McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Civil Engineering .
| 351. |
When a solid is placed such that axis is inclined with the H.P and parallel to the V.P. Its projections are drawn in stages. |
| A. | 1 |
| B. | 4 |
| C. | 2 |
| D. | 3 |
| Answer» C. 2 | |
| Explanation: in the initial stage, the axis is kept perpendicular to the h.p and parallel to | |
| 352. |
A hexagonal pyramid first placed in such a way its axis is perpendicular to V.P and one edge AB parallel to H.P and then next this is turned about its axis so the base AB is now making some angle with H.P. The top view for previous and later one will be having different shapes. |
| A. | true |
| B. | false |
| Answer» B. false | |
| Explanation: for given positions of solid the solid is just rotated around itself and given the axis is perpendicular to v.p so the top view gives the true shape and size of its base but the base is just rotated to its given angle shape will not change. | |
| 353. |
A regular cone first placed in such a way its axis is perpendicular to H.P and next to this is tilted such that its base is making some acute angle with H.P. The top view for previous and later one will be |
| A. | triangle, triangle |
| B. | irregular shape of circle and triangle, triangle |
| C. | circle, irregular shape of circle and triangle |
| D. | circle, triangle |
| Answer» C. circle, irregular shape of circle and triangle | |
| Explanation: for given positions of solid the solid is just tilted to some angle with h.p and previously given the axis is perpendicular to | |
| 354. |
4 PROJECTION OF SOLIDS WITH AXIS INCLINED TO HORIZONTAL PLANE AND PARALLEL TO VERTICAL PLANE |
| A. | true |
| B. | false |
| Answer» A. true | |
| Explanation: for given positions of solid the solid is just tilted to some angle with h.p and previously given the axis is perpendicular to | |
| 355. |
A regular pentagon prism first placed in such a way its axis is perpendicular to H.P and one edge is parallel to V.P and next this is tilted such that its axis is making some acute angle with H.P. The front view for previous and later one will be |
| A. | pentagon, rectangle |
| B. | rectangle, pentagon |
| C. | rectangle, rectangle |
| D. | irregular hexagon, pentagon |
| Answer» C. rectangle, rectangle | |
| Explanation: for given positions of solid the solid is made acute angle with h.p and previously given the axis is perpendicular to | |
| 356. |
A cylinder first placed in such a way its axis is perpendicular to H.P and next this is tilted such that its axis is making some acute angle with H.P. The top view for previous and later one will be |
| A. | circle, rectangle with circular ends |
| B. | rectangle, rectangle |
| C. | rectangle with circular ends, rectangle |
| D. | circle, rectangle |
| Answer» A. circle, rectangle with circular ends | |
| Explanation: for given positions of solid the solid is made acute angle with h.p and previously given the axis is perpendicular to | |
| 357. |
A cylinder first placed in such a way its axis is perpendicular to H.P and next this is tilted such that its axis is making some acute angle with H.P. The front view for previous and later one will be |
| A. | circle, rectangle with circular ends |
| B. | rectangle, rectangle |
| C. | rectangle with circular ends, rectangle |
| D. | circle, rectangle |
| Answer» B. rectangle, rectangle | |
| Explanation: for given positions of solid the solid is made acute angle with v.p and previously given the axis is perpendicular to | |
| 358. |
A triangular pyramid is placed such that its axis is perpendicular to H.P and one of its base’s edges is parallel to H.P the front view and top view will be |
| A. | triangle of base, triangle due to slanting side |
| B. | triangle due to slanting side, triangle of base |
| C. | triangle of base, rhombus |
| D. | rhombus, triangle of base |
| Answer» B. triangle due to slanting side, triangle of base | |
| Explanation: given a triangular pyramid which means the projection to its base gives triangle of base and other orthographic views give triangle due to slanting sides. here given is pyramid whose axis is perpendicular to h.p so its front view will be triangle due to sides and top view will be triangle of base. | |
| 359. |
A square pyramid is placed such that its axis is inclined to H.P and one of its base’s edges is parallel to V.P the front view and top view will be |
| A. | square, isosceles triangle |
| B. | irregular pentagon, square |
| C. | isosceles triangle, irregular pentagon |
| D. | pentagon, equilateral triangle |
| Answer» C. isosceles triangle, irregular pentagon | |
| Explanation: given a square pyramid which means the projection to its base gives square shape and other orthographic views give triangle. here given is pyramid whose axis is inclined to h.p so its front view will be isosceles triangle and top view will be square. | |
| 360. |
A square prism is placed such that its axis is inclined to H.P and one of its base’s edges is parallel to V.P the front view and top view will be |
| A. | square, irregular polygon |
| B. | irregular polygon, square |
| C. | square, rectangle |
| D. | rectangle, irregular polygon |
| Answer» D. rectangle, irregular polygon | |
| Explanation: given a square prism which means the projection to its base gives square shape and other orthographic views give rectangle. here given is prism whose axis is inclined to h.p so its front view will be rectangle and top view will be irregular polygon. | |
| 361. |
A tetrahedron is made to place on H.P that is with its axis perpendicular to it and one of the edges of base parallel to V.P and then the tetrahedron is made to rotate w.r.t to H.P up to an acute angle. The top view of previous and later one is |
| A. | isosceles triangle, isosceles triangle |
| B. | equilateral triangle, isosceles triangle |
| C. | equilateral triangle, square |
| D. | square, irregular polygon of 4 sides |
| Answer» B. equilateral triangle, isosceles triangle | |
| Explanation: as normal a tetrahedron gives equilateral triangle for a project to its base and isosceles triangle for other view when placed without inclination but here inclination is given but given view is top view so the shape will change to isosceles triangle. | |
| 362. |
The front views of 1st, 2nd and final stages of square prism, has its axis inclined at 45 degrees with H.P and has an edge of its base on H.P and inclined 30 degrees with V.P while drawing orthographic projections are |
| A. | rectangle, rectangle, hexagon |
| B. | square, rectangle, rectangle |
| C. | rectangle, rectangle, octagon |
| D. | square, rectangle, hexagon |
| Answer» A. rectangle, rectangle, hexagon | |
| Explanation: as the 1st stage is to keep the solid in simple position and given is front view it is rectangle and then rotated to an angle of 45 degrees with h.p which again gives rectangle and then rotating 30 degrees | |
| 363. |
The top views of 1st, 2nd and final stages of square prism, has its axis inclined at 45 degrees with H.P and has an edge of its base on H.P and inclined 30 degrees with V.P while drawing orthographic projections are |
| A. | rectangle, rectangle, hexagon |
| B. | square, rectangle, rectangle |
| C. | rectangle, rectangle, octagon |
| D. | square, rectangle, hexagon |
| Answer» B. square, rectangle, rectangle | |
| Explanation: as the 1st stage is to keep the solid in simple position and given is top view it is square and then rotated to an angle of 45 degrees with h.p which gives rectangle and | |
| 364. |
The top views of 1st, 2nd and final stages of a pentagonal pyramid, has one of its triangular faces in the V.P and edge of the base contained by that face makes an angle of 30 degrees with the H.P while drawing orthographic projections are |
| A. | pentagon, irregular pentagon, irregular pentagon |
| B. | triangle, irregular pentagon, irregular pentagon |
| C. | triangle, triangle, irregular pentagon |
| D. | pentagon, triangle, irregular pentagon |
| Answer» C. triangle, triangle, irregular pentagon | |
| Explanation: as the 1st stage is to keep the solid in simple position for given conditions the solid’s base should be placed on v.p so top view gives triangle and then rotated so as to one of the face touch the v.p now the view will remain triangle and then adjust so that edge of base on v.p makes 30 degrees with | |
| 365. |
A cube is resting on H.P on one of its corners with a solid diagonal perpendicular to the V.P. What are the top views of 1st, 2nd, 3rd stages while drawing orthographic projections? |
| A. | rectangle, rectangle, regular hexagon |
| B. | square, irregular hexagon, irregular hexagon |
| C. | rectangle, rectangle, irregular hexagon |
| D. | square, regular hexagon, regular hexagon |
| Answer» B. square, irregular hexagon, irregular hexagon | |
| Explanation: as in the 1st stage the cube is to be placed in the position occurred when the diagonal of base perpendicular to v.p so top view gives square and then rotated so as to keep one of the corners only on h.p so the top view will be irregular hexagon then if we make diagonal perpendicular to v.p the top view will be irregular hexagon. | |
| 366. |
A pentagonal prism is resting on H.P on one of its corners and from top view the solid’s axis is making 30 degrees with the xy reference line. What are the top views of the 1st, 2nd, 3rd stages of orthographic drawing? |
| A. | rectangle, rectangle, heptagon |
| B. | pentagon, heptagon, heptagon |
| C. | rectangle, heptagon, rectangle |
| D. | pentagon, rectangle, heptagon |
| Answer» B. pentagon, heptagon, heptagon | |
| Explanation: as in the 1st stage the pentagonal prism is to be placed in simple position the axis perpendicular to v.p so top view gives pentagon and then rotated so as to keep one of the corners only on h.p so the top view will be irregular heptagon then adjusting the axis so as to make 30 degrees with xy reference line so top view remain same. | |
| 367. |
A pentagonal prism is resting on H.P on one of its corners and from top view the solid’s axis is making 30 degrees with the xy reference line. What are the front views of the 1st, 2nd, 3rd stages of orthographic drawing? |
| A. | rectangle, rectangle, heptagon |
| B. | pentagon, heptagon, heptagon |
| C. | rectangle, heptagon, rectangle |
| D. | pentagon, rectangle, heptagon |
| Answer» A. rectangle, rectangle, heptagon | |
| Explanation: as in the 1st stage the pentagonal prism is to be placed in simple position the axis perpendicular to v.p so front view gives rectangle and then rotated so as to keep one of the corners only on h.p so the front view will remain same then from projections of top view the front is drawn so an irregular heptagon will form. | |
| 368. |
A pentagonal pyramid is placed on H.P on one of its base’s edge and the triangular surface containing the edge on which it is resting is making 45 degrees with H.P. Draw orthographic views and what are the top views of 1st, 2nd, 3rd stages? |
| A. | triangle, triangle, irregular pentagon |
| B. | pentagon, irregular polygon of 4 sides, irregular polygon of 4 sides |
| C. | triangle, triangle, irregular polygon of 4 sides |
| D. | pentagon, irregular pentagon, irregular pentagon |
| Answer» B. pentagon, irregular polygon of 4 sides, irregular polygon of 4 sides | |
| Explanation: in the 1st stage the solid’s axis | |
| 369. |
A pentagonal pyramid is placed on H.P on one of its base’s edge and the triangular surface containing the edge on which it is resting is making 45 degrees with H.P. Draw orthographic views and what are the front views of 1st, 2ndrd stages? |
| A. | triangle, triangle, irregular pentagon |
| B. | pentagon, irregular polygon of 4 sides, irregular polygon of 4 sides |
| C. | triangle, triangle, irregular polygon of 4 sides |
| D. | pentagon, irregular pentagon, irregular pentagon |
| Answer» A. triangle, triangle, irregular pentagon | |
| Explanation: in the 1st stage the solid’s axis is perpendicular to h.p and one base’s edge is perpendicular to v.p. so the front view will be triangle and then made to rest on only one edge so front view will remain same and then adjusted to a given angle so front view will be pentagon. | |
| 370. |
surface is formed when a sphere is cut by a plane. |
| A. | ellipse |
| B. | parabola |
| C. | circle |
| D. | hyperbola |
| Answer» C. circle | |
| Explanation: sphere is a closed solid object which is formed by rotating semicircle about its flat side. sphere gives top view, front view, side views as a circle whose radius is equal to the radius of a sphere. | |
| 371. |
When a hemisphere is placed on the ground on its flat face, its front view is a |
| A. | semi circle |
| B. | circle |
| C. | ellipse |
| D. | irregular one |
| Answer» A. semi circle | |
| Explanation: hemisphere is solid formed by cutting the sphere at its middle. the flat surface of hemisphere will have section of circle with radius equal to radius of sphere. here the hemisphere is placed on h.p on its flat surface so it gives semi circle from front view. | |
| 372. |
When a hemisphere is placed on the ground on its flat face, its top view is a |
| A. | semi circle |
| B. | circle |
| C. | ellipse |
| D. | irregular one |
| Answer» B. circle | |
| Explanation: hemisphere is solid formed by cutting the sphere at its middle. the flat surface of hemisphere will have section of circle with radius equal to radius of sphere. here the hemisphere is placed on h.p on its flat surface so it gives circle from top view. | |
| 373. |
When a hemisphere is placed on H.P such that the flat surface is perpendicular to V.P and inclined with horizontal then the front view will be |
| A. | semi circle |
| B. | circle |
| C. | ellipse |
| D. | irregular one |
| Answer» A. semi circle | |
| Explanation: the flat surface of hemisphere will have section of circle with radius equal to radius of sphere. here the hemisphere is placed on h.p so that its flat surface is inclined to h.p so it gives semi circle from front view and ellipse from top view. | |
| 374. |
When two spheres of same radius are placed on H.P both are touching each other and the line joining the centers is perpendicular to V.P. The front view will be. |
| A. | single circle |
| B. | two circles |
| C. | concentric circles |
| D. | intersecting circles |
| Answer» A. single circle | |
| Explanation: given two spheres of same radius are placed on h.p touching each other so as the spheres are placed on h.p the line joining the centers is parallel to h.p and given it is perpendicular to v.p so they both align in one line which gives single circle from front view. | |
| 375. |
When two spheres of same radius are placed on H.P both are touching each other and the line joining the centers is perpendicular to V.P. The top view will be |
| A. | single circle |
| B. | two circles |
| C. | concentric circles |
| D. | intersecting circles |
| Answer» B. two circles | |
| Explanation: given two spheres of same radius are placed on h.p touching each other so as the spheres are placed on h.p the line | |
| 376. |
When two spheres of same radius are placed on H.P both are touching each other and the line joining the centers is making 45 degrees to V.P. The front view will be |
| A. | single circle |
| B. | two circles |
| C. | concentric circles |
| D. | intersecting circles |
| Answer» D. intersecting circles | |
| Explanation: given two spheres of same radius are placed on h.p touching each other | |
| 377. |
When two spheres of same radius are placed on H.P both are touching each other and the line joining the centers is making 45 degrees to V.P. The top view will be |
| A. | single circle |
| B. | two circles |
| C. | concentric circles |
| D. | intersecting circles |
| Answer» D. intersecting circles | |
| Explanation: given two spheres of same radius are placed on h.p touching each other so as the spheres are placed on h.p the line joining the centers is parallel to h.p and given it is making 45 degrees with v.p so they both align in one line which gives two circles in top view. | |
| 378. |
Three spheres of same radius are placed on H.P such that the line joining centers is parallel to H.P and each one touching other two. The front view will be |
| A. | three circles |
| B. | two circles |
| C. | concentric circles |
| D. | intersecting circles |
| Answer» D. intersecting circles | |
| Explanation: given three spheres of same radius are placed on h.p each touching other | |
| 379. |
Three spheres of same radius are placed on H.P such that the line joining centers is parallel to H.P and each one touching other two. The top view will be |
| A. | three circles |
| B. | two circles |
| C. | concentric circles |
| D. | intersecting circles |
| Answer» A. three circles | |
| Explanation: given three spheres of same radius are placed on h.p each touching other two, the line joining centers of spheres gives equilateral triangle. from front view the spheres seem to be intersecting circles but from top three circles will be seen. | |
| 380. |
Which of the following is not the purpose of using cutting (section) plane? |
| A. | interpretation of object |
| B. | visualizing of object |
| C. | cutting the objects |
| D. | invisible features |
| Answer» C. cutting the objects | |
| Explanation: section plane or cutting plane is an imaginary plane which is used to cut the object to visualize the geometry which is hidden inside the object and interpret it which plays an important role in designing many machine parts. | |
| 381. |
To understand some of the hidden geometry of components an imaginary plane is used to cut the object which is called |
| A. | auxiliary plane |
| B. | picture plane |
| C. | section plane |
| D. | additional plane |
| Answer» C. section plane | |
| Explanation: to understand some of the hidden geometry of components an imaginary plane is used to cut the object which is called | |
| 382. |
A section plane is parallel to V.P the top view gives which is to xy line. |
| A. | true shape, parallel |
| B. | straight line, parallel |
| C. | straight line, perpendicular |
| D. | true shape, perpendicular |
| Answer» B. straight line, parallel | |
| Explanation: the projection of section plane on the plane to which it is perpendicular gives a straight line which is parallel, perpendicular, inclined as due to section if it is parallel, perpendicular, inclined to reference planes. | |
| 383. |
The projection of a section plane, on the plane to which it is perpendicular is a straight line. |
| A. | true |
| B. | false |
| Answer» A. true | |
| Explanation: the projection of a section plane, on the plane to which it is perpendicular is a straight line. the projection of a section on the reference plane to which the section plane is perpendicular will be a straight line coinciding with the trace of the section plane of it. | |
| 384. |
The projection of section surface on the other plane to which it is inclined is called auxiliary section. |
| A. | true |
| B. | false |
| Answer» B. false | |
| Explanation: no it is not auxiliary plane but apparent section. this is obtained by projecting on the other plane, the points at which the trace of the section plane intersects | |
| 385. |
The section plane is perpendicular to H.P and inclined to V.P the front view of section if section is a line. It xy line. |
| A. | is perpendicular to |
| B. | is parallel to |
| C. | is inclined to v.p |
| D. | crosses |
| Answer» B. is parallel to | |
| Explanation: the projection of section plane on the plane to which it is perpendicular gives a straight line. it is given the section is line and also from front view the section lies parallel to xy reference line. | |
| 386. |
The section plane is perpendicular to H.P and inclined to V.P the top view of section if section is a line. It xy line. |
| A. | is perpendicular to |
| B. | is parallel to |
| C. | is inclined to v.p |
| D. | crosses |
| Answer» C. is inclined to v.p | |
| Explanation: the projection of section plane on the plane to which it is perpendicular gives a straight line. here it is given section plane is inclined with v.p so top view gives a line inclined to xy reference line. | |
| 387. |
A section is parallel to horizontal plane the true shape and size is obtained by taking projection of section on to plane. |
| A. | horizontal |
| B. | vertical |
| C. | profile |
| D. | auxiliary |
| Answer» A. horizontal | |
| Explanation: always remember the true shape and size will be trace if projections are drawn on to the plane parallel to section plane. so here as the section is parallel to horizontal plane the projection is to be taken on horizontal plane. | |
| 388. |
A section is parallel to vertical plane the true shape and size is obtained by taking projection of section on to plane. |
| A. | horizontal |
| B. | vertical |
| C. | profile |
| D. | auxiliary |
| Answer» B. vertical | |
| Explanation: always remember the true shape and size will be trace if projections are drawn on to the plane parallel to section plane. so here as the section is parallel to a vertical plane the projection is to be taken on vertical plane. | |
| 389. |
A regular triangular prism is resting on H.P and section plane is parallel to H.P and cutting the prism the section would be a |
| A. | triangle |
| B. | rectangle |
| C. | trapezium |
| D. | parallelogram |
| Answer» B. rectangle | |
| Explanation: prisms are obtained by extruding required shape up to some appreciable length so there exist same cross- section along the length perpendicular to axis. if the cutting plane parallel to axis we get rectangle. | |
| 390. |
A cube is placed on H.P on its base and vertical face is making 30 degrees with V.P, section plane is perpendicular to V.P the section will give a shape of a |
| A. | triangle |
| B. | rectangle |
| C. | trapezium |
| D. | parallelogram |
| Answer» C. trapezium | |
| Explanation: prisms are obtained by extruding required shape up to some appreciable length so there will be same cross-section along the length perpendicular to axis. if the cutting plane is parallel to axis we get rectangle if inclined to axis the section depends on the position where it is cutting. | |
| 391. |
A square prism has its base on H.P and its faces equally inclined to V.P is cut at most critical place by a plane which is perpendicular to V.P and inclined 60 degrees with H.P the section will have shape like a |
| A. | irregular pentagon |
| B. | rectangle |
| C. | trapezium |
| D. | parallelogram |
| Answer» A. irregular pentagon | |
| Explanation: prisms are obtained by extruding required shape up to some appreciable length so there will be same cross-section along the length perpendicular to axis. if the cutting plane is parallel to axis we get rectangle if inclined to axis the section depends on the position where it is cutting. | |
| 392. |
A triangular prism resting on one of its longest faces on H.P and axis of prism is parallel to V.P, the section plane is perpendicular to both V.P and H.P the section will be a |
| A. | triangle |
| B. | rectangle |
| C. | trapezium |
| D. | parallelogram |
| Answer» A. triangle | |
| Explanation: prisms are obtained by extruding required shape up to some appreciable length so there exist same cross- section along the length perpendicular to axis. if the cutting plane parallel to axis we get a rectangle. | |
| 393. |
A pentagonal prism resting on one of its longest faces on H.P and axis of prism is parallel to V.P, the section plane is perpendicular to both V.P and H.P the section will be a |
| A. | pentagon |
| B. | irregular pentagon |
| C. | rectangle |
| D. | trapezium |
| Answer» A. pentagon | |
| Explanation: prisms are obtained by extruding required shape up to some appreciable length so there exist same cross- section along the length perpendicular to axis. if the cutting plane parallel to axis we get a rectangle. | |
| 394. |
A pentagonal prism resting on one of its longest faces on H.P and axis of prism is parallel to V.P, the section plane is perpendicular to V.P and inclined H.P the section will be a |
| A. | pentagon |
| B. | irregular pentagon |
| C. | rectangle |
| D. | trapezium |
| Answer» B. irregular pentagon | |
| Explanation: prisms are obtained by extruding required shape up to some | |
| 395. |
A hexagonal prism is resting on H.P on one of its longest faces, axis is perpendicular to V.P the section plane is parallel to V.P and perpendicular to H.P. The section will be like a |
| A. | hexagon |
| B. | irregular hexagon |
| C. | rectangle |
| D. | trapezium |
| Answer» A. hexagon | |
| Explanation: prisms are obtained by extruding required shape up to some appreciable length so there exist same cross- section along the length perpendicular to axis. if the cutting plane parallel to axis we get a rectangle. | |
| 396. |
A square pyramid is placed on V.P with square as base on V.P the cutting plane is parallel to H.P and also parallel to one edge of base, the section will be |
| A. | triangle |
| B. | rectangle |
| C. | square |
| D. | trapezium |
| Answer» D. trapezium | |
| Explanation: if a pyramid is cut by a plane parallel to axis and also parallel to any edge of base then the section formed will be trapezium if the section plane not parallel to edge of base then the section will be triangle. | |
| 397. |
A square pyramid is placed on V.P with square as base on V.P the cutting plane is parallel to V.P, the section will be |
| A. | triangle |
| B. | rectangle |
| C. | square |
| D. | pentagon |
| Answer» C. square | |
| Explanation: if a pyramid is cut by a plane perpendicular to its axis section gives the base shape or parallel to axis and also parallel to any edge of base then the section formed will be trapezium if the section plane not parallel to edge of base then the section will be triangle. | |
| 398. |
A pentagon pyramid is placed on V.P with square as base on V.P the cutting plane is parallel to H.P and parallel to edge of base, the section will be |
| A. | triangle |
| B. | rectangle |
| C. | trapezium |
| D. | pentagon |
| Answer» C. trapezium | |
| Explanation: if a pyramid is cut by a plane parallel to axis and also parallel to any edge of base then the section formed will be trapezium if the section plane not parallel to edge of base then the section will be triangle. | |
| 399. |
A pentagon pyramid is placed on V.P with square as base on V.P the cutting plane is perpendicular to H.P and inclined to V.P and the section is cutting the whole cross-section, the section will be |
| A. | triangle |
| B. | trapezium |
| C. | irregular square |
| D. | irregular pentagon |
| Answer» D. irregular pentagon | |
| Explanation: given a regular pentagonal pyramid it may of any size having any distances in between them if a section plane cutting the solid inclined to its base and completely cutting the solid the section formed will be irregular base shape. | |
| 400. |
A pentagon pyramid is placed on V.P with square as base on V.P the cutting plane is perpendicular to H.P and inclined to V.P and the section is cutting not more than 3 edges, the section will be |
| A. | triangle |
| B. | trapezium |
| C. | irregular square |
| D. | irregular pentagon |
| Answer» A. triangle | |
| Explanation: : if a pyramid is cut by a plane perpendicular to its axis section gives the base shape or parallel to axis and also parallel to any edge of base then the section formed will be trapezium if the section plane not parallel to edge of base then the section will be a triangle. | |
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