McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: All India Pre Medical Test (AIPMT) .
Chapters
| 51. |
How many nucleotides make one okazaki segment in eukaryotes ? |
| A. | 1000-1500 |
| B. | 100-200 |
| C. | 5000 |
| D. | Not fixed |
| Answer» A. 1000-1500 | |
| 52. |
Which of the following enzymes help in the process of formation of phosphodiester bond during reverse transcription ? |
| A. | DNA - dependant RNA polymerase |
| B. | DNA dependant DNA polymerase |
| C. | RNA - dependant RNA polymerase |
| D. | RNA - dependant DNA polymerase |
| Answer» D. RNA - dependant DNA polymerase | |
| 53. |
The two strands of a DNA molecule are separted and one of them is analysed for its A + T / G + C ratio, This is found to be 0.2 What is the A + T / G + C ratio of the other strand |
| A. | 0.02 |
| B. | 0.08 |
| C. | 0.8 |
| D. | 0.2 |
| Answer» D. 0.2 | |
| 54. |
DNA replication in lagging strand of most of the eukaryotic organis ms is |
| A. | conservative and continuous |
| B. | semi conservative but discontinuous |
| C. | conservative and semi - discontinuous |
| D. | semi conservative but continuous |
| Answer» B. semi conservative but discontinuous | |
| 55. |
How many bases consist in an average gene ? |
| A. | 3, 00, 000 |
| B. | 3000 |
| C. | 4, 00, 000 |
| D. | 4000 |
| Answer» B. 3000 | |
| 56. |
Match the following using salient features of Human genome project A B
|
| A. | (P - iv) (Q - iii) ( R - ii) ( S - i) |
| B. | ( P - iv) (Q - ii) (R - iii) (S - i) |
| C. | (P - iv) (Q - i) (R - ii) (S - iii) |
| D. | (P - i) (Q - iii) (R - iv) (S - ii) |
| Answer» A. (P - iv) (Q - iii) ( R - ii) ( S - i) | |
| 57. |
State the use of moleculer medicine ? |
| A. | Improves diagnosis of diseases |
| B. | Used as gene theraphy |
| C. | Used to understand several diseass like Alzheimer’s Parkinsons diseases etc., |
| D. | All the above |
| Answer» D. All the above | |
| 58. |
Among the following which is used for separation of DNA fragments ? |
| A. | centifugation |
| B. | Cell fractionation |
| C. | Cell homogenation |
| D. | Electrophoresis |
| Answer» D. Electrophoresis | |
| 59. |
In Which of the following DNA not directly involved ? |
| A. | Repication |
| B. | Transcription |
| C. | Translation |
| D. | Transformation |
| Answer» C. Translation | |
| 60. |
Transcription begins when one of the following enzymes binds to promotor site. |
| A. | DNA polymerase |
| B. | RNA polymerase |
| C. | helicase |
| D. | Gyrase |
| Answer» B. RNA polymerase | |
| 61. |
What dose A & B represent ? |
| A. | Grycase , Helicase |
| B. | Double Stranded Protein, Helicase |
| C. | Helicase, Single strand binding protein |
| D. | Topoisomerase Helicase |
| Answer» C. Helicase, Single strand binding protein | |
| 62. |
State the process and mention the labelled protion. |
| A. | Process of Translation - X-RNA Polymerase- Y-DNA Template- Z-m RNA Transcript |
| B. | process of Transcription - X-RNA Polymerase- Y-DNA Template- Z- RNA Transcript |
| C. | process of Translocation - X-DNA polymerase- Y- Template- Z- Transcript |
| D. | Process of Transformation - X - DNA polymerase- Y - RNA template- Z - RNA transcript |
| Answer» B. process of Transcription - X-RNA Polymerase- Y-DNA Template- Z- RNA Transcript | |
| 63. |
What do P, Q, R and S regions of t RNA ? |
| A. | P - Anticodon loop |
| B. | P. D LoopQ - Variable loop Q - T ψ c loopR - T ψ c loop R - Variable loopS - D Loop S - Anticodon loop |
| C. | P - T ψ c loop |
| D. | P - Anticodon LoopQ - D loop Q - T ψ c loop R - Anticodon loop R - D loop S - Variable loop S - Variable loop |
| Answer» A. P - Anticodon loop | |
| 64. |
Which state is represent by the above model |
| A. | Repressed state of lac operon |
| B. | Inactive state of Lac operon |
| C. | Active state of Lac operon |
| D. | Induced state of Lac operon |
| Answer» A. Repressed state of lac operon | |
| 65. |
What does X replesent in the above diagram |
| A. | Released polypeptide chain |
| B. | Released 3D protein molecule |
| C. | Released secondary protein |
| D. | Released tertiary protein |
| Answer» A. Released polypeptide chain | |
| 66. |
What does ‘X’ represent |
| A. | gene |
| B. | segment of DNA |
| C. | seqment of DNA coding for specific protein |
| D. | Both A & C |
| Answer» D. Both A & C | |
| 67. |
Write the codon for the anticodon on the t - RNA |
| A. | AGU |
| B. | UGU |
| C. | UGA |
| D. | ACU |
| Answer» A. AGU | |
| 68. |
In the genetic code dictionary how many codons are used to code for all the 20 essential amino-acids? (AIPMT - 2003) |
| A. | 20 |
| B. | 64 |
| C. | 61 |
| D. | 60 |
| Answer» B. 64 | |
| 69. |
What would happen if in a gene encoding polypeptide of 50 aminoacids 25th codon (UAU) is mutated to UAA ? (AIPMT - 2003) |
| A. | A Polypeptide of 24 aminoacids will be formed |
| B. | Two polypeptides of 24 and 25 aminoacids will be formed |
| C. | A polypeptide of 49 aminoacids will be formed |
| D. | A polypeptide of 25 aminoacids will be formed |
| Answer» A. A Polypeptide of 24 aminoacids will be formed | |
| 70. |
Which one of the following triplet codes, is correctly matched with its specificity for an aminoacid in protein synthesis or as ‘start’ or ‘stop’ codon ? |
| A. | UCG - start |
| B. | UUU - stop |
| C. | UGU - Leucine |
| D. | UAC - Tyrosine |
| Answer» D. UAC - Tyrosine | |
| 71. |
What does “Lac” refer to in what we call the lac operon ? (AIPMT - 2003) |
| A. | Lactose |
| B. | Lactase |
| C. | Lac insect |
| D. | The number 1,00,000 |
| Answer» A. Lactose | |
| 72. |
The following ratio is generally constant for a given species (AIPMT - 2004) |
| A. | A + G / C + T |
| B. | T + C / G + A |
| C. | G + C / A + T |
| D. | A + C / T + G |
| Answer» C. G + C / A + T | |
| 73. |
During transcription if the nucleotide sequence of the DNA strand that is being coded is ATACG then the nucleotide sequence in the m RNA would be (AIPMT - 2004) |
| A. | TATGC |
| B. | T C T G G |
| C. | U A U G C |
| D. | U A T G C |
| Answer» C. U A U G C | |
| 74. |
Which one of the following makes use of RNA template to synthesize DNA (AIPMT - 2005) |
| A. | DNA polymerase |
| B. | RNA polymerase |
| C. | Reverse transcriptase |
| D. | DNA dependant RNA polymerase |
| Answer» C. Reverse transcriptase | |
| 75. |
Protein synthesis is an animal cell occurs (AIPMT - 2005) |
| A. | only on the ribosomes present in cytosol |
| B. | only on ribosomes attached to the nuclear envelope and endoplasmic reticulum |
| C. | On ribosomes present in the nucleolus as well as in cytoplasm |
| D. | on ribosomes present in cytoplasm as well as in mitochondria |
| Answer» D. on ribosomes present in cytoplasm as well as in mitochondria | |
| 76. |
E coli cells with a mutant z gene of the lac operon cannot grow in medium containing only lactose as the source of energy because (AIPMT - 2005) |
| A. | the lac operon is constitutively active in these cells |
| B. | they cannot synthesize functional beta galactosidase |
| C. | in the presence of glucose E Coli cell do not utilize lactose |
| D. | they cannot transport lactose from the medium into the cell |
| Answer» B. they cannot synthesize functional beta galactosidase | |
| 77. |
Aminoacid Sequence in protein synthesis is decided by the sequence of (AIPMT - 2006) |
| A. | r RNA |
| B. | t- RNA |
| C. | m RNA |
| D. | c DNA |
| Answer» C. m RNA | |
| 78. |
Antiparallel strands of a DNA molecule means that (AIPMT - 2006) |
| A. | One strand turns clockwise |
| B. | One strand turns anticlockwise |
| C. | The phosphate groups of two DNA strands , at their ends share the same position |
| D. | The phosphate groups at the start of two DNA strands are is opposite position (Pole). |
| Answer» D. The phosphate groups at the start of two DNA strands are is opposite position (Pole). | |
| 79. |
Polysome is formed by (AIPMT - 2008) |
| A. | a ribosome with several subunits |
| B. | ribosomes attached to each other in a linear arrangement |
| C. | several ribosomes attached to a single m RNA |
| D. | many ribosomes attached to a strand of endoplasmic reticulum |
| Answer» C. several ribosomes attached to a single m RNA | |
| 80. |
Whose experiments cracked the DNA and discovered unequivocally that a genetic code is a “triplet” (AIPMT - 2009) |
| A. | Hershey and chase |
| B. | Morgan and sturtevant |
| C. | Beadle and Tatum |
| D. | Nirenberg and Mathai |
| Answer» D. Nirenberg and Mathai | |
| 81. |
Select the two correct statement out of the four statement given below about “ Lac opern”(AIPMT-2010)
|
| A. | ii and iii |
| B. | i and iii |
| C. | ii and iv |
| D. | i and ii |
| Answer» C. ii and iv | |
| 82. |
Which one of the following does not follow the central dogma of molecular biology ? (AIPMT - 2010) |
| A. | Pea |
| B. | Mucor |
| C. | Chlamydomonas |
| D. | HIV |
| Answer» D. HIV | |
| 83. |
The lac opern consists of (AIPMT - 2010) |
| A. | four regulatory genes only |
| B. | One regulatory gene and three structural genes |
| C. | Two regulatory genes and three structural genes |
| D. | three regulatory genes and three structural genes |
| Answer» C. Two regulatory genes and three structural genes | |
| 84. |
The 31 - 51Phosphodiester linkages inside a potynucleotide chain serve to join AIPMT - 2010) |
| A. | One DNA strand with the other DNA strand |
| B. | One nucleoside with another nucleoside |
| C. | One nucleotide with another nucleotide |
| D. | One nitrogen base with pentose sugar |
| Answer» C. One nucleotide with another nucleotide | |
| 85. |
Ribosomal RNA is actively synthesized by |
| A. | Lysosomes |
| B. | nucleolus |
| C. | nucleoplasm |
| D. | ribosomes |
| Answer» B. nucleolus | |
| 86. |
If one strand of DNA has the nitrogenous base sequence as ATCTG, What would be the complementary RNA strand Sequence (AIPMT - 2012) |
| A. | TTAGU |
| B. | UAGAC |
| C. | AACTG |
| D. | ATCGU |
| Answer» B. UAGAC | |
| 87. |
Semiconservative DNA replication using 15 N was demonstrated by (AIIMS -1994) |
| A. | Meselson |
| B. | Taylor |
| C. | Meselson and stahl |
| D. | Hershey and chase |
| Answer» C. Meselson and stahl | |
| 88. |
In operan concept, the operator gene combines with (AIIMS -1986) |
| A. | Regulator protein to switch off structural gene transcription |
| B. | Regulator protein to switch on structural gene transcription |
| C. | Inducer to switch off structural gene transcription |
| D. | Regulator gene to switch off structural gene transcription |
| Answer» A. Regulator protein to switch off structural gene transcription | |
| 89. |
Termination of polypeptide chain is brought about by |
| A. | UUG , UAG and UCG |
| B. | UAA , UAG and UGA |
| C. | UUG , UGC and UCA |
| D. | UCG , GCG and ACC |
| Answer» B. UAA , UAG and UGA | |
| 90. |
RNA that picks up specific aminoacid from amino acid pool of cytoplasm to carry it to ribosome during protein synthesis is |
| A. | t RNA |
| B. | m RNA |
| C. | r RNA |
| D. | g RNA |
| Answer» A. t RNA | |
| 91. |
Correct sequenceof code transfer during polypeptide formation is (AIIMS -1999) |
| A. | DNA , mRNA , t RNA and amino acids |
| B. | DNA , t RNA , r RNA and m RNA |
| C. | m RNA , t RNA , DNA and amino acids |
| D. | r RNA , DNA ,m RNA and t RNA |
| Answer» A. DNA , mRNA , t RNA and amino acids | |
| 92. |
Best method to determine paternity is |
| A. | Protein analysis |
| B. | chromosome counting |
| C. | gene counting |
| D. | DNA finger printing |
| Answer» D. DNA finger printing | |
| 93. |
DNA is copied from m-RNA molecule with help of |
| A. | Restriction enzyme |
| B. | Reverse transcriptase |
| C. | DNA polymerase |
| D. | Adenosine deaminase |
| Answer» B. Reverse transcriptase | |
| 94. |
Nucleotide arrangement in DNA can be seen by |
| A. | X - ray crystallography |
| B. | Electron microscope |
| C. | Ultra centrifuge |
| D. | Light microscope |
| Answer» A. X - ray crystallography | |
| 95. |
Pneumococcus experiment proved that (AFMC - 1993) |
| A. | Bacteria do not reproduce asexuallly |
| B. | Bacteria undergo binary fission |
| C. | DNA is genetic material |
| D. | RNA may sometimes control a production of DNA and protein |
| Answer» C. DNA is genetic material | |
| 96. |
A DNA nucletotide chain has A G C T T C G A sequence The nucleotide sequence of other chain would be |
| A. | T C G A A G C T |
| B. | G C T A A G C T (AFMC - 1993) |
| C. | T A G C A T A T |
| D. | G A T C C T A G |
| Answer» A. T C G A A G C T | |
| 97. |
A functional unit in synthesis of protein is (MPPMT - 1994) |
| A. | Lysosome |
| B. | Peroxisome |
| C. | Polysome |
| D. | Dictyosome |
| Answer» C. Polysome | |
| 98. |
VNTR is employed for (AMU - 2002) |
| A. | Protoplasmic culture |
| B. | DNA finger printing |
| C. | Regulation of plant growth hormones |
| D. | Enhancing photosynthesis in desert plant |
| Answer» B. DNA finger printing | |
| 99. |
Out of 64 codons 61 code for 20 types of aminoacids It is due to (CBSE - 2002) |
| A. | Overlapping genes |
| B. | Degeneracy of genetic code |
| C. | Wobbling of codons |
| D. | Universality of codons |
| Answer» B. Degeneracy of genetic code | |
| 100. |
Okazaki fragments are joined by enzyme (Kerala 2005) |
| A. | DNA helix |
| B. | DNA ligase |
| C. | DNA polymerase II |
| D. | RNA polymerase II |
| Answer» B. DNA ligase | |
Done Studing? Take A Test.
Great job completing your study session! Now it's time to put your knowledge to the test. Challenge yourself, see how much you've learned, and identify areas for improvement. Don’t worry, this is all part of the journey to mastery. Ready for the next step? Take a quiz to solidify what you've just studied.