reference is 12 and distance from front view to profile plane is 13. sum 12 + 13 =25. | |
| 170. |
A point in 2nd quadrant is 25 units away from both the horizontal plane and profile plane 15 units away from the vertical plane. Orthographic projections are drawn find the distance from the side view and top view. |
| A. | 40 |
| B. | 50.99 |
| C. | 33.54 |
| D. | 41.23 |
| Answer» D. 41.23 | |
| Explanation: given the point is in 2nd quadrant. since here distance from side view and top view is asked for that we need the distance between the front view and side view (25+15); front view and top view (25-15) and these lines which form perpendicular to each other gives needed distance, answer is | |
| 171. |
23units. |
| A. | 25.6 |
| B. | 25 |
| C. | 17.69 |
| D. | 13 |
| Answer» B. 25 | |
| Explanation: given the point is in 2nd quadrant. since here distance from side view and top view is asked for that we need the distance between the front view and side view (12+13); front view and top view (12-12) and these lines which form perpendicular to each other gives needed distance, answer is | |
| 172. |
A point in 2nd quadrant is 10 cm away from the vertical plane and 15 cm away from the horizontal plane, orthographic projections are drawn. What is the distance from a side view of point to line of vertical reference? |
| A. | 10 |
| B. | 15 |
| C. | 25 |
| D. | can’t found |
| Answer» A. 10 | |
| Explanation: given the point is in 2nd quadrant. the distance from the side view of point to line of vertical reference will be the | |
| 173. |
A point is in 2nd quadrant which is 5 meters away from horizontal and 3 meters away from profile plane. Orthographic projections are drawn. What is the distance from the top view to xy reference line? |
| A. | 5 |
| B. | 3 |
| C. | 8 |
| D. | can’t found |
| Answer» D. can’t found | |
| Explanation: given the point is in 2nd quadrant. the xy reference line is between the vertical plane and horizontal plane but distance from a vertical point is not given in question so we can’t found some given information. | |
| 174. |
A point is in 2nd quadrant which is 7 meters away from horizontal and 2 meters away from profile plane. Orthographic projections are drawn. What is the distance from the front view to xy reference line? |
| A. | 7 |
| B. | 2 |
| C. | 5 |
| D. | 9 |
| Answer» A. 7 | |
| Explanation: given the point is in 2nd quadrant. the distance from front view is given by distance between point and horizontal plane here it is given 7 meters. and distance from vertical reference will be 2 meters. | |
| 175. |
A point is in 2nd quadrant which is 8 meters away from vertical and 6 meters away from profile plane. Orthographic projections are drawn. What is the distance from the side view to vertical reference line? |
| A. | 8 |
| B. | 6 |
| C. | 2 |
| D. | can’t found |
| Answer» A. 8 | |
| Explanation: given the point is in 2nd quadrant. the distance from the side view is given by distance between point and vertical plane here it is given 8 meters. and the distance from front view will be 6 meters. | |
| 176. |
Two points are placed in 3rd quadrant of projection planes such that the line joining the points is perpendicular to vertical plane the side view and top view will be |
| A. | single point, two points |
| B. | two points, single point |
| C. | single point, single point |
| D. | two points, two points |
| Answer» D. two points, two points | |
| Explanation: here given the two points such that the joining line is perpendicular to vertical plane in 3rd quadrant asked side view and top view. the views in any quadrant will remain same but the relative positions in projection will change accordingly the quadrant. | |
| 177. |
A point is 7 units away from the vertical plane and 3 units away from profile plane and 3 units away from horizontal plane in 3rd quadrant then the projections are drawn on paper the distance between the front view and top view of point is |
| A. | 10 units |
| B. | 8 units |
| C. | 9 units |
| D. | 5 units |
| Answer» A. 10 units | |
| Explanation: since the point is 3 units away from the horizontal plane the distance from the point to xy reference line will be 3 units. | |
| 178. |
A point is 9 units away from the vertical plane and 5 units away from profile plane and 4 units away from horizontal plane in 3rd quadrant then the projections are drawn on paper the distance between the side view and front view of point is |
| A. | 12 units |
| B. | 14 units |
| C. | 10 units |
| D. | 8 units |
| Answer» B. 14 units | |
| Explanation: since the point is 5 units away from the profile plane the distance from the point to a reference line will be 5 units. and then the point is at distance of 9 units from the vertical plane the distance from reference line and point will be 9, sum is 14. | |
| 179. |
A point is 7 units away from the vertical plane and 5 units away from profile plane and 7 units away from horizontal plane in 3rd quadrant then the projections are drawn on paper the distance between the front view and side view of point is |
| A. | 10 |
| B. | 5 |
| C. | 9 |
| D. | 12 |
| Answer» D. 12 | |
| Explanation: since the point is 5 units away from the profile plane the distance from the point to a reference line will be 5 units. and then the point is at distance of 7 units from the profile plane the distance from reference line and point will be 7 units, sum is 12. | |
| 180. |
8 PROJECTION OF POINTS IN THIRD QUADRANT |
| A. | 29 units |
| B. | 20 units |
| C. | 21 units |
| D. | 17 units |
| Answer» C. 21 units | |
| Explanation: since the point is 12 units away from the profile plane the distance from the point to a reference line will be 12 units. and then the point is at distance of 8 units from profile plane the distance from reference line and point will be 8 units, sum is 20. | |
| 181. |
A point is 20 cm away from the vertical plane and 8 units away from profile plane and 17 cm away from horizontal plane in 3rd quadrant then the projections are drawn on paper the shortest distance from top view and side view of point is |
| A. | 37 |
| B. | 44.65 |
| C. | 46.40 |
| D. | 37.53 |
| Answer» C. 46.40 | |
| Explanation: since here distance from side view and top view is asked for that we need the distance between the front view and side view (8+20); front view and top view (17+20)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √(282+372 ) =46.40 units. | |
| 182. |
If a point P is placed in between the projection planes in third quadrant. The distance from side view to reference line towards front view and the distance between top view and reference line towards top view will be same. |
| A. | true |
| B. | false |
| Answer» A. true | |
| Explanation: the projection will be drawn by turning the other planes parallel to vertical plane in clockwise direction along the lines of intersecting of planes. and so as we fold | |
| 183. |
A point is 2 m away from the vertical plane and 1 m away from profile plane and 9 m away from horizontal plane in 3rd quadrant then the projections are drawn on paper the distance between the side view and top view of point is |
| A. | 21 |
| B. | 14.86 |
| C. | 11.4 |
| D. | 10.4 |
| Answer» B. 14.86 | |
| Explanation: since here distance from side view and top view is asked for that we need the distance between the front view and side view (1+9); front view and top view (9+2)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances | |
| 184. |
A point is 6 units away from the vertical plane and profile plane and 10 units away from horizontal plane in 3rd quadrant then the projections are drawn on paper the distance between the side view and top view of point is |
| A. | 15 |
| B. | 16 |
| C. | 12 |
| D. | 20 |
| Answer» D. 20 | |
| Explanation: since here distance from side view and top view is asked for that we need the distance between the front view and side view (6+6); front view and top view (10+6)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √(122+162 ) = 20 units. | |
| 185. |
A point is 15 cm away from the vertical plane and 10 cm away from profile plane and horizontal plane in 3rd quadrant then the projections are drawn on paper the distance between the front view and top view of point is |
| A. | 27 cm |
| B. | 15 cm |
| C. | 12 cm |
| D. | 25 cm |
| Answer» D. 25 cm | |
| Explanation: since the point is 10 cm away from the horizontal plane the distance from the point to xy reference line will be 10 cm. and then the point is at distance of 15 cm from the vertical plane the distance from reference line and point will be 15, sum is 25 cm. | |
| 186. |
A point is 6 m away from the vertical plane and profile plane 5 m away from horizontal plane in 3rd quadrant then the projections is drawn on paper the distance between the front view and side view of point is |
| A. | 27 |
| B. | 15 |
| C. | 12 |
| D. | 24 |
| Answer» C. 12 | |
| Explanation: since the point is 6 m away from the profile plane the distance from the point to xy reference line will be 6 m. and then the point is a distance of 6 from the profile plane the distance from reference line and point will be 6, sum is 12. | |
| 187. |
A point is 50 cm away from the vertical plane and horizontal plane 80 cm away from profile plane in 3rd quadrant then the projections is drawn on paper the distance between the front view and top view of point is |
| A. | 130 |
| B. | 100 |
| C. | 160 |
| D. | 0 |
| Answer» B. 100 | |
| Explanation: since the point is 50 cm away from the horizontal plane the distance from the point to xy reference line will be 50 cm. and then the point is at distance of 50 cm from the vertical plane the distance from reference line and point will be 50 cm, sum is 100 cm. | |
| 188. |
A point is 5 units away from the vertical plane and horizontal plane 4 units away from profile plane in 3rd quadrant then the projections are drawn on paper the distance between the side view and top view of point is |
| A. | 13.45 |
| B. | 12.72 |
| C. | 19 |
| D. | 12.04 |
| Answer» A. 13.45 | |
| Explanation: since here distance from side view and top view is asked for that we need the distance between the front view and side view (4+5); front view and top view (5+5)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √(102+92 | |
| 189. |
A point is 3 m away from the vertical plane and horizontal planes in 3rd quadrant then the projections are drawn on paper the distance between the side view and vertical reference line? |
| A. | 3 |
| B. | 0 |
| C. | can’t found |
| D. | 6 |
| Answer» A. 3 | |
| Explanation: the side view’s distance from reference line will be the perpendicular distance from the vertical plane and front view’s distance from reference line will be | |
| 190. |
A point is 3 m away from the vertical plane and 7 m away from profile plane in 3rd quadrant then the projections are drawn on paper the distance between the side view and vertical reference line? |
| A. | 6 |
| B. | 3 |
| C. | 14 |
| D. | 7 |
| Answer» B. 3 | |
| Explanation: the side view’s distance from vertical reference line will be the perpendicular distance from vertical plane and top view’s distance from a vertical reference line will be the perpendicular distance from profile plane. | |
| 191. |
A point is in 4th quadrant 10 units away from the horizontal plane and 20 units away from the vertical plane. Orthographic projection is drawn. What is the distance from point of front view to reference line, top view point to reference line? |
| A. | 20, 10 |
| B. | 10, 20 |
| C. | 0, 20 |
| D. | 10, 0 |
| Answer» B. 10, 20 | |
| Explanation: given object is point placed in 4th quadrant the top view gives the distance from the vertical plane (20) and front view gives the distance from horizontal plane (10) both are placed overlapped in orthographic projection since the object is placed in 4th quadrant. | |
| 192. |
A point is in 4th quadrant, 5 m away from the vertical plane, 1 m away from the horizontal plane and 8 units away from the profile plane. Orthographic projection is drawn. What is the distance from point of front view to point of top view? |
| A. | 6 |
| B. | 4 |
| C. | 10 |
| D. | 2 |
| Answer» B. 4 | |
| Explanation: as the point is in 4th quadrant while drawing the projections the planes should rotate along the hinges such that the plane with top view overlaps the front view. so the distance between them is difference of distances from respective planes that is 5 (5- | |
| 193. |
A point in 4th quadrant is 30 mm away from both the horizontal plane and vertical plane and orthographic projections are drawn. The distance between the points formed by front view and top view is |
| A. | 0 |
| B. | 30 |
| C. | 15 |
| D. | 15+ distance from profile |
| Answer» A. 0 | |
| Explanation: given the point is in the 4th quadrant. while drawing orthographic projections the front view and top view overlaps and also the distance of point is same from planes of projections so the distance between them is zero. | |
| 194. |
A point in 4th quadrant is 13 inches away from the horizontal plane and 10 inches away from both the vertical plane and profile plane. Orthographic projections are drawn find the distance from side view and front view. |
| A. | 10 |
| B. | 13 |
| C. | 20 |
| D. | 26 |
| Answer» C. 20 | |
| Explanation: given the point is in 4th quadrant. the front view and side view lie parallel to the horizontal plane when orthographic projections are drawn. the distance from side view to vertical reference is 10 and distance from front view to profile plane is 10. sum is 10+10= 20 inches. | |
| 195. |
A point in 4th quadrant is 18 units away from the horizontal plane and vertical plane and 17 units away from both the profile plane. Orthographic projections are drawn find the distance from side view and front view. |
| A. | 1 |
| B. | 24 |
| C. | 35 |
| D. | 36 |
| Answer» C. 35 | |
| Explanation: given the point is in 4th quadrant. the front view and side view lie parallel to the horizontal plane when orthographic projections are drawn. the distance from side view to vertical reference is 12 and distance from front view to profile plane is 13. sum is 18 + 17 =35 units. | |
| 196. |
A point in 4th quadrant is 8 inches away from the horizontal plane and 20 inches away from both the vertical plane and profile plane. Orthographic projections are drawn find the distance from side view and top view. |
| A. | 41.76 |
| B. | 20 |
| C. | 43.08 |
| D. | 16 |
| Answer» A. 41.76 | |
| Explanation: given the point is in the 4th quadrant. since here distance from side view and top view is asked for that we need the distance between the front view and side view (20+20); front view and top view (20-8) and these lines which form perpendicular to each other gives needed distance, answer is | |
| 197. |
A point in 4th quadrant is 15 cm away from the vertical plane and 10 cm away from the horizontal plane, orthographic projections are drawn. What is the distance from side view of point to line of vertical reference? |
| A. | 10 |
| B. | 15 |
| C. | 25 |
| D. | can’t found |
| Answer» B. 15 | |
| Explanation: given the point is in 4th quadrant. the distance from the side view of point to line of vertical reference will be the distance from the point to the vertical plane in plane of projection that is as given 15 cm. | |
| 198. |
A point is in 4th quadrant which is 15 inches away from horizontal and 30 inches away from profile plane. Orthographic projections are drawn. What is the distance from the top view to xy reference line? |
| A. | 5 |
| B. | 3 |
| C. | 8 |
| D. | can’t found |
| Answer» D. can’t found | |
| Explanation: given the point is in 4th quadrant. the xy reference line is between the vertical plane and horizontal plane but distance from vertical point is not given in question so we can’t found some given information. | |
| 199. |
A point is in 4th quadrant which is 17 dm away from horizontal and 12 dm away from profile plane. Orthographic projections are drawn. What is the distance from the front view to xy reference line? |
| A. | 17 |
| B. | 12 |
| C. | 5 |
| D. | 29 |
| Answer» A. 17 | |
| Explanation: given the point is in 4th quadrant. the distance from front view is given by distance between point and horizontal plane here it is given 17 dm. and distance from vertical reference will be 12 dm. | |
| 200. |
A point is in 4th quadrant which is 18 mm away from vertical and 20 mm away from profile plane. Orthographic projections are drawn. What is the distance from the side view to vertical reference line? |
| A. | 18 |
| B. | 2 |
| C. | 20 |
| D. | can’t found |
| Answer» A. 18 | |
| Explanation: given the point is in 4th quadrant. the distance from side view is given by distance between point and vertical plane here it is given 18 mm. and distance from front view will be 20 mm. | |
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