McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: All India Pre Medical Test (AIPMT) .
Chapters
| 51. |
When there is no Possibility of independent assortment of genes during gametogenesis then What Will be the real ratio of F2 in dihybrd cross? |
| A. | 9 : 3 : 3 : 1 |
| B. | 11 : 1 : 1 : 3 |
| C. | 12 : 1 : 1 : 2 |
| D. | 9 : 3 : 2 : 2 |
| E. | cessive |
| Answer» B. 11 : 1 : 1 : 3 | |
| 52. |
What is incorrect statement Gynandromorphs ? |
| A. | Individuals who show male characters and female characters |
| B. | Individuals who show only female characters |
| C. | It happens due to less of X- chromosomes |
| D. | It happens due to binacleated eggs |
| E. | cessive |
| Answer» B. Individuals who show only female characters | |
| 53. |
What is Barr body ? |
| A. | One more than the number of X - chromosomes |
| B. | One more than the number of Y-chromosomes |
| C. | One less than the number of X - chromosomes |
| D. | Two less than the number of X - chromosomes |
| E. | cessive |
| Answer» C. One less than the number of X - chromosomes | |
| 54. |
What is called Free martin ? |
| A. | Sterile male born along with a fertile female |
| B. | Sterile intersex born along with a fertile female |
| C. | Sterile super male born along with a intersex |
| D. | Sterile female born along with a fertile male |
| E. | cessive |
| Answer» D. Sterile female born along with a fertile male | |
| 55. |
Out of the following , Find out the reason for occurrence of free martin in cattles ? |
| A. | Both the twins are connected by a common umbilical cord |
| B. | Gonad of the male develop earlier then those of the female |
| C. | Male hormones reach the female embryo and influence the development of male sex in the female embryo |
| D. | All of the above |
| E. | cessive |
| Answer» D. All of the above | |
| 56. |
In this group of plants male is heterogametic and female is homogametic type |
| A. | Gymnosperms |
| B. | Bryophytes |
| C. | pteridophytes |
| D. | angiosperms |
| E. | cessive |
| Answer» D. angiosperms | |
| 57. |
Name the Plant possessing two X chromosomes |
| A. | Humulus japanic |
| B. | Dioscoria sinulate |
| C. | Flagellaria |
| D. | Both (A) & (B) |
| E. | cessive |
| Answer» D. Both (A) & (B) | |
| 58. |
State the mutant gene Which converts the male flowers into female flowers In Maize plant |
| A. | TA TA |
| B. | ta ta |
| C. | TA Ta |
| D. | Both (A) &(C) |
| E. | cessive |
| Answer» B. ta ta | |
| 59. |
By which gene sex is determind in Spinach ? |
| A. | Single gene "m" located in the X- chromosome |
| B. | Single gene "m" located in the Y- chromosome |
| C. | Single gene "t" located in the X- chromosome |
| D. | Single gene "t" located in the Y- chromosome |
| E. | cessive |
| Answer» A. Single gene "m" located in the X- chromosome | |
| 60. |
Which factor in nature causes discontinuous Variation in a population ? |
| A. | Recombination |
| B. | Shufflng of parental genes |
| C. | Mutation |
| D. | Geneflow |
| E. | cessive |
| Answer» C. Mutation | |
| 61. |
This is reversal of mutation |
| A. | Spontneous mutation |
| B. | Zygotic mutation |
| C. | Back mutation |
| D. | Recessive mutation |
| E. | cessive |
| Answer» C. Back mutation | |
| 62. |
Which condition among the following is lethal ? |
| A. | (2n-2) |
| B. | (2n +2) |
| C. | (2n +1) |
| D. | (2n- 1) |
| E. | cessive |
| Answer» A. (2n-2) | |
| 63. |
State the cause of Philadelphia syndrome |
| A. | Deletion from the long arm of chromosome number 20 |
| B. | Duplication in long arm of chromosome number 20 |
| C. | Deletion from the long arm of chromosome number 22 |
| D. | Deletion from the short arm of chromosome number 22 |
| E. | cessive |
| Answer» C. Deletion from the long arm of chromosome number 22 | |
| 64. |
which statement is incorrect regarding gene mutation |
| A. | Mutations may be gradual or they may not be induced. |
| B. | Mutation is an evolutionary agent |
| C. | Any gene can undergo mutation |
| D. | Mutated gene is harmful to the individual |
| E. | cessive |
| Answer» A. Mutations may be gradual or they may not be induced. | |
| 65. |
What happens to excessive phenylalanine accumulation in the blood of phenylketonuria patient ? |
| A. | Get deposited on synovial membrane |
| B. | excreted in urine |
| C. | Get deposited in storage organs |
| D. | All of the above |
| E. | cessive |
| Answer» B. excreted in urine | |
| 66. |
Name the enzyme needed for the following biochemical reaction Tyrosine enzyme Melanin |
| A. | Melanase |
| B. | tyrosinase |
| C. | Tyrosine aminase |
| D. | transaminase |
| E. | cessive |
| Answer» C. Tyrosine aminase | |
| 67. |
Which is very common method to study Human Karyotype ? |
| A. | Blood culture method |
| B. | Tissue culture method |
| C. | Pedigree method |
| D. | Statistical method |
| E. | cessive |
| Answer» A. Blood culture method | |
| 68. |
Name the disorder caused by trisomy of sex chromosomes. |
| A. | Down’s syndrome |
| B. | Kline felter’s syndrome |
| C. | Turner’s syndrome |
| D. | Edward’s syndrome |
| E. | cessive |
| Answer» B. Kline felter’s syndrome | |
| 69. |
What will be expected blood groups in the off spring when there is a cross between AB blood group mother and heterozygous B blood group father ? |
| A. | 25 % AB group 25 % A group 50 % B group |
| B. | 50 % AB group 25 % A group 25 % B group |
| C. | 25% AB group 50% O group 25 % A group |
| D. | 25 % O group 50 % B group 25 % A group |
| E. | cessive |
| Answer» A. 25 % AB group 25 % A group 50 % B group | |
| 70. |
Which law of Mendel can be explained on chromosomal basis of inheritance ? |
| A. | Law of dominance |
| B. | Law of segregation |
| C. | Law of independent assortment |
| D. | All the above |
| E. | cessive |
| Answer» C. Law of independent assortment | |
| 71. |
Out of the marked portions X, Y and Z, in which region the male worm develop ? |
| A. | X |
| B. | Y |
| C. | Z |
| D. | All the three regions |
| E. | cessive |
| Answer» C. Z | |
| 72. |
Which kind of structural abnormality is seen in the above chromosome? |
| A. | Terminal deletion |
| B. | Duplication (Tandem) |
| C. | Duplication (Reverse) |
| D. | Inversion |
| E. | cessive |
| Answer» B. Duplication (Tandem) | |
| 73. |
Name the abnormality seen in chromosome number - 2 |
| A. | Interstitial Deletion |
| B. | Terminal Deletion |
| C. | Tandem Duplication |
| D. | Reverse Duplicaton |
| E. | cessive |
| Answer» A. Interstitial Deletion | |
| 74. |
What does the following pedigree chart represent ? |
| A. | Pedigree of sex - influenced disorder |
| B. | Pedigree of sex - linked disorder |
| C. | Pedigree of polydactylous in man |
| D. | Pedigree of gene mutation |
| E. | cessive |
| Answer» C. Pedigree of polydactylous in man | |
| 75. |
What kind of chromosomal aberrations is seen in the given diagram? |
| A. | Deletion |
| B. | Duplication |
| C. | inversion |
| D. | Translocation |
| E. | cessive |
| Answer» C. inversion | |
| 76. |
What kind of sex determination is seen in the given chart? |
| A. | Sex determination in drosophila |
| B. | Sex determination in honey bee |
| C. | Sex determination in moth |
| D. | Sex determination in butterfly |
| E. | cessive |
| Answer» B. Sex determination in honey bee | |
| 77. |
What do A, B, C represent in the given diagram? |
| A. | Centromere, chromatids chiasma |
| B. | Chromatid, chiasma, centromere |
| C. | Centromere, chiasma, chromatid |
| D. | Chromatid, chiasma centromere |
| E. | cessive |
| Answer» A. Centromere, chromatids chiasma | |
| 78. |
What does the diagram represent ? |
| A. | synapsis Zygotene |
| B. | crossing over, Diplotene |
| C. | Tetrad, Pachytene |
| D. | Terminalization, Diakinesis |
| E. | cessive |
| Answer» B. crossing over, Diplotene | |
| 79. |
Whose karyotype is represented below ? |
| A. | Female Drosophila |
| B. | Male Drosophila |
| C. | Intersex Fly |
| D. | Super female fly |
| E. | cessive |
| Answer» B. Male Drosophila | |
| 80. |
What does the above cross represent ? |
| A. | Incomplete linkage |
| B. | Complete linkage |
| C. | Crossing over |
| D. | Evolution |
| E. | cessive |
| Answer» B. Complete linkage | |
| 81. |
The genes Controlling the seven characters of a pea plant studied by Mendel are now known to be located on how many different chromosomes? AIPMT - 2003 |
| A. | Seven |
| B. | Six |
| C. | Five |
| D. | Four |
| E. | cessive |
| Answer» D. Four | |
| 82. |
Which one of the following traits of garden pea studied by Mendel was a recessive feature? AIPMT - 2003 |
| A. | Axial flower position |
| B. | Green Seed colour |
| C. | Green pod colour |
| D. | Round Seed shape |
| E. | cessive |
| Answer» B. Green Seed colour | |
| 83. |
Down's Syndrome is caused by an extra copy of chromosome number 21. What percent age of off spring produced by an affected mother and a normal father? AIPMT - 2003 |
| A. | 100% |
| B. | 75% |
| C. | 50% |
| D. | 25% |
| E. | cessive |
| Answer» D. 25% | |
| 84. |
Lack of independent assortment of two genes A and B in fruitfly the Drosophilia is due to |
| A. | Repulsion |
| B. | Recombination |
| C. | Linkage |
| D. | Crossing over |
| E. | cessive |
| Answer» C. Linkage | |
| 85. |
. A male human is heterozygous for autosomal genes A and B and is also hemizygous for haemophilic gene h. What proportion of his sperms will be abh? AIPMT - 2004 |
| A. | 1/8 |
| B. | 1/32 |
| C. | 1/16 |
| D. | 1/4 |
| E. | cessive |
| Answer» A. 1/8 | |
| 86. |
. In a plant, red fruit (R) is dominant over yellow fruit (r) and tallness (T) is dominant over shortness (t). If a plant with RRTt genotype is crossed with a plant that is rrtt. AIPMT - 2004 |
| A. | 25% will be tall with red fruit |
| B. | 50% will be tall with red fruit |
| C. | 75% will be tall with red fruit |
| D. | All the offspring will be tall with red fruit. |
| E. | cessive |
| Answer» B. 50% will be tall with red fruit | |
| 87. |
A normal woman, whose father was colour blind is married with normal man. The sons would be AIPMT - 2004 |
| A. | 75% Colour blind |
| B. | 50% colour blind |
| C. | all normal |
| D. | all colourblind |
| E. | cessive |
| Answer» A. 75% Colour blind | |
| 88. |
.The recessive genes located on X - chromosome of humans are alwaysAIPMT-2004 |
| A. | Lethal |
| B. | Sub - Lethal |
| C. | expressed in males |
| D. | expressed in females |
| E. | cessive |
| Answer» C. expressed in males | |
| 89. |
. Inorder to find out the different types of gametes produced by a pea plant having the genotype AaBb it should be crossed to a plant with the genotype AIPMT - 2004 |
| A. | AABB |
| B. | AaBb |
| C. | aabb |
| D. | aaBB |
| E. | cessive |
| Answer» C. aabb | |
| 90. |
. A woman with normal vision, but whose father was colourblind, marries a colourblind man. AIPMT - 2004 Suppose that the fourth child of this couple was a boy. This boy |
| A. | May be colourblind or may be of normal vision |
| B. | Must be colourblind |
| C. | Must have normal colour vision |
| D. | Will be partially colourblind since he is heterozygous for the colourblind mutant allele. |
| E. | cessive |
| Answer» A. May be colourblind or may be of normal vision | |
| 91. |
.Which of the following is not a hereditary disease? AIPMT - 2004 |
| A. | Cystic Fibrosis |
| B. | Thalassaemia |
| C. | Haemophilia |
| D. | Cretinism |
| E. | cessive |
| Answer» D. Cretinism | |
| 92. |
.Haemophilia is more commonly seen in human males than in human females because |
| A. | a greater proportion of girls die in infancy AIPMT - 2004 |
| B. | this disease is due to a Y- linked recessive mutation |
| C. | this disease is due to an X - linked recessive mutation |
| D. | this disease is due to an X- linked dominant mutation |
| E. | cessive |
| Answer» C. this disease is due to an X - linked recessive mutation | |
| 93. |
.A woman with 47 chromosomes due to 3 copies of chromosome 21 is characterized by AIPMT - 2005 |
| A. | Super Femaleness |
| B. | Triploidy |
| C. | Turner's Syndrome |
| D. | Down's Syndrome |
| E. | cessive |
| Answer» D. Down's Syndrome | |
| 94. |
. A man and a woman, who do not show any apparent signs of a certain inherited disease, have Seven Children (2 daughters and 5 sons). Three of the Sons suffer from the given disease but none of the daughters affected. Which of the following mode of inheritance do you suggest for this disease? AIPMT - 2005 |
| A. | Sex - linked dominant |
| B. | Sex - linked recessive |
| C. | Sex - limited recessive |
| D. | Autosomal dominant |
| E. | cessive |
| Answer» B. Sex - linked recessive | |
| 95. |
.Which one of the following is an example of polygenic inheritance ? AIPMT - 2006 |
| A. | Skin colour in humans |
| B. | Flower colour in Miralibilis jalapa |
| C. | Production of male honey bee |
| D. | Pod shape in garden pea |
| E. | cessive |
| Answer» A. Skin colour in humans | |
| 96. |
.Phenotype of an organism is the result of AIPMT - 2006 |
| A. | genotype and environmental interactions |
| B. | mutations and linkages |
| C. | Cytoplasmic effects and nutrition |
| D. | environmental changes and sexual dimorphism |
| E. | cessive |
| Answer» A. genotype and environmental interactions | |
| 97. |
.How many different gametes will be produced by a plant having the genotype AABbCC? AIPMT - 2006 |
| A. | Two |
| B. | Three |
| C. | Four |
| D. | Nine |
| E. | cessive |
| Answer» A. Two | |
| 98. |
.In Mendel's experiments with garden pea, round seed shape (RR) was dominant over wrinkledSeeds (rr), Yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the expected Phenotypes in the F2 generation of the cross RRYY x rryy? |
| A. | Round Seeds with yellow cotyledons, and wrinkled seeds with yellow cotyle dons |
| B. | Only round seeds with green cotyledons |
| C. | Only wrinkled seeds with yellow cotyledons |
| D. | Only wrinkled seeds with green cotyledons |
| E. | cessive |
| Answer» A. Round Seeds with yellow cotyledons, and wrinkled seeds with yellow cotyle dons | |
| 99. |
Test cross involves AIPMT - 2006 |
| A. | Crossing between two genotypes with dominant trait |
| B. | Crossing between two genotypes with recessive trait |
| C. | Crossing between two F1 hybrids |
| D. | Crossing the F1 hybrid with a double recessive genotype |
| E. | cessive |
| Answer» D. Crossing the F1 hybrid with a double recessive genotype | |
| 100. |
. If a colourblind woman marries a normal visioned man, their sons will be AIPMT - 2006 |
| A. | all colourblind |
| B. | all normal visioned |
| C. | one - half colourblind and one - half normal |
| D. | three - fourths colourblind and one - fourth normal |
| E. | cessive |
| Answer» A. all colourblind | |
Done Studing? Take A Test.
Great job completing your study session! Now it's time to put your knowledge to the test. Challenge yourself, see how much you've learned, and identify areas for improvement. Don’t worry, this is all part of the journey to mastery. Ready for the next step? Take a quiz to solidify what you've just studied.