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McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Uncategorized topics .
201. |
Which of the following is an assumption of an LP model |
A. | Divisibility |
B. | Proportionality |
C. | Additivity |
D. | All of the above |
Answer» D. All of the above |
202. |
Which of the following is a limitation associated with an LP model |
A. | The relationship among decision variables in linear |
B. | No guarantee to get integer valued solutions |
C. | No consideration of effect of time & uncertainty on LP model |
D. | All of the above |
Answer» D. All of the above |
203. |
The graphical method of LP problem uses |
A. | Objective function equation |
B. | Constraint equations |
C. | Linear equations |
D. | All of the above |
Answer» D. All of the above |
204. |
A feasible solution to an LP problem |
A. | Must satisfy all of the problem’s constraints simultaneously |
B. | Need not satisfy all of the constraints, only some of them |
C. | Must be a corner point of the feasible region |
D. | Must optimize the value of the objective function |
Answer» A. Must satisfy all of the problem’s constraints simultaneously |
205. |
Which of the following statements is true with respect to the optimal solution of an LP problem |
A. | Every LP problem has an optimal solution |
B. | Optimal solution of an LP problem always occurs at an extreme point |
C. | At optimal solution all resources are completely used |
D. | If an optimal solution exists, there will always be at least one at a corner |
Answer» D. If an optimal solution exists, there will always be at least one at a corner |
206. |
An iso-profit line represents |
A. | An infinite number of solutions all of which yield the same profit |
B. | An infinite number of solution all of which yield the same cost |
C. | An infinite number of optimal solutions |
D. | A boundary of the feasible region |
Answer» A. An infinite number of solutions all of which yield the same profit |
207. |
If an iso-profit line yielding the optimal solution coincides with a constaint line, then |
A. | The solution is unbounded |
B. | The solution is infeasible |
C. | The constraint which coincides is redundant |
D. | None of the above |
Answer» D. None of the above |
208. |
While plotting constraints on a graph paper, terminal points on both the axes are connected by a straight line because |
A. | The resources are limited in supply |
B. | The objective function as a linear function |
C. | The constraints are linear equations or inequalities |
D. | All of the above |
Answer» C. The constraints are linear equations or inequalities |
209. |
A constraint in an LP model becomes redundant because |
A. | Two iso-profit line may be parallel to each other |
B. | The solution is unbounded |
C. | This constraint is not satisfied by the solution values |
D. | None of the above |
Answer» D. None of the above |
210. |
If two constraints do not intersect in the positive quadrant of the graph, then |
A. | The problem is infeasible |
B. | The solution is unbounded |
C. | One of the constraints is redundant |
D. | None of the above |
Answer» A. The problem is infeasible |
211. |
Constraints in LP problem are called active if they |
A. | Represent optimal solution |
B. | At optimality do not consume all the available resources |
C. | Both a & b |
D. | None of the above |
Answer» A. Represent optimal solution |
212. |
The solution space (region) of an LP problem is unbounded due to |
A. | An incorrect formulation of the LP model |
B. | Objective function is unbounded |
C. | Neither a nor b |
D. | Both a & b |
Answer» C. Neither a nor b |
213. |
While solving a LP model graphically, the area bounded by the constraints is called |
A. | Feasible region |
B. | Infeasible region |
C. | Unbounded solution |
D. | None of the above |
Answer» A. Feasible region |
214. |
Alternative solutions exist of an LP model when |
A. | One of the constraints is redundant |
B. | Objective function equation is parallel to one of the constraints |
C. | Two constraints are parallel |
D. | All of the above |
Answer» B. Objective function equation is parallel to one of the constraints |
215. |
While solving a LP problem, infeasibility may be removed by |
A. | Adding another constraint |
B. | Adding another variable |
C. | Removing a constraint |
D. | Removing a variable |
Answer» C. Removing a constraint |
216. |
If a non-redundant constraint is removed from an LP problem then |
A. | Feasible region will become larger |
B. | Feasible region will become smaller |
C. | Solution will become infeasible |
D. | None of the above |
Answer» A. Feasible region will become larger |
217. |
If one of the constraint of an equation in an LP problem has an unbounded solution, then |
A. | Solution to such LP problem must be degenerate |
B. | Feasible region should have a line segment |
C. | Alternative solutions exist |
D. | None of the above |
Answer» B. Feasible region should have a line segment |
218. |
The initial solution of a transportation problem can be obtained by applying any known method. However, the only condition is that |
A. | The solution be optimal |
B. | The rim conditions are satisfied |
C. | The solution not be degenerate |
D. | All of the above |
Answer» B. The rim conditions are satisfied |
219. |
The dummy source or destination in a transportation problem is added to |
A. | Satisfy rim conditions |
B. | Prevent solution from becoming degenerate |
C. | Ensure that total cost does not exceed a limit |
D. | None of the above |
Answer» A. Satisfy rim conditions |
220. |
The occurrence of degeneracy while solving a transportation problem means that |
A. | Total supply equals total demand |
B. | The solution so obtained is not feasible |
C. | The few allocations become negative |
D. | None of the above |
Answer» B. The solution so obtained is not feasible |
221. |
An alternative optimal solution to a minimization transportation problem exists whenever opportunity cost corresponding to unused route of transportation is: |
A. | Positive & greater than zero |
B. | Positive with at least one equal to zero |
C. | Negative with at least one equal to zero |
D. | None of the above |
Answer» B. Positive with at least one equal to zero |
222. |
One disadvantage of using North-West Corner rule to find initial solution to the transportation problem is that |
A. | It is complicated to use |
B. | It does not take into account cost of transportation |
C. | It leads to a degenerate initial solution |
D. | All of the above |
Answer» B. It does not take into account cost of transportation |
223. |
The solution to a transportation problem with ‘m’ rows (supplies) & ‘n’ columns (destination) is feasible if number of positive allocations are |
A. | m+n |
B. | m*n |
C. | m+n-1 |
D. | m+n+1 |
Answer» C. m+n-1 |
224. |
If an opportunity cost value is used for an unused cell to test optimality, it should be |
A. | Equal to zero |
B. | Most negative number |
C. | Most positive number |
D. | Any value |
Answer» B. Most negative number |
225. |
During an iteration while moving from one solution to the next, degeneracy may occur when |
A. | The closed path indicates a diagonal move |
B. | Two or more occupied cells are on the closed path but neither of them represents a corner of the path. |
C. | Two or more occupied cells on the closed path with minus sign are tied for lowest circled value |
D. | Either of the above |
Answer» C. Two or more occupied cells on the closed path with minus sign are tied for lowest circled value |
226. |
The large negative opportunity cost value in an unused cell in a transportation table is chosen to improve the current solution because |
A. | It represents per unit cost reduction |
B. | It represents per unit cost improvement |
C. | It ensure no rim requirement violation |
D. | None of the above |
Answer» A. It represents per unit cost reduction |
227. |
The smallest quantity is chosen at the corners of the closed path with negative sign to be assigned at unused cell because |
A. | It improve the total cost |
B. | It does not disturb rim conditions |
C. | It ensure feasible solution |
D. | All of the above |
Answer» C. It ensure feasible solution |
228. |
When total supply is equal to total demand in a transportation problem, the problem is said to be |
A. | Balanced |
B. | Unbalanced |
C. | Degenerate |
D. | None of the above |
Answer» C. Degenerate |
229. |
Which of the following methods is used to verify the optimality of the current solution of the transportation problem |
A. | Least cost method |
B. | Vogel’s approximation method |
C. | Modified distribution method |
D. | All of the above |
Answer» A. Least cost method |
230. |
The degeneracy in the transportation problem indicates that |
A. | Dummy allocation(s) needs to be added |
B. | The problem has no feasible solution |
C. | The multiple optimal solution exist |
D. | a & b but not c |
Answer» C. The multiple optimal solution exist |
231. |
An assignment problem is considered as a particular case of a transportation problem because |
A. | The number of rows equals columns |
B. | All xij = 0 or 1 |
C. | All rim conditions are 1 |
D. | All of the above |
Answer» D. All of the above |
232. |
An optimal assignment requires that the maximum number of lines that can be drawn through squares with zero opportunity cost be equal to the number of |
A. | Rows or columns |
B. | Rows & columns |
C. | Rows + columns – 1 |
D. | None of the above |
Answer» D. None of the above |
233. |
While solving an assignment problem, an activity is assigned to a resource through a square with zero opportunity cost because the objective is to |
A. | Minimize total cost of assignment |
B. | Reduce the cost of assignment to zero |
C. | Reduce the cost of that particular assignment to zero |
D. | All of the above |
Answer» A. Minimize total cost of assignment |
234. |
The method used for solving an assignment problem is called |
A. | Reduced matrix method |
B. | MODI method |
C. | Hungarian method |
D. | None of the above |
Answer» C. Hungarian method |
235. |
The purpose of a dummy row or column in an assignment problem is to |
A. | Obtain balance between total activities & total resources |
B. | Prevent a solution from becoming degenerate |
C. | Provide a means of representing a dummy problem |
D. | None of the above |
Answer» A. Obtain balance between total activities & total resources |
236. |
Maximization assignment problem is transformed into a minimization problem by |
A. | Adding each entry in a column from the maximization value in that column |
B. | Subtracting each entry in a column from the maximum value in that column |
C. | Subtracting each entry in the table from the maximum value in that table |
D. | Any one of the above |
Answer» C. Subtracting each entry in the table from the maximum value in that table |
237. |
If there were n workers & n jobs there would be |
A. | n! solutions |
B. | (n-1)! solutions |
C. | (n!)n solutions |
D. | n solutions |
Answer» A. n! solutions |
238. |
An assignment problem can be solved by |
A. | Simplex method |
B. | Transportation method |
C. | Both a & b |
D. | None of the above |
Answer» C. Both a & b |
239. |
For a salesman who has to visit n cities which of the following are the ways of his tour plan |
A. | n! |
B. | (n+1)! |
C. | (n-1)! |
D. | n |
Answer» C. (n-1)! |
240. |
The assignment problem |
A. | Requires that only one activity be assigned to each resource |
B. | Is a special case of transportation problem |
C. | Can be used to maximize resources |
D. | All of the above |
Answer» D. All of the above |
241. |
An assignment problem is a special case of transportation problem, where |
A. | Number of rows equals number of columns |
B. | All rim conditions are 1 |
C. | Values of each decision variable is either 0 or 1 |
D. | All of the above |
Answer» D. All of the above |
242. |
Every basic feasible solution of a general assignment problem, having a square pay-off matrix of order, n should have assignments equal to |
A. | 2n+1 |
B. | 2n-1 |
C. | m+n-1 |
D. | m+n |
Answer» B. 2n-1 |
243. |
To proceed with the MODI algorithm for solving an assignment problem, the number of dummy allocations need to be added are |
A. | n |
B. | 2n |
C. | n-1 |
D. | 2n-1 |
Answer» C. n-1 |
244. |
The Hungarian method for solving an assignment problem can also be used to solve |
A. | A transportation problem |
B. | A travelling salesman problem |
C. | A LP problem |
D. | Both a & b |
Answer» B. A travelling salesman problem |
245. |
An optimal solution of an assignment problem can be obtained only if |
A. | Each row & column has only one zero element |
B. | Each row & column has at least one zero element |
C. | The data is arrangement in a square matrix |
D. | None of the above |
Answer» D. None of the above |
246. |
Customer behavior in which the customer moves from one queue to another in a multiple channel situation is |
A. | Balking |
B. | Reneging |
C. | Jockeying |
D. | Altering |
Answer» C. Jockeying |
247. |
Which of the following characteristics apply to queuing system |
A. | Customer population |
B. | Arrival process |
C. | Both a & b |
D. | Neither a nor b |
Answer» C. Both a & b |
248. |
Which of the following is not a key operating characteristics apply to queuing system |
A. | Utilization factor |
B. | Percent idle time |
C. | Average time spent waiting in the system & queue |
D. | None of the above |
Answer» D. None of the above |
249. |
Priority queue discipline may be classified as |
A. | Finite or infinite |
B. | Limited & unlimited |
C. | Pre-emptive or non-pre-emptive |
D. | All of the above |
Answer» C. Pre-emptive or non-pre-emptive |
250. |
The calling population is assumed to be infinite when |
A. | Arrivals are independent of each other |
B. | Capacity of the system is infinite |
C. | Service rate is faster than arrival rate |
D. | All of the above |
Answer» A. Arrivals are independent of each other |
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