McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Electrical Engineering .
201. |
the and property of metals increase due to cold working |
A. | hardness, electrical conductivity |
B. | tensile strength, electrical conductivity |
C. | electrical resistance, internal stresses |
D. | corrosion resistance, ductility |
Answer» C. electrical resistance, internal stresses |
202. |
the and property of metals decrease due to cold working |
A. | hardness, electrical conductivity |
B. | tensile strength, electrical conductivity |
C. | electrical resistance, internal stresses |
D. | corrosion resistance, ductility |
Answer» D. corrosion resistance, ductility |
203. |
the property of metals increases and property decreases due to cold working |
A. | hardness, electrical conductivity |
B. | ductility, electrical conductivity |
C. | electrical resistance, internal stresses |
D. | corrosion resistance, ductility |
Answer» A. hardness, electrical conductivity |
204. |
the process by which the internal stresses are reduced in cold worked metal is called |
A. | strain hardening |
B. | hot working |
C. | heat treatment |
D. | cold treatment |
Answer» C. heat treatment |
205. |
the heat treatment which is used to reduce the internal stresses after cold working is called as |
A. | hardeninig |
B. | annealing |
C. | carburising |
D. | quenching |
Answer» B. annealing |
206. |
during recovery part of annealing treatment, which of the following properties are improved noticeably? |
A. | hardness, electrical resistance, tensile strength |
B. | electrical resistance, tensile strength, corrosion resistance |
C. | tensile strength, corrosion resistance, ductility |
D. | internal stresses, electrical resistance, corrosion resistance |
Answer» D. internal stresses, electrical resistance, corrosion resistance |
207. |
during which stage of annealing there is no major change in microstructure ? |
A. | recrystalliza tion |
B. | recovery |
C. | grain growth |
D. | none of the above |
Answer» B. recovery |
208. |
the process of formation of new grains starts by the process of |
A. | recovery |
B. | nucleation |
C. | grain growth |
D. | none of the above |
Answer» B. nucleation |
209. |
nucleation starts at areas of |
A. | low energy |
B. | high energy |
C. | randomly |
D. | none of the above |
Answer» B. high energy |
210. |
new grain formation take place in stage of annealing treatment |
A. | recovery |
B. | grain growth |
C. | recrystalliza tion |
D. | none of the above |
Answer» C. recrystalliza tion |
211. |
after the recrystalllization stage |
A. | hardness and tensile strength reduces |
B. | internal stresses reduces whereas corrosion resistance increases |
C. | ductility increases |
D. | all of the above |
Answer» D. all of the above |
212. |
during grain growth takes place |
A. | new grains are formed |
B. | no change in |
C. | larger grains are formed |
D. | all of the above |
Answer» C. larger grains are formed |
213. |
strain hardening followed by annealing is known as |
A. | cold working |
B. | hot working |
C. | strain hardening |
D. | all of the above |
Answer» B. hot working |
214. |
there are no residual internal stresses after hot working because |
A. | metal is annealed before hot working |
B. | there are no dislocations |
C. | there is simultaneou s working and recrystalliza tion |
D. | all of the above |
Answer» C. there is simultaneou s working and recrystalliza tion |
215. |
wire drawing is a type of |
A. | cold working |
B. | hot working |
C. | cold working followed by hardening |
D. | none of the above |
Answer» A. cold working |
216. |
hot forging is a type of |
A. | cold working |
B. | hot working |
C. | cold working followed by hardening |
D. | none of the above |
Answer» B. hot working |
217. |
in working of metals, the microstructure is distorted |
A. | hot |
B. | cold |
C. | both |
D. | none of the above |
Answer» B. cold |
218. |
it is possible to continuosly work on metal during working |
A. | hot |
B. | cold |
C. | both |
D. | none of the above |
Answer» A. hot |
219. |
cold working requires higher than hot working |
A. | temperature |
B. | time |
C. | energy for plastic deformation |
D. | none of the above |
Answer» C. energy for plastic deformation |
220. |
the possibility of oxidation is higher in case of working of metals |
A. | hot |
B. | cold |
C. | both |
D. | none of the above |
Answer» A. hot |
221. |
in case of hot working of metals, there is higher possibility of |
A. | oxidation |
B. | decarburizat ion |
C. | both a and b |
D. | none of the above |
Answer» C. both a and b |
222. |
the machinery used for hot working is than used for cold working |
A. | cheaper |
B. | expensive |
C. | same |
D. | depends on mertals used |
Answer» C. same |
223. |
the resolved shear stress of a unit cell in nickel is N/mm2 if a tensile stress of 13.7 Mpa is applied. Take angle between the axial force and slip direction is 450 and angle between axial force and normal to slip is 540 |
A. | 2.3 |
B. | 5.7 |
C. | 5.2 |
D. | 6.1 |
Answer» B. 5.7 |
224. |
if resolved shear stress is maximum, it is given by |
A. | σt |
B. | 2σt |
C. | 4σt |
D. | 0.5σt |
Answer» D. 0.5σt |
225. |
at 450 the resolved shear stress is |
A. | minimum |
B. | maximum |
C. | zero |
D. | none of the above |
Answer» B. maximum |
226. |
this is type of slip systems. |
A. | glide |
B. | slip |
C. | twinns |
D. | none of the above |
Answer» A. glide |
227. |
it is type of stacking faults |
A. | twinns |
B. | glide |
C. | climb |
D. | intrisic |
Answer» D. intrisic |
228. |
get for burger vector |
A. | quality |
B. | plane |
C. | direction |
D. | atoms |
Answer» C. direction |
229. |
is defined as fraction of volume occupied by atoms in unit cell |
A. | ligancy number |
B. | avg. no. of atoms/ unit cell |
C. | atomic packing number |
D. | none of the above |
Answer» C. atomic packing number |
230. |
A crystalline material must have |
A. | repetitive arrangement of atoms in any one direction |
B. | repetitive arrangement of atoms in any two direction |
C. | repetitive arrangement of atoms in all three direction |
D. | none of the above |
Answer» C. repetitive arrangement of atoms in all three direction |
231. |
A family of directions is represented by |
A. | (hkl) |
B. | <uvw> |
C. | {hkl} |
D. | [uvw] |
Answer» B. <uvw> |
232. |
A hexagonal crystal system consists of |
A. | a=b=c |
B. | a=b but not equal to c |
C. | β= α = 90 °, γ = 120° |
D. | both b & c |
Answer» D. both b & c |
233. |
A higher value of atomic packing factor number indicates |
A. | bigger size of material |
B. | higher density of material |
C. | higher value of avg. no. of atoms per unit cell |
D. | both b & c |
Answer» D. both b & c |
234. |
A higher value of co-ordination number indicates |
A. | bigger size of material |
B. | higher density of material |
C. | lower density of material |
D. | none of the above |
Answer» B. higher density of material |
235. |
A material having repetitive arrangement of atoms over larger atomic distances is called |
A. | crystalline material |
B. | non- crystalline material |
C. | solid material |
D. | liquid material |
Answer» A. crystalline material |
236. |
A non-crystalline material is characterized as having _ |
A. | repetitive arrangement of atoms in all three direction |
B. | repetitive arrangement of atoms in any one direction |
C. | non- repetitative or random arrangement of atoms in all three directions |
D. | none of the above |
Answer» B. repetitive arrangement of atoms in any one direction |
237. |
A single cubic crystal system consists of |
A. | a=b=c |
B. | a=b but not equal to c |
C. | β= α = γ = 90° |
D. | both a & c |
Answer» D. both a & c |
238. |
A unit cell represents of a crystal structure |
A. | weight |
B. | size |
C. | geometry |
D. | none of the above |
Answer» C. geometry |
239. |
APF (Atomic Packing Factor) of Body- Centered Cubic structure is….. |
A. | 0.74 |
B. | 0.52 |
C. | 0.68 |
D. | 0.8 |
Answer» C. 0.68 |
240. |
FCC structure have APF (Atomic Packing Factor) of ….. |
A. | 0.74 |
B. | 0.52 |
C. | 0.68 |
D. | 0.8 |
Answer» A. 0.74 |
241. |
HCP structure have APF (Atomic Packing Factor) of ….. |
A. | 0.74 |
B. | 0.52 |
C. | 0.68 |
D. | 0.8 |
Answer» A. 0.74 |
242. |
Atomic packing factor is |
A. | distance between two adjacent atoms |
B. | projected area fraction of atoms on a plane |
C. | volume fraction of atoms in cell |
D. | none |
Answer» C. volume fraction of atoms in cell |
243. |
Average frequency of atomic vibrations in a solid (in Hz) |
A. | 10-12 |
B. | 10-13 |
C. | 10+12 |
D. | 10+13 |
Answer» D. 10+13 |
244. |
BCC have Average no. of atoms per unit cell |
A. | 6 |
B. | 2 |
C. | 4 |
D. | 8 |
Answer» B. 2 |
245. |
BCC have ligancy number |
A. | 6 |
B. | 12 |
C. | 4 |
D. | 8 |
Answer» D. 8 |
246. |
BCC having stacking |
A. | abcabca bc |
B. | aaaaaaa |
C. | abababa b |
D. | abcabab c |
Answer» C. abababa b |
247. |
Beneficial property of foreign particles |
A. | reduces density |
B. | act as stress raisers |
C. | obstructs dislocation motion |
D. | none |
Answer» C. obstructs dislocation motion |
248. |
Burger vector gives of the shift |
A. | amount |
B. | quality |
C. | plane |
D. | atoms |
Answer» A. amount |
249. |
Burger vector to dislocation line is for edge dislocations |
A. | perpendicul ar |
B. | parallel |
C. | inclined |
D. | first perpendicul ar then parallel |
Answer» B. parallel |
250. |
Carbon diffuses in Fe, this is type of impurity |
A. | substitution al |
B. | interstitial |
C. | both a & b |
D. | none of the above |
Answer» B. interstitial |
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