McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Electrical Engineering , Bachelor of Science in Computer Science FY (BSc CS) , Bachelor of Computer Applications (BCA) , Bachelor of Science in Computer Science (BSc CS) .
351. |
Fusing process is |
A. | reversible |
B. | irreversible |
C. | synchronous |
D. | asynchronous |
Answer» B. irreversible |
352. |
The cell type used inside a PROM is |
A. | link cells |
B. | metal cells |
C. | fuse cells |
D. | electric cells |
Answer» C. fuse cells |
353. |
How many types of fuse technologies are used in PROMs? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» B. 3 |
354. |
Metal links are made up of |
A. | polycrystalline |
B. | magnesium sulphide |
C. | nichrome |
D. | silicon dioxide |
Answer» C. nichrome |
355. |
EPROM uses an array of |
A. | p-channel enhancement type mosfet |
B. | n-channel enhancement type mosfet |
C. | p-channel depletion type mosfet |
D. | n-channel depletion type mosfet |
Answer» B. n-channel enhancement type mosfet |
356. |
The EPROM was invented by |
A. | wen tsing chow |
B. | dov frohman |
C. | luis o brian |
D. | j p longwell |
Answer» B. dov frohman |
357. |
Address decoding for dynamic memory chip control may also be used for |
A. | chip selection and address location |
B. | read and write control |
C. | controlling refresh circuits |
D. | memory mapping |
Answer» A. chip selection and address location |
358. |
Which of the following describes the action of storing a bit of data in a mask ROM? |
A. | a 0 is stored by connecting the gate of a mos cell to the address line |
B. | a 0 is stored in a bipolar cell by shorting the base connection to the address line |
C. | a 1 is stored by connecting the gate of a mos cell to the address line |
D. | a 1 is stored in a bipolar cell by opening the base connection to the address line |
Answer» C. a 1 is stored by connecting the gate of a mos cell to the address line |
359. |
The check sum method of testing a ROM |
A. | allows data errors to be pinpointed to a specific memory location |
B. | provides a means for locating and correcting data errors in specific memory locations |
C. | indicates if the data in more than one memory location is incorrect |
D. | simply indicates that the contents of the rom are incorrect |
Answer» D. simply indicates that the contents of the rom are incorrect |
360. |
The initial values in all the cells of an EPROM is |
A. | 0 |
B. | 1 |
C. | both 0 and 1 |
D. | alternate 0s and 1s |
Answer» B. 1 |
361. |
To store 0 in such a cell, the floating point must be |
A. | reprogrammed |
B. | restarted |
C. | charged |
D. | power off |
Answer» C. charged |
362. |
The major disadvantage of RAM is? |
A. | its access speed is too slow |
B. | its matrix size is too big |
C. | it is volatile |
D. | high power consumption |
Answer» C. it is volatile |
363. |
Which one of the following is used for the fabrication of MOS EPROM? |
A. | tms 2513 |
B. | tms 2515 |
C. | tms 2516 |
D. | tms 2518 |
Answer» C. tms 2516 |
364. |
How many addresses a MOS EPROM have? |
A. | 1024 |
B. | 512 |
C. | 2516 |
D. | 256 |
Answer» C. 2516 |
365. |
To read from the memory, the select input and the power down/program input must be |
A. | high |
B. | low |
C. | sometimes high and sometimes low |
D. | alternate high and low |
Answer» B. low |
366. |
ROMs retain data when |
A. | power is on |
B. | power is off |
C. | system is down |
D. | all of the mentioned |
Answer» D. all of the mentioned |
367. |
When a RAM module passes the checker board test it is |
A. | able to read and write only 0s |
B. | faulty |
C. | probably good |
D. | able to read and write only 1s |
Answer» C. probably good |
368. |
What is the difference between static RAM and dynamic RAM? |
A. | static ram must be refreshed, dynamic ram does not |
B. | there is no difference |
C. | dynamic ram must be refreshed, static ram does not |
D. | sram is slower than dram |
Answer» C. dynamic ram must be refreshed, static ram does not |
369. |
What is access time? |
A. | the time taken to move a stored word from one bit to other bits after applying the address bits |
B. | the time taken to write a word after applying the address bits |
C. | the time taken to read a stored word after applying the address bits |
D. | the time taken to erase a stored word after applying the address bits |
Answer» C. the time taken to read a stored word after applying the address bits |
370. |
What are the typical values of tOE? |
A. | 10 to 20 ns for bipolar |
B. | 25 to 100 ns for nmos |
C. | 12 to 50 ns for cmos |
D. | all of the mentioned |
Answer» D. all of the mentioned |
371. |
Which of the following is not a type of memory? |
A. | ram |
B. | fprom |
C. | eeprom |
D. | rom |
Answer» C. eeprom |
372. |
The chip by which both the operation of read and write is performed |
A. | ram |
B. | rom |
C. | prom |
D. | eprom |
Answer» A. ram |
373. |
RAM is also known as |
A. | rwm |
B. | mbr |
C. | mar |
D. | rom |
Answer» A. rwm |
374. |
If a RAM chip has n address input lines then it can access memory locations upto |
A. | 2(n-1) |
B. | 2(n+1) |
C. | 2n |
D. | 22n |
Answer» C. 2n |
375. |
The n-bit address is placed in the |
A. | mbr |
B. | mar |
C. | ram |
D. | rom |
Answer» B. mar |
376. |
Which of the following control signals are selected for read and write operations in a RAM? |
A. | data buffer |
B. | chip select |
C. | read and write |
D. | memory |
Answer» C. read and write |
377. |
Computers invariably use RAM for |
A. | high complexity |
B. | high resolution |
C. | high speed main memory |
D. | high flexibility |
Answer» C. high speed main memory |
378. |
How many types of RAMs are? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» A. 2 |
379. |
Static RAM employs |
A. | bjt or mosfet |
B. | fet or jfet |
C. | capacitor or bjt |
D. | bjt or mos |
Answer» D. bjt or mos |
380. |
Dynamic RAM employs |
A. | capacitor or mosfet |
B. | fet or jfet |
C. | capacitor or bjt |
D. | bjt or mos |
Answer» A. capacitor or mosfet |
381. |
Which one of the following is volatile in nature? |
A. | rom |
B. | erom |
C. | prom |
D. | ram |
Answer» D. ram |
382. |
The magnetic core memories have been replaced by semiconductor RAMs, why? |
A. | semiconductor rams are highly flexible |
B. | semiconductor rams have highest storing capacity |
C. | semiconductor rams are smaller in size |
D. | all of the mentioned |
Answer» D. all of the mentioned |
383. |
The data written in flip-flop remains stored as long as |
A. | d.c. power is supplied |
B. | d.c. power is removed |
C. | a.c. power is supplied |
D. | a.c. power is removed |
Answer» A. d.c. power is supplied |
384. |
What is memory decoding? |
A. | the process of memory ic used in a digital system is overloaded with data |
B. | the process of memory ic used in a digital system is selected for the range of address assigned |
C. | the process of memory ic used in a digital system is selected for the range of data assigned |
D. | the process of memory ic used in a digital system is overloaded with data allocated in memory cell |
Answer» B. the process of memory ic used in a digital system is selected for the range of address assigned |
385. |
The first step in the design of memory decoder is |
A. | selection of a eprom |
B. | selection of a ram |
C. | address assignment |
D. | data insertion |
Answer» C. address assignment |
386. |
How many address bits are required to select memory location in Memory decoder? |
A. | 4 kb |
B. | 8 kb |
C. | 12 kb |
D. | 16 kb |
Answer» C. 12 kb |
387. |
How memory expansion is done? |
A. | by increasing the supply voltage of the memory ics |
B. | by decreasing the supply voltage of the memory ics |
C. | by connecting memory ics together |
D. | by separating memory ics |
Answer» C. by connecting memory ics together |
388. |
IC 4116 is organised as |
A. | 512 * 4 |
B. | 16 * 1 |
C. | 32 * 4 |
D. | 64 * 2 |
Answer» C. 32 * 4 |
389. |
To construct 16K * 4-bit memory, how many 4116 ICs are required? |
A. | 1 |
B. | 2 |
C. | 3 |
D. | 4 |
Answer» D. 4 |
390. |
How many 1024 * 1 RAM chips are required to construct a 1024 * 8 memory system? |
A. | 4 |
B. | 6 |
C. | 8 |
D. | 12 |
Answer» C. 8 |
391. |
How many 16K * 4 RAMs are required to achieve a memory with a capacity of 64K and a word length of 8 bits? |
A. | 2 |
B. | 4 |
C. | 6 |
D. | 8 |
Answer» D. 8 |
392. |
The full form of PLD is |
A. | programmable load devices |
B. | programmable logic data |
C. | programmable logic devices |
D. | programmable loaded devices |
Answer» C. programmable logic devices |
393. |
PLD contains a large number of |
A. | flip-flops |
B. | gates |
C. | registers |
D. | all of the mentioned |
Answer» D. all of the mentioned |
394. |
Logic circuits can also be designed using |
A. | ram |
B. | rom |
C. | pld |
D. | pla |
Answer» C. pld |
395. |
How many types of PLD is? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» A. 2 |
396. |
PAL refers to |
A. | programmable array loaded |
B. | programmable logic array |
C. | programmable array logic |
D. | programmable and logic |
Answer» C. programmable array logic |
397. |
Outputs of the AND gate in PLD is known as |
A. | input lines |
B. | output lines |
C. | strobe lines |
D. | control lines |
Answer» B. output lines |
398. |
PLA contains |
A. | and and or arrays |
B. | nand and or arrays |
C. | not and and arrays |
D. | nor and or arrays |
Answer» A. and and or arrays |
399. |
PLA is used to implement |
A. | a complex sequential circuit |
B. | a simple sequential circuit |
C. | a complex combinational circuit |
D. | a simple combinational circuit |
Answer» C. a complex combinational circuit |
400. |
A PLA is similar to a ROM in concept except that |
A. | it hasn’t capability to read only |
B. | it hasn’t capability to read or write operation |
C. | it doesn’t provide full decoding to the variables |
D. | it hasn’t capability to write only |
Answer» C. it doesn’t provide full decoding to the variables |
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