McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Civil Engineering .
| 101. |
The value of Cd and Cv is 0.62 & 0.92, then find Cc. |
| A. | 0.57 |
| B. | 0.67 |
| C. | 1.48 |
| D. | 1.0 |
| Answer» C. 1.48 | |
| 102. |
An opening provided in one side of a tank or a reservoir, with upstream liquid level below the top edge of the opening is called |
| A. | circle |
| B. | orifice |
| C. | notch |
| D. | weir |
| Answer» C. notch | |
| 103. |
a structure constructed across a river or canal to store water on the upstream side is called |
| A. | circle |
| B. | orifice |
| C. | notch |
| D. | weir |
| Answer» D. weir | |
| 104. |
The top of a weir over which water flows is known as |
| A. | top |
| B. | crest |
| C. | max level |
| D. | max height |
| Answer» B. crest | |
| 105. |
As compared to notch, the size of weir is large. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» A. true | |
| 106. |
The equation of rectangular notch is deal with H is |
| A. | 2/3 |
| B. | 3/2 |
| C. | 5/2 |
| D. | 2/5 |
| Answer» B. 3/2 | |
| 107. |
The equation of V-notch is deal with H is |
| A. | 2/3 |
| B. | 3/2 |
| C. | 5/2 |
| D. | 2/5 |
| Answer» C. 5/2 | |
| 108. |
Water is flowing through a rectangular notch, having base width 500 mm and head over it is 160 mm. Find discharge of notch if Cd = 0.6. |
| A. | 0.0567 m3/sec |
| B. | 56.70 m3/sec |
| C. | 0.0567 lit/sec |
| D. | 56.70 lit/sec |
| Answer» A. 0.0567 m3/sec | |
| 109. |
Only one reading, i.e. head (H) is required to be taken for the measurement of discharge in a triangular notch. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» A. true | |
| 110. |
A rectangular notch gives more accurate results for low discharges than a triangular notch. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» B. false | |
| 111. |
The same triangular notch can measure a wide range of flows accurately. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» A. true | |
| 112. |
When the length of the weir is less than the width of the stream, there will be contraction of flow at each end. This contraction is known as |
| A. | side contraction |
| B. | end contraction |
| C. | sides contraction |
| D. | none of the above |
| Answer» B. end contraction | |
| 113. |
The velocity with which water approaches the weir, is known as |
| A. | velocity coming |
| B. | velocity ends |
| C. | velocity of approach |
| D. | all of the above |
| Answer» C. velocity of approach | |
| 114. |
the velocity of approach is considered for the discharge over the weir then the additional height of must be considered. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» A. true | |
| 115. |
The cippoletti weir is a trapezoidal weir, having side slope 1 horizontal to 4 vertical. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» A. true | |
| 116. |
Determine the head over sill of a 90° V-notch when the discharge passing over it is 100 lit/sec. consider Cd 0.6. |
| A. | 0.346 cm |
| B. | 3.46 cm |
| C. | 0.346 m |
| D. | 3.46 m |
| Answer» C. 0.346 m | |
| 117. |
A 12 m long weir is subdivided by four intermediate vertical posts each 0.6 m wide. If the weir is discharging under a head of 0.5 m, calculate discharge using Francis formula. |
| A. | 5.895 m3/sec |
| B. | 5.895 m3/hr |
| C. | 5.895 lit/sec |
| D. | 5.895 lit/ hr |
| Answer» A. 5.895 m3/sec | |
| 118. |
As the flow moves in the pipe, fluid pressure decreases. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» A. true | |
| 119. |
The velocity of liquid particles at the centre of pipe is less than the velocity of particles near the inner surface of pipe. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» B. false | |
| 120. |
The frictional resistance is proportional to the velocity in laminar flow |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» A. true | |
| 121. |
The fR depends on the nature of the surface of contact in laminar flow. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» B. false | |
| 122. |
Head loss due to entry. |
| A. | h = 0.5 V12/2g |
| B. | h = 0.5 V22/2g |
| C. | h = (V2 – V3)2/2g |
| D. | h = 0.5 V32/2g |
| Answer» A. h = 0.5 V12/2g | |
| 123. |
Head loss due to exist. |
| A. | h = 0.5 V12/2g |
| B. | h = 0.5 V22/2g |
| C. | h = (V2 – V3)2/2g |
| D. | h = 0.5 V32/2g |
| Answer» D. h = 0.5 V32/2g | |
| 124. |
Head loss due to sudden contraction. |
| A. | h = 0.5 V12/2g |
| B. | h = 0.5 V22/2g |
| C. | h = (V2 – V3)2/2g |
| D. | h = 0.5 V32/2g |
| Answer» B. h = 0.5 V22/2g | |
| 125. |
Head loss due to sudden enlargement. |
| A. | h = 0.5 V12/2g |
| B. | h = 0.5 V22/2g |
| C. | h = (V2 – V3)2/2g |
| D. | h = 0.5 V32/2g |
| Answer» C. h = (V2 – V3)2/2g | |
| 126. |
Head loss due to fitting in pipe. |
| A. | h = 0.5 V12/2g |
| B. | h = Kb V2/2g |
| C. | h = (V2 – V3)2/2g |
| D. | h = Kf V2/2g |
| Answer» D. h = Kf V2/2g | |
| 127. |
Head loss due to bend in pipe. |
| A. | h = 0.5 V12/2g |
| B. | h = 0.5 V22/2g |
| C. | h = (V2 – V3)2/2g |
| D. | h = 0.5 V32/2g |
| Answer» B. h = 0.5 V22/2g | |
| 128. |
In ___________ Reynolds carried out number of to decide the type of flow. |
| A. | 1823 |
| B. | 1833 |
| C. | 1843 |
| D. | 1853 |
| Answer» B. 1833 | |
| 129. |
In Reynolds experiment, the dye thread will move so steadily that it will be hardly seen to be in motion. Such a flow is known as |
| A. | Laminar flow |
| B. | Transition flow |
| C. | Turbulent flow |
| D. | None of the above |
| Answer» A. Laminar flow | |
| 130. |
Such a velocity, at which the dye thread starts becoming irregular is known as |
| A. | lower critical velocity. |
| B. | upper critical velocity |
| C. | critical velocity |
| D. | None of the above |
| Answer» A. lower critical velocity. | |
| 131. |
Such a velocity at which the whole dye thread is diffused, is known as |
| A. | lower critical velocity. |
| B. | upper critical velocity |
| C. | critical velocity |
| D. | None of the above |
| Answer» B. upper critical velocity | |
| 132. |
In Reynolds experiment, beyond the upper critical velocity, the flow will be fully disturbed and such a flow is known as |
| A. | Laminar flow |
| B. | Transition flow |
| C. | Turbulent flow |
| D. | None of the above |
| Answer» C. Turbulent flow | |
| 133. |
If pressure heads (P/w) of a liquid Bowing in a pipe be plotted as vertical ordinates on the center line of the pipe, then the line joining the tops of such ordinates is known as |
| A. | Hydraulic Line |
| B. | Hydraulic Gradient Line |
| C. | Total Energy Line |
| D. | Energy Line |
| Answer» B. Hydraulic Gradient Line | |
| 134. |
If the sum of pressure heads and velocity heads [(p/w) + (v2 /2g)] of a liquid flowing In a pipe be plotted as vertical ordinates on the centre line of the pipe. then the line joining the tops of such ordinates is known as |
| A. | Hydraulic Line |
| B. | Hydraulic Gradient Line |
| C. | Total Energy Line |
| D. | Energy Line |
| Answer» C. Total Energy Line | |
| 135. |
A nomogram is a graph in which lines representing different variables are arranged at certain distances is known as |
| A. | Hazen Nomogram |
| B. | William Nomogram |
| C. | Hazen-William Nomogram |
| D. | None of the above |
| Answer» C. Hazen-William Nomogram | |
| 136. |
The Hagen William formula is used to design the pipeline. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» A. true | |
| 137. |
Water supply system for any village or city can be designed by |
| A. | Gravitational method |
| B. | Gravitational and Pumping combined system |
| C. | Pumping system |
| D. | All of the above |
| Answer» D. All of the above | |
| 138. |
In the gravitational system, normally Pressure in the pipe is |
| A. | 2 to 7 kg/m3 |
| B. | 10 to 45 kg/m3 |
| C. | 1 to 2 kg/m3 |
| D. | 150 to 200 kg/m3 |
| Answer» A. 2 to 7 kg/m3 | |
| 139. |
In the gravitational system, normally Velocity of flow is |
| A. | 2 to 7 m/sec |
| B. | 10 to 45 m/sec |
| C. | 1 to 2 m/sec |
| D. | 150 to 200 m/sec |
| Answer» C. 1 to 2 m/sec | |
| 140. |
In the gravitational system, normally Diameter of pipe is |
| A. | 2 to 7 cm |
| B. | 10 to 45 cm |
| C. | 1 to 2 cm |
| D. | 150 to 200 cm |
| Answer» B. 10 to 45 cm | |
| 141. |
In the gravitational system, normally Water requirements is |
| A. | 2 to 7 liter per capita per day. |
| B. | 10 to 45 liter per capita per day. |
| C. | 1 to 2 liter per capita per day. |
| D. | 150 to 200 liter per capita per day. |
| Answer» D. 150 to 200 liter per capita per day. | |
| 142. |
While laying a pipeline we have to connect pipes of different lengths and diameters with one another to form a pipeline. Such a pipeline is called a |
| A. | pipe line |
| B. | compound pipe |
| C. | equivalent pipe |
| D. | None of the above |
| Answer» A. pipe line | |
| 143. |
Sometimes a compound pipe is required to be replaced by a pipe of uniform diameter and of the same length as that of the compound pipe is known as |
| A. | pipe line |
| B. | compound pipe |
| C. | equivalent pipe |
| D. | None of the above |
| Answer» C. equivalent pipe | |
| 144. |
A pipe line is 6 km long and having 20 cm diameter connect two reservoir 'A' and 'B'. The rate of discharge in the pipe is 30 lit/sec. Find out the difference in reservoir levels if friction factor f = 0.0008. |
| A. | 4.5 mm |
| B. | 4.5 cm |
| C. | 4.5 m |
| D. | 4.5 |
| Answer» C. 4.5 m | |
| 145. |
A compound pipe line is made up of pipe 45 cm dia. for 900 m, 37.5 cm for 450 m and 30 cm for 300 m is required to replace by a pipe of uniform diameter. Find diameter of equivalent pipe. |
| A. | 0.37 cm |
| B. | 3.7 cm |
| C. | 3.7 m |
| D. | 0.37 m |
| Answer» D. 0.37 m | |
| 146. |
When the free surface of a stream is in contact with the atmosphere and the flow is flowing due to gravitational force and atmospheric pressure, it is called |
| A. | canal |
| B. | river |
| C. | aqueduct |
| D. | all of the above |
| Answer» D. all of the above | |
| 147. |
When the free surface of a stream is in contact with the atmosphere and the flow is flowing due to gravitational force and atmospheric pressure, it is called pipe. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» B. false | |
| 148. |
Flow into the canal, flows due to the slope of the bottom of the canal. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» A. true | |
| 149. |
The roughness of the pipe depends upon the new or old pipe. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» A. true | |
| 150. |
The cross-section is irregular in shape in artificial channel. |
| A. | true |
| B. | false |
| C. | all |
| D. | none |
| Answer» B. false | |
Done Studing? Take A Test.
Great job completing your study session! Now it's time to put your knowledge to the test. Challenge yourself, see how much you've learned, and identify areas for improvement. Don’t worry, this is all part of the journey to mastery. Ready for the next step? Take a quiz to solidify what you've just studied.